AQA GCSE Combined Science: Trilogy Physics Paper 2 (Higher), 2019: Question 5
11 marks · Standard Demand difficulty · Extended Answer
Identify the proportional relationship for a spring and calculate a person's mass and the spring constant of mattress springs, then explain which spring property would make the mattress soft.
Practise this questionQuestion
Question text
05 Figure 8 shows some springs inside a mattress.
Figure 8
05.1 Which proportionality is true when a force is applied to a spring?
[1 mark]
Tick ( ) one box.
Force ∝ energy stored
Force ∝ extension
Force ∝ length
Force ∝ spring constant 15
A mattress contains 1200 identical springs.
A person lies on the mattress and the springs compress.
The mean force on each spring in the mattress is 0.49 N
05.2 Calculate the mass of the person.
gravitational field strength = 9.8 N/kg
[4 marks]
Mass = kg
The mean compression of each spring is 3.5 × 10–3 m
05.3
Calculate the spring constant of each spring in the mattress.
Give the unit.
[4 marks]
Spring constant =
Unit =
05.4 For a given force, different springs compress by different amounts.
*15* Explain what property of the springs would make the mattress soft.
[2 marks]
Mark scheme
Show the mark scheme
AO /
Question Answers Extra information Mark ID
Spec. Ref.
05.1 force ∝ extension 1 AO1 A
6.5.3
an answer of 60 (kg) scores 4
05.2 marks AO2 E
6.5.1.3
F = 0.49 × 1 200 1
or
F = 588 (N)
588 = m × 9.8 allow a correct substitution using 1
an incorrectly calculated value
of F
588 allow a correct rearrangement 1
m = using an incorrectly calculated
9.8
value of F
m = 60 (kg) allow a correct calculation using 1
an incorrectly calculated value
of F
OR
0.49 = mean mass per spring ×
9.8 (1)
0.49
mean mass per spring =
9.8
(1)
mean mass per spring = 0.050
(1)
m = 0.050 × 1200 = 60 (kg) (1)
05.3 an answer of 140 scores 3 3 x AO2 E
calculation marks 1 x AO1
6.5.3
0.49 = k × 3.5 × 10–3 1
0.49 1
k = -3
3.5×10
140 1
N/m 1
05.4 springs with a low spring 1 AO3 E
constant 6.5.3
because they can compress by allow they can compress by the 1
a larger amount (for a given same amount for a smaller force
force)
allow low stiffness
Total 11
How to answer it
Spring Mattress: Force, Mass and Spring Constant
Hooke’s law ideas, using F = mg , calculating the total force shared by many springs, rearranging equations, and explaining how spring stiffness affects softness. Marks are gained for correct method, correct substitution, correct units, and a clear explanation.
Springs in a mattress
This question uses a real-life context to test your understanding of force, extension, spring constant, and how to calculate with multiples of springs.
Part (05.1) Which proportionality is true when a force is applied to a spring?
1 mark
✅ Correct answer
Force ∝ extension
💡 Key knowledge
- For a spring obeying Hooke’s law: F = kx
- This means force is directly proportional to extension.
- As the force increases, the spring stretches more.
🧠 Exam technique
- Read the wording carefully: the question asks for a proportionality.
- Choose the option that matches the law, not a general idea.
❌ Common errors
- Choosing force ∝ energy stored — this is not the GCSE relationship here.
- Choosing force ∝ length — it is extension that matters, not total length.
- Choosing force ∝ spring constant — the spring constant is a property of the spring, not something force is proportional to in this question.
Part (05.2) Calculate the mass of the person
4 marks
📐 Calculation: step by step
- Total force from all springs = 0.49 × 1200
- F = 588 N
- Use F = mg
- 588 = m × 9.8
- m = 588 ÷ 9.8
- m = 60 kg
✅ Full-mark answer
Mass = 60 kg
A completely correct final answer scores all 4 marks.
💡 Key knowledge
- Weight is a force: W = mg
- Here the force on one spring is given, and there are 1200 identical springs.
- So first find the total force supported by all springs.
🧠 Exam technique
- Show the equation before rearranging.
- Include units at each stage: N for force, kg for mass.
- Use the given value of g = 9.8 N/kg .
- Marks were awarded for method, not just the final answer.
❌ Common errors
- Using only 0.49 N instead of multiplying by 1200 .
- Forgetting that the force on the whole mattress is the sum of the forces on all springs.
- Writing m = 588 × 9.8 instead of dividing.
- Leaving the answer in newtons instead of kilograms.
Examiner insight
Many students gained early marks by correctly calculating the total force first. Some lost marks by not linking the total force to the equation F = mg . Top answers were clear, organised, and showed each stage.
Part (05.3) Calculate the spring constant of each spring
4 marks
📐 Calculation: step by step
- Use Hooke’s law: F = kx
- Substitute values: 0.49 = k × 3.5 × 10⁻³
- Rearrange: k = 0.49 ÷ (3.5 × 10⁻³)
- Calculate: k = 140
- Write the unit: N/m
✅ Full-mark answer
Spring constant = 140 N/m
The mark scheme accepts the correct answer of 140 with the unit N/m.
💡 Key knowledge
- Hooke’s law: F = kx
- k = spring constant
- x = extension or compression in metres
- The force and compression must be in the correct units before calculating.
🧠 Exam technique
- Always rearrange the equation clearly.
- Give the unit for the spring constant: N/m .
- Notice the compression is given in standard form: 3.5 × 10⁻³ m .
❌ Common errors
- Using the whole mattress force instead of the force on one spring.
- Forgetting to divide by the compression.
- Writing the unit as N instead of N/m .
- Missing the unit mark even if the number is correct.
Common calculation trap
The biggest trap is mixing up the force on one spring with the total force on the mattress. In this question, 0.49 N is for each spring, so you use that value when finding k .
Part (05.4) Explain what property of the springs would make the mattress soft
2 marks
✅ Correct answer
The springs should have a low spring constant, so they compress by a larger amount for the same force.
💡 Key knowledge
- A soft mattress gives more under your weight.
- That means the springs are easier to compress.
- Lower stiffness = larger compression for the same force.
🧠 Exam technique
- For 2 marks, give both the property and the reason.
- A good answer links the spring constant to how much the spring compresses.
❌ Common errors
- Saying “strong springs” or “stiff springs” would make it soft — this is the opposite of the correct idea.
- Just saying “it compresses a lot” without mentioning a low spring constant.
- Confusing “soft” with “long” or “large”.
What distinguished top-level responses
The best answers used the phrase low spring constant and then explained that the springs compress more for the same force. That is exactly what the examiner was looking for.
Quick revision summary
Key equations
- F = mg
- F = kx
Remember
- Force in newtons (N)
- Mass in kilograms (kg)
- Extension/compression in metres (m)
- Spring constant in N/m
Final exam tip
- Show the full working for calculations.
- Check whether a force is for one spring or all springs.
- Use the correct units to secure the final mark.
Topics
Physics · P5: Forces
Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Physics Paper 2 (Higher), 2019. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.