AQA GCSE Combined Science: Trilogy Physics Paper 2 (Higher), 2019: Question 6

9 marks · Standard Demand difficulty · Extended Answer

Explain how the forces on an aeroplane must change for it to land and calculate the mass of the aeroplane from its deceleration and resultant force.

Practise this question

Question

The question page shows Figure 9, a free-body diagram of an aeroplane flying at constant speed and constant height. A central dot has four labelled arrows: lift upwards, weight downwards, thrust to the right, and air resistance to the left. Part 06.1 asks students to explain how the forces need to change so the aeroplane can land, worth 4 marks. Part 06.2 states that the aeroplane lands at 80 m/s, then takes 28 s to decelerate to 10 m/s, and that the mean resultant force during deceleration is 750 000 N; students must calculate the mass of the aeroplane, worth 5 marks.
Question text

06 Figure 9 shows a free body diagram for an aeroplane flying at a constant speed and

at a constant height.

The speed of the aeroplane is much greater than the speed at which the

aeroplane lands.

Figure 9

06.1 Explain how the forces need to change so the aeroplane can land.

[4 marks]

06.2 The aeroplane lands at a speed of 80 m/s

After landing, the aeroplane takes 28 s to decelerate to a speed of 10 m/s

The mean resultant force on the aeroplane as it decelerates is 750 000 N

Calculate the mass of the aeroplane.

[5 marks]

Mass = kg

Mark scheme

Show the mark scheme The mark scheme is a table for questions 06.1 and 06.2. For 06.1, marks are awarded for stating that thrust decreases or drag increases, causing a resultant force opposite to motion, and that lift decreases while weight stays the same, causing a resultant downward force; references to weight increasing are not allowed for the last two points. For 06.2, the scheme shows calculating acceleration using a = (10 - 80) / 28 = -2.5 m/s squared, then using F = ma as -750000 = m × -2.5, rearranging to m = -750000 / -2.5, giving 300000 kg for 5 marks total.

AO /

Question Answers Extra information Mark ID

Spec. Ref.

1xAO1

06.1 thrust decreases allow air resistance or drag 1 1xAO2 E

increases 2xAO3

6.5.4.2.1

ignore air resistance decreases

as speed decreases

so there is a resultant force in allow so air resistance or drag is 1

opposite direction greater than thrust

lift must decrease (because 1

weight stays the same)

so there is a resultant allow so weight is greater than 1

downwards force lift

the last two marking points

cannot be awarded if there is a

reference to the weight

increasing

an answer of 300 000 (kg) AO2

06.2 scores 5 marks 6.5.4.1.5 E

6.5.4.2.2

(10-80) (80-10)

a = allow a = 1

28 28

a = (–)2.5 (m/s2) a valid equation must have been 1

used to calculate a to score

subsequent marks

(–) 750 000 = m × (–)2.5 allow a correct substitution using 1

their calculated value of a

(-)750 000 allow a correct rearrangement 1

m = using their calculated value of a

(-)2.5

m = 300 000 (kg) allow a correct calculation using 1

their calculated value of a

Total 9

How to answer it

Aeroplane Forces and Deceleration

What this question tests

Applying force diagrams to a changing situation, explaining resultant force, and using force = mass × acceleration with a deceleration calculation. You need to identify which forces change, describe the direction of the resultant force, and show a clear multi-step calculation with correct units.

Question 06

Aeroplane landing: changing forces and finding mass

Overall focus: forces, resultant force, and Newton’s second law

This is a standard GCSE physics-style question: part 06.1 is explanation, and part 06.2 is a calculation. Top marks come from clear force language and careful rearrangement.

Part 06.1 — Explain how the forces need to change so the aeroplane can land

✅ Correct answers

  • Thrust decreases.
  • This gives a resultant force opposite to the direction of motion so the plane slows down.
  • Lift decreases because the plane is no longer needing to stay at constant height.
  • This means there is a resultant downward force.

To get all 4 marks, students needed both horizontal and vertical changes.

💡 Key knowledge

  • At constant speed and constant height, forces are balanced.
  • For landing, the plane must slow down and descend.
  • If thrust is reduced, air resistance can become greater than thrust, so the plane decelerates.
  • If lift is reduced while weight stays the same, weight becomes greater than lift, so the plane moves downward.

🧠 Exam technique

  • Use the word resultant to show you understand unbalanced forces.
  • Link each force change to the effect: thrust down → slows down, lift down → descends.
  • Think in pairs: thrust vs air resistance, lift vs weight.

❌ Common errors

  • Saying only “the plane slows down” without explaining how the forces change.
  • Writing that weight increases — the mark scheme says this is not correct here.
  • Mixing up lift and weight.
  • Forgetting to state that the resultant force must be downwards for landing.

📐 Model 4-mark answer

Thrust decreases, so there is a resultant force opposite to the direction of motion and the aeroplane slows down. Lift decreases, while weight stays the same, so weight becomes greater than lift. This gives a resultant downward force so the aeroplane descends and can land.

Why this gets full marks: it includes both changes, both resultant forces, and clear cause-and-effect reasoning.

Part 06.2 — Calculate the mass of the aeroplane

💡 Key knowledge

  • Use force = mass × acceleration.
  • Rearrange to mass = force ÷ acceleration.
  • Because the aeroplane is slowing down, acceleration is negative.
  • In GCSE exam questions, correct handling of signs and units is essential.

🧠 Exam technique

  • Write the formula first.
  • Calculate acceleration before using force = mass × acceleration.
  • Show every stage clearly: substitution, rearrangement, final answer.
  • Include the unit kg in the final answer.

❌ Common errors

  • Forgetting that the speed change is from 80 m/s to 10 m/s.
  • Using 80 + 10 instead of finding the change in speed.
  • Not dividing by time correctly.
  • Leaving the answer in N instead of kg.
  • Ignoring the negative sign and losing method marks.

📐 Step-by-step calculation

  1. Find the acceleration:
    a = (final speed − initial speed) ÷ time
    a = (10 − 80) ÷ 28
  2. Calculate:
    a = −70 ÷ 28 = −2.5 m/s²
  3. Use force = mass × acceleration:
    750 000 = m × (−2.5)
  4. Rearrange for mass:
    m = 750 000 ÷ 2.5
  5. Answer:
    m = 300 000 kg

✅ Correct answer

Mass = 300 000 kg

The mark scheme allows 300 000 kg even if a student uses the negative acceleration correctly, because mass is a positive quantity.

🧠 Why this earns 5 marks

  • 1 mark for a correct acceleration equation.
  • 1 mark for finding a = −2.5 m/s² .
  • 1 mark for substituting into F = ma .
  • 1 mark for rearranging correctly to find mass.
  • 1 mark for the final correct value 300 000 kg .

❌ Calculation traps to avoid

  • Trap 1: using the wrong speed order — it should be final minus initial for acceleration.
  • Trap 2: forgetting that deceleration means the acceleration is negative.
  • Trap 3: writing 750 000 = 2.5m without showing the sign or rearrangement clearly.
  • Trap 4: giving the answer in the wrong unit.

Examiner insight: what made the difference?

💡 What strong answers did

  • Named the force changes directly: thrust decreases, lift decreases.
  • Explained the result: resultant force opposite direction of motion and resultant downward force.
  • Used clear physics vocabulary rather than vague phrases.
  • Showed a full calculation chain in 06.2.

❌ Where students lost marks

  • Only describing the plane landing, not the forces.
  • Saying weight increases, which the mark scheme rejects.
  • Doing the maths but not showing the equation or rearrangement.
  • Mixing up the direction of the resultant force.

Topics

Physics · P5: Forces

Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Physics Paper 2 (Higher), 2019. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.