AQA GCSE Chemistry Chemistry Paper 2 (Foundation), November 2020: Question 3
15 marks · Low Demand difficulty · Short Answer
Investigate the rate of reaction between hydrochloric acid and different sized calcium carbonate lumps, including plotting data, calculating mean rate, identifying errors, and determining surface area.
Practise this questionQuestion
Question text
03 This question is about the rate of the reaction between hydrochloric acid and
calcium carbonate.
A student investigated the effect of changing the size of calcium carbonate lumps on
the rate of this reaction.
This is the method used.
1. Pour hydrochloric acid into a conical flask up to the 50 cm3 line.
2. Add 10.0 g of small calcium carbonate lumps to the conical flask.
3. Attach a gas syringe to the conical flask.
4. Measure the volume of gas produced every 20 seconds for 100 seconds.
5. Repeat steps 1 to 4 using 10.0 g of large calcium carbonate lumps.
03.1 The student used the 50 cm3 line on the conical flask to measure the volume of
hydrochloric acid.
Suggest a piece of equipment the student could use to make
the measurement of volume more accurate.
[1 mark]
03.2 Carbon dioxide gas is produced in the reaction between hydrochloric acid and
calcium carbonate.
Which test is used to identify carbon dioxide gas?
[1 mark]
Tick ( ) one box.
A burning splint pops
A glowing splint relights
Damp litmus paper is bleached
Limewater turns milky 12
Table 2 shows the student’s results for large calcium carbonate lumps.
Table 2
*11* Time in seconds Volume of gas in cm3
20 16
40 30
60 40
80 46
100 48
Figure 4 shows the student’s results for small calcium carbonate lumps.
Figure 4
03.3 Complete Figure 4.
You should:
• plot the data for large calcium carbonate lumps from Table 2 on Figure 4
• draw a line of best fit for large calcium carbonate lumps.
[3 marks]
03.4 Determine the mean rate of reaction using small calcium carbonate lumps
between 0 seconds and 60 seconds.
Use the equation:
volume of gas produced
mean rate of reaction =
time taken
Use Figure 4.
[3 marks]
Mean rate of reaction = cm3/s
03.5 Describe what happens to the volume of gas collected using
small calcium carbonate lumps:
• between 0 and 20 seconds
• between 80 and 100 seconds.
Use Figure 4.
[2 marks]
Between 0 and 20 seconds
Between 80 and 100 seconds
03.6 The balance used to weigh 10.0 g of calcium carbonate lumps caused an error.
The balance always read 0.2 g before being used.
What type of error was caused by the balance?
[1 mark]
Tick ( ) one box.
Human error
Random error
Systematic error
Figure 5 shows the dimensions of two cubes of calcium carbonate.
Figure 5
03.7 A cube of calcium carbonate has six faces.
Calculate the total surface area of the large cube of calcium carbonate.
Use Figure 5.
[3 marks]
Total surface area = mm2
03.8 The large cube of calcium carbonate was divided into eight smaller cubes.
The eight smaller cubes have a greater total surface area than the one large cube.
Compare the rate of reaction when using the eight smaller cubes with the rate of
reaction when using the large cube.
Complete the sentence.
Choose the answer from the box.
[1 mark]
faster slower the same
The rate of reaction of the eight smaller cubes is .
Mark scheme
Show the mark scheme
Question 3
AO /
Question Answers Extra information Mark
Spec. Ref.
03.1 measuring cylinder allow pipette / burette 1 AO3
4.6.1.1
03.2 limewater turns milky 1 AO1
4.8.2.3
03.3 all six points plotted correctly allow a tolerance of ± ½ a small 2 AO2
square 4.6.1.1
allow 1 mark for four or five
points plotted correctly
line of best fit 1
03.4 (volume =) 48 (cm3) 1 AO2
4.6.1.1
(rate=) allow correct use of an 1
60 incorrectly determined value for
volume
= 0.8 (cm3/s)
03.5 (between 0 and 20 seconds) 1 AO2
(volume of gas) increases 4.6.1.1
(between 80 and 100 seconds)
no change (in volume of gas) allow reaction stops 1
Question 3 (continued)
AO /
Spec. Ref.
03.6 systematic error 1 AO3
4.6.1.1
03.7 (area of one face = 2 x 2 =) 4 1 AO2
(mm2) 4.6.1.2
(total surface area =) 4 x 6 allow correct use of an 1
incorrectly calculated area of
one face
= 24 (mm2) 1
03.8 faster 1 AO1
4.6.1.3
Total 15
How to answer it
Rates of Reaction: Calcium Carbonate & Acid
This 15-mark question assesses fundamental practical skills and core concepts from AQA Topic 6 (The Rate and Extent of Chemical Change) and Topic 8 (Chemical Analysis):
- Selecting suitable apparatus to measure volume accurately.
- Standard gas identification tests (carbon dioxide).
- Graph plotting, line of best fit, and interpreting rate curves.
- Calculating the mean rate of reaction from experimental data.
- Identifying experimental errors (zero error / systematic error).
- Mathematical determination of surface area and explaining collision theory effects.
Question 03.1
Apparatus for measuring liquid volume (1 Mark)
✅ Correct Answer
Any one from:
- Measuring cylinder
- Burette
- Pipette (or volumetric pipette)
🧠 Exam Technique
Conical flasks and beakers only have approximate graduation lines. To improve precision or accuracy in any volumetric practical, always suggest a measuring cylinder, burette, or pipette.
❌ Common Errors
Do not write "beaker" or "flask" — these are not calibrated measuring instruments and will receive 0 marks.
Question 03.2
Gas identification test for CO₂ (1 Mark)
✅ Correct Answer
☑ Limewater turns milky (cloudy)
💡 Key Knowledge (Gas Tests Recall)
- Carbon dioxide: Limewater turns milky/cloudy.
- Hydrogen: Burning splint pops with a squeaky sound.
- Oxygen: Glowing splint relights.
- Chlorine: Damp litmus paper bleaches white.
🧠 Chemical Detail
Limewater is an aqueous solution of calcium hydroxide, Ca(OH)₂. It turns cloudy because insoluble calcium carbonate, CaCO₃, forms:
Ca(OH)₂(aq) + CO₂(g) → CaCO₃(s) + H₂O(l)
Question 03.3
Plotting data & drawing line of best fit (3 Marks)
✅ Correct Plotting & Line
Plot coordinates from Table 2 for large lumps:
- (0, 0), (20, 16), (40, 30), (60, 40), (80, 46), (100, 48)
- Line of best fit: A smooth curve starting at (0,0), levelling off gradually.
🧠 Graph Drawing Rules
- Use small, sharp '×' marks directly on the grid intersections.
- Examiners allow a tolerance of ± ½ small square.
- Draw a single, smooth, continuous curve. Avoid "feathering" (multiple sketchy lines) or connecting points with a ruler.
❌ Common Errors
Connecting the points dot-to-dot with straight ruler lines. Chemical reactions with changing rates produce curved lines of best fit, not jagged polygons!
• [2 marks] for all 6 points plotted correctly (allow 1 mark for 4 or 5 points correctly plotted).
• [1 mark] for a smooth curve of best fit.
Question 03.4
Calculating mean rate of reaction from 0 to 60 s (3 Marks)
📐 Step-by-Step Calculation
Step 1: Read value from Figure 4 for small lumps at t = 60 s
Volume at 60 s = 48 cm³
Step 2: Substitute into the given rate equation
Mean rate = 48 cm³ / 60 s
Step 3: Calculate the final value
Mean rate = 0.8 cm³/s
🧠 Exam Technique
- Check which curve: The question specifically asked for small calcium carbonate lumps (Figure 4, not your plotted curve!).
- Look carefully at the grid: At 60 s, the curve passes exactly through 48 cm³.
- If you misread the volume (e.g. read 49 cm³), you can still get 2 method marks if you show 49 / 60 = 0.82 . Always show your working!
❌ Common Errors
Using 50 cm³ (the final volume) instead of reading the volume at 60 seconds. Read the time specified in the question carefully.
• [1 mark] for finding volume = 48 (cm³).
• [1 mark] for working showing 48 / 60 (or correctly using an incorrect volume).
• [1 mark] for 0.8 (cm³/s).
Question 03.5
Describing changes in volume over time (2 Marks)
✅ Model Answers
Between 0 and 20 seconds:
The volume of gas collected increases (or rises from 0 to 26 cm³ / reaction is fastest).
Between 80 and 100 seconds:
There is no change in the volume of gas collected (it stays constant at 50 cm³ / the reaction has stopped).
🧠 Reading Rate Curves
- A steep upward slope = gas volume is increasing rapidly.
- A flat horizontal plateau = volume stays constant because the limiting reactant has been completely used up.
❌ Common Errors
Stating that the volume "decreases" between 80 and 100 seconds. The rate has decreased to zero, but the total volume stays constant at 50 cm³!
• [1 mark] for volume increases between 0 and 20 s.
• [1 mark] for no change in volume (or reaction has stopped) between 80 and 100 s.
Question 03.6
Identifying the type of error (1 Mark)
✅ Correct Answer
☑ Systematic error
💡 Key Knowledge: Experimental Errors
- Systematic error: An error that causes readings to differ from the true value by a consistent amount each time (e.g. zero error on a balance).
- Random error: Unpredictable variations caused by human reaction time or slight environmental fluctuations.
- Zero error: A specific type of systematic error where an instrument gives a non-zero reading when the measured quantity is zero.
🧠 Exam Technique
The balance "always read 0.2 g before being used". Because it shifts every measurement in the same direction by the exact same amount (+0.2 g), it is definitely a systematic error.
Question 03.7
Surface area calculation for a cube (3 Marks)
📐 Step-by-Step Calculation
Dimensions of large cube: 2 mm × 2 mm × 2 mm
Step 1: Calculate the area of one face
Area of 1 face = 2 mm × 2 mm = 4 mm²
Step 2: Multiply by the number of faces (6)
Total surface area = 4 mm² × 6
Step 3: State the final answer
Total surface area = 24 mm²
🧠 Exam Technique
Cubes always have 6 identical square faces. Always structure your calculation clearly in two stages:
- Area of single square face = length × width
- Total surface area = single face area × 6
❌ Common Errors
- Calculating volume instead of surface area: 2 × 2 × 2 = 8 mm³ (scores 0).
- Multiplying by 4 sides instead of 6 faces (forgetting top and bottom faces): 4 × 4 = 16 mm².
• [1 mark] for calculating area of one face = 4 (mm²).
• [1 mark] for multiplying face area by 6 (e.g. 4 × 6).
• [1 mark] for 24 (mm²).
Question 03.8
Surface area and rate of reaction (1 Mark)
✅ Correct Answer
The rate of reaction of the eight smaller cubes is faster.
💡 Collision Theory Link
- Smaller cubes have a greater surface area to volume ratio.
- More particles of calcium carbonate are exposed to the acid.
- This leads to a higher frequency of collisions between reacting particles.
- Therefore, the rate of reaction increases (faster).
🧠 Exam Tip
The question provides the word bank: faster , slower , the same . Choose only from the exact words provided in the box.
Topics
Chemistry · C6: The Rate and Extent of Chemical Change · C8: Chemical Analysis
Question and mark scheme from the AQA GCSE Chemistry examination, Chemistry Paper 2 (Foundation), November 2020. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.