AQA GCSE Chemistry Chemistry Paper 1 (Foundation), June 2025: Question 5

15 marks · Standard Demand difficulty · Short Answer

Answer a series of questions on the electrolysis of molten compounds and aqueous solutions, including aluminium extraction and calculating the rate of gas production from a graph.

Practise this question

Question

Question 5 on electrolysis across multiple parts. It includes: Table 4 showing products of molten copper chloride and potassium bromide; Figure 4 showing an industrial aluminium extraction cell; multiple choice and short answer questions about aluminium oxide, cryolite, and carbon anodes; Figure 5 showing the experimental apparatus for the electrolysis of magnesium sulfate solution with inverted measuring cylinders; Figure 6 showing a zoomed-in inverted measuring cylinder containing gas; Figure 7 showing a line graph of volume of hydrogen against time for currents of 0.05 A and 0.10 A; and Figure 8 showing a triangle drawn on the 0.10 A line to determine its gradient.
Question text

05 This question is about electrolysis.

05.1 Table 4 shows some of the products of electrolysis of two molten compounds.

Complete Table 4.

[2 marks]

Table 4

Product at the Product at the

Molten compound

negative electrode positive electrode

Copper chloride Chlorine

Potassium bromide Potassium

Aluminium is extracted by electrolysis of a molten mixture of aluminium oxide

and cryolite.

The products are molten aluminium and oxygen gas.

Figure 4 shows the electrolysis cell.

Figure 4

05.2 What is the formula of oxygen gas?

[1 mark]

Tick ( ) one box.

O O O2 2 O

2 19

05.3 Aluminium oxide contains the ions Al3+ and O2–

Explain why aluminium is produced at the negative electrode.

[2 marks]

05.4 The melting point of aluminium oxide is 2045 °C.

The melting point of the mixture of aluminium oxide and cryolite is 950 °C.

Explain why the electrolysis uses the mixture instead of pure aluminium oxide.

[2 marks]

05.5 The positive electrodes in the electrolysis cell are made of carbon.

Why do the positive electrodes need to be continually replaced?

[1 mark]

Tick ( ) one box.

Carbon reacts with the aluminium oxide.

Carbon reacts with the aluminium produced.

Carbon reacts with the oxygen produced.20

A student investigated the electrolysis of magnesium sulfate solution.

Figure 5 shows the apparatus.

Figure 5

This is the method used.

1. Set the power supply to give a current of 0.05 A.

2. Measure the volume of each gas every minute for 5 minutes.

3. Repeat steps 1 and 2 using a current of 0.10 A in step 1.21

05.6 Figure 6 shows a measuring cylinder during the electrolysis.

Figure 6

What is the volume of gas in the measuring cylinder?

[1 mark]

Tick ( ) one box.

2.7 cm3 3.4 cm3 4.6 cm3

05.7 Hydrogen is produced instead of magnesium at the negative electrode.

Why is hydrogen produced at the negative electrode?

[1 mark]

Tick ( ) one box.

Hydrogen is less reactive than magnesium.

Hydrogen has the same reactivity as magnesium.

Hydrogen is more reactive than magnesium.22

05.8 Figure 7 shows the results for the volume of hydrogen collected.

Figure 7

Which hypothesis explains the results in Figure 7?

[1 mark]

Tick ( ) one box.

The volume of hydrogen collected depends on both

the current and the time.

The volume of hydrogen collected depends on the current

but not the time.

The volume of hydrogen collected depends on the time

but not the current. 23

05.9 Figure 8 is a repeat of part of the graph for current = 0.10 A in Figure 7.

Figure 8

Determine the gradient of the graph in Figure 8.

Use the equation

change in volume

gradient =

change in time

[4 marks]

Change in volume = cm3

Change in time = min

Gradient = cm3/min

Mark scheme

Show the mark scheme Mark scheme for Question 5 detailing accepted answers: 05.1: copper at negative electrode and bromine at positive electrode (2 marks); 05.2: O₂ (1 mark); 05.3: aluminium ions are positive and attracted to the negative electrode (2 marks); 05.4: lower melting point and less energy required (2 marks); 05.5: carbon reacts with the oxygen produced (1 mark); 05.6: 3.4 cm³ (1 mark); 05.7: hydrogen is less reactive than magnesium (1 mark); 05.8: volume depends on both current and time (1 mark); 05.9: change in volume = 1.9, change in time = 2.5, gradient = 1.9 / 2.5 = 0.76 cm³/min (4 marks). Total: 15 marks.

Question 5

AO /

Question Answers Mark

Spec. Ref.

05.1

product at the product at the

molten compound

negative electrode positive electrode

copper chloride copper chlorine 1 AO2

4.4.3.2

potassium bromide potassium bromine 1

AO /

Question Answers Extra information Mark

Spec. Ref.

05.2 O2 1 AO1

4.1.1.1

4.2.1.4

AO /

Spec. Ref.

05.3 aluminium ions are positive(ly 1 AO1

charged) 4.4.3.1

4.4.3.2

4.4.3.3

(so) are attracted to the negative allow (and) opposite charges 1

electrode attract

AO /

Spec. Ref.

05.4 (the mixture) has a lower 1 AO3

melting point (than aluminium

oxide)

(so) less energy is required 1 AO1

4.4.3.3

AO /

Spec. Ref.

14 05.5 carbon reacts with the oxygen 1 AO1

produced 4.4.3.3

AO /

Spec. Ref.

05.6 3.4 cm3 1 AO2

4.4.3.4

RPA3

AO /

Spec. Ref.

05.7 hydrogen is less reactive than 1 AO1

magnesium 4.4.3.4

RPA3

AO /

Spec. Ref.

05.8 the volume of hydrogen 1 AO3

collected depends on both the 4.4.3.4

current and the time RPA3

AO /

Spec. Ref.

05.9 (change in volume = 3.8 – 1.9 =) 1 AO2

1.9 (cm3) 4.4.3.4

allow any correct matching RPA3

pairs of values of volume and

(change in time = 5 – 2.5 =) time for 2 marks 1

2.5 (min)

1.9 1

(gradient =) allow correct use of incorrectly

2.5

determined values of volume

and / or time

= 0.76 (cm3/min) allow correct use of incorrectly 1

determined values of volume

and / or time

Total Question 5 15 15

How to answer it

Electrolysis of Molten Compounds and Aqueous Solutions

AQA GCSE Chemistry • Paper 1 • 15 Marks Total

What this question tests

This question assesses fundamental and practical principles across Topic 4: Chemical Changes (Electrolysis):

  • Predicting products from the electrolysis of molten binary ionic compounds.
  • Industrial extraction of aluminium from molten aluminium oxide using cryolite and carbon anodes.
  • Electrostatic attraction of ions to oppositely charged electrodes ( Al³⁺ to the cathode).
  • Electrolysis of aqueous solutions: applying the reactivity series rule at the cathode ( H⁺ vs metal).
  • Apparatus reading: accurately measuring gas volume collected by downward displacement in an inverted measuring cylinder.
  • Graph skills: evaluating scientific hypotheses and calculating rates/gradients using gradient = Δy / Δx with correct units.

Question 05.1 (2 marks)

Predicting Products of Molten Compounds

✅ Correct Answers

Molten compound Product at negative electrode (cathode) Product at positive electrode (anode)
Copper chloride copper [1] Chlorine
Potassium bromide Potassium bromine [1]
1 mark for copper; 1 mark for bromine.

💡 Key Knowledge

  • Molten ionic compounds contain only two elements: the metal cation and the non-metal anion (no water/no H⁺/OH⁻).
  • Negative electrode (cathode): attracts positive metal ions → forms metal atoms.
  • Positive electrode (anode): attracts negative non-metal ions → forms non-metal molecules.

❌ Common Errors

  • Writing bromide instead of bromine. The product is the elemental halogen (bromine gas/liquid), not the ion.
  • Writing chemical formulas when names are used (e.g. Br₂ instead of bromine). Stick to the naming format established in the table.

Question 05.2 (1 mark)

Formula of Oxygen Gas

✅ Correct Answer

Tick: O₂ [1 mark]

💡 Key Knowledge

  • Oxygen gas exists naturally as a diatomic molecule: two oxygen atoms covalently bonded together ( O₂ ).
  • Do not confuse the elemental molecule O₂ with an oxide ion ( O²⁻ ) or individual oxygen atoms ( O ).

🧠 Exam Technique

Remember diatomic elements using the mnemonic "I Have No Clever Or Brilliant Friends": I₂, H₂, N₂, Cl₂, O₂, Br₂, F₂.

Question 05.3 (2 marks)

Movement of Ions During Aluminium Extraction

✅ Correct Answer

  • Aluminium ions are positively charged (or are Al³⁺ ions) [1 mark]
  • (So) they are attracted to the negative electrode / cathode (allow: opposite charges attract) [1 mark]

💡 Key Knowledge

  • PANIC rule: Positive Anode, Negative Is Cathode.
  • Opposite charges always attract: positively charged cations migrate to the cathode; negatively charged anions ( O²⁻ ) migrate to the anode.

❌ Common Errors

  • Vaguely stating "aluminium is negative" – aluminium atoms have no charge; it is the aluminium ions ( Al³⁺ ) that carry a positive charge.
  • Stating only that "opposites attract" without explicitly stating that the aluminium ion is positive.

Question 05.4 (2 marks)

Role of Cryolite in Aluminium Extraction

✅ Correct Answer

  • The mixture has a lower melting point (than pure aluminium oxide / lowers the operating temperature from 2045 °C to 950 °C) [1 mark]
  • (So) less energy is required / reduces energy costs [1 mark]

💡 Key Knowledge

  • Aluminium oxide has a giant ionic lattice with extremely strong electrostatic attractions between Al³⁺ and O²⁻ ions, giving it a melting point over 2000 °C.
  • Dissolving it in molten cryolite drastically lowers the melting point to around 950 °C.

🧠 Exam Technique

Always pair property change with practical/economic consequence: Lower melting point → Less energy needed / cheaper to run.

Question 05.5 (1 mark)

Replacement of Carbon Anodes

✅ Correct Answer

Tick: Carbon reacts with the oxygen produced. [1 mark]

💡 Key Knowledge

  • Oxygen gas is liberated at the positive carbon (graphite) anode: 2O²⁻ → O₂ + 4e⁻
  • At 950 °C, the carbon anodes react with the hot oxygen: C (s) + O₂ (g) → CO₂ (g)
  • This causes the anodes to burn away slowly, meaning they must be replaced regularly.

❌ Common Errors

Confusing the reaction with aluminium. Carbon does not react with aluminium metal under these conditions; aluminium forms at the bottom/negative electrode.

Question 05.6 (1 mark)

Reading an Inverted Measuring Cylinder

✅ Correct Answer

Tick: 3.4 cm³ [1 mark]

🧠 Exam Technique: Downward Displacement

  • Notice the scale on the inverted cylinder: 0 is at the closed top, increasing downwards ( 2, 4, 6, 8, 10 cm³ ).
  • Between 2 and 4 , there are 10 small divisions → each small division represents 0.2 cm³ .
  • The liquid level is 7 marks below 2.0: 2.0 + (7 × 0.2) = 3.4 cm³ .

❌ Common Errors

Reading from the bottom up! Students who misread the inverted scale read 4.6 cm³ or 2.7 cm³. Always check which end has the zero mark on collected gas apparatus.

Question 05.7 (1 mark)

Aqueous Electrolysis: Cathode Rules

✅ Correct Answer

Tick: Hydrogen is less reactive than magnesium. [1 mark]

💡 Key Knowledge: Cathode Rule for Solutions

  • In an aqueous solution, water provides H⁺ and OH⁻ ions.
  • At the negative cathode, H⁺ and metal ions compete for electrons.
  • The less reactive element is discharged:
    • If the metal is more reactive than hydrogen (e.g. Mg, Na, K), hydrogen gas is produced.
    • If the metal is less reactive than hydrogen (e.g. Cu, Ag), the metal is deposited.

❌ Common Errors

Choosing "Hydrogen is more reactive than magnesium" – remember magnesium is high in the reactivity series; hydrogen is discharged because it is less reactive.

Question 05.8 (1 mark)

Interpreting Graphical Relationships

✅ Correct Answer

Tick: The volume of hydrogen collected depends on both the current and the time. [1 mark]

🧠 Exam Technique: Evaluating Graphs

  • Effect of time: For each curve, volume increases linearly as time increases from 0 to 5 min → volume depends on time.
  • Effect of current: At any chosen time (e.g. 5 min), a current of 0.10 A yields ~3.8 cm³, while 0.05 A yields ~1.9 cm³ → volume depends on current.
  • Therefore, volume depends on both variables.

Question 05.9 (4 marks)

Determining Gradient from a Graph

📐 Step-by-Step Gradient Calculation

Using the reference triangle printed on Figure 8:

1 Find change in volume (Δy):
Read values at the top and bottom of the vertical line:
Change in volume = 3.8 - 1.9 = 1.9 cm³ [1 mark]

2 Find change in time (Δx):
Read values at the right and left of the horizontal line:
Change in time = 5.0 - 2.5 = 2.5 min [1 mark]

3 Substitute into gradient formula:
Gradient = (Change in volume) / (Change in time) = 1.9 / 2.5 [1 mark]

4 Calculate final answer:
Gradient = 0.76 cm³/min [1 mark]

Mark Scheme Allowance: Any correct matching pair of values from the graph is accepted (e.g. using the origin: 3.8 / 5.0 = 0.76 ). If volume or time is read incorrectly, error carried forward (ecf) applies for working and final division.

🧠 Exam Technique

  • Always check the grid scale carefully: on the y-axis, 10 small squares = 1.0 cm³ (each square = 0.1 cm³); on the x-axis, 10 small squares = 1 min (each square = 0.1 min).
  • Where an exam question prints "Change in volume" and "Change in time" arrows directly on the graph, use the exact coordinates indicated by those construction lines!

❌ Calculation Traps to Avoid

  • Inverting the gradient: Dividing time by volume ( 2.5 / 1.9 = 1.32 ) gives zero marks for the final two steps. Remember: gradient = y / x = rise / run .
  • Unit mismatches: The answer space states cm³/min , so keep time in minutes – do not convert minutes into seconds.

Topics

Chemistry · Required Practicals · C4: Chemical Changes · Required Practicals

Question and mark scheme from the AQA GCSE Chemistry examination, Chemistry Paper 1 (Foundation), June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.