AQA GCSE Combined Science: Trilogy Physics Paper 2 (Higher), 2019: Question 5

11 marks · Standard Demand difficulty · Extended Answer

Identify the proportional relationship for a spring and calculate a person's mass and the spring constant of mattress springs, then explain which spring property would make the mattress soft.

Practise this question

Question

The question page shows Figure 8, a cutaway image of a mattress with several internal coil springs visible, with one spring labelled by an arrow. Part 05.1 asks which proportionality is true when a force is applied to a spring, with four tick-box options: force proportional to energy stored, extension, length, or spring constant. Part 05.2 states that a mattress contains 1200 identical springs, a person lies on the mattress so the springs compress, and the mean force on each spring is 0.49 N; students must calculate the mass of the person using gravitational field strength 9.8 N/kg. Part 05.3 gives a mean compression of each spring of 3.5 × 10 to the minus 3 metres and asks for the spring constant and unit, and part 05.4 asks what property of the springs would make the mattress soft if different springs compress by different amounts for the same force.
Question text

05 Figure 8 shows some springs inside a mattress.

Figure 8

05.1 Which proportionality is true when a force is applied to a spring?

[1 mark]

Tick ( ) one box.

Force ∝ energy stored

Force ∝ extension

Force ∝ length

Force ∝ spring constant 15

A mattress contains 1200 identical springs.

A person lies on the mattress and the springs compress.

The mean force on each spring in the mattress is 0.49 N

05.2 Calculate the mass of the person.

gravitational field strength = 9.8 N/kg

[4 marks]

Mass = kg

The mean compression of each spring is 3.5 × 10–3 m

05.3

Calculate the spring constant of each spring in the mattress.

Give the unit.

[4 marks]

Spring constant =

Unit =

05.4 For a given force, different springs compress by different amounts.

*15* Explain what property of the springs would make the mattress soft.

[2 marks]

Mark scheme

Show the mark scheme The mark scheme is a table with rows for questions 05.1 to 05.4, listing answers, extra information, mark allocations, and assessment objective references. For 05.1 the accepted answer is force proportional to extension. For 05.2 it shows using total force equals 0.49 multiplied by 1200 to get 588 N, then applying 588 = m × 9.8 and rearranging to give m = 60 kg, with an alternative method via mass per spring. For 05.3 it uses 0.49 = k × 3.5 × 10 to the minus 3, rearranges to k = 0.49 divided by 3.5 × 10 to the minus 3, giving 140 N/m. For 05.4 it awards marks for stating that soft mattresses use springs with a low spring constant, or low stiffness, because they compress more for a given force.

AO /

Question Answers Extra information Mark ID

Spec. Ref.

05.1 force ∝ extension 1 AO1 A

6.5.3

an answer of 60 (kg) scores 4

05.2 marks AO2 E

6.5.1.3

F = 0.49 × 1 200 1

or

F = 588 (N)

588 = m × 9.8 allow a correct substitution using 1

an incorrectly calculated value

of F

588 allow a correct rearrangement 1

m = using an incorrectly calculated

9.8

value of F

m = 60 (kg) allow a correct calculation using 1

an incorrectly calculated value

of F

OR

0.49 = mean mass per spring ×

9.8 (1)

0.49

mean mass per spring =

9.8

(1)

mean mass per spring = 0.050

(1)

m = 0.050 × 1200 = 60 (kg) (1)

05.3 an answer of 140 scores 3 3 x AO2 E

calculation marks 1 x AO1

6.5.3

0.49 = k × 3.5 × 10–3 1

0.49 1

k = -3

3.5×10

140 1

N/m 1

05.4 springs with a low spring 1 AO3 E

constant 6.5.3

because they can compress by allow they can compress by the 1

a larger amount (for a given same amount for a smaller force

force)

allow low stiffness

Total 11

How to answer it

Spring Mattress: Force, Mass and Spring Constant

What this question tests

Hooke’s law ideas, using F = mg , calculating the total force shared by many springs, rearranging equations, and explaining how spring stiffness affects softness. Marks are gained for correct method, correct substitution, correct units, and a clear explanation.

Question 05.1–05.4

Springs in a mattress

This question uses a real-life context to test your understanding of force, extension, spring constant, and how to calculate with multiples of springs.

Part (05.1) Which proportionality is true when a force is applied to a spring?

1 mark

✅ Correct answer

Force ∝ extension

💡 Key knowledge

  • For a spring obeying Hooke’s law: F = kx
  • This means force is directly proportional to extension.
  • As the force increases, the spring stretches more.

🧠 Exam technique

  • Read the wording carefully: the question asks for a proportionality.
  • Choose the option that matches the law, not a general idea.

❌ Common errors

  • Choosing force ∝ energy stored — this is not the GCSE relationship here.
  • Choosing force ∝ length — it is extension that matters, not total length.
  • Choosing force ∝ spring constant — the spring constant is a property of the spring, not something force is proportional to in this question.

Part (05.2) Calculate the mass of the person

4 marks

📐 Calculation: step by step

  1. Total force from all springs = 0.49 × 1200
  2. F = 588 N
  3. Use F = mg
  4. 588 = m × 9.8
  5. m = 588 ÷ 9.8
  6. m = 60 kg

✅ Full-mark answer

Mass = 60 kg

A completely correct final answer scores all 4 marks.

💡 Key knowledge

  • Weight is a force: W = mg
  • Here the force on one spring is given, and there are 1200 identical springs.
  • So first find the total force supported by all springs.

🧠 Exam technique

  • Show the equation before rearranging.
  • Include units at each stage: N for force, kg for mass.
  • Use the given value of g = 9.8 N/kg .
  • Marks were awarded for method, not just the final answer.

❌ Common errors

  • Using only 0.49 N instead of multiplying by 1200 .
  • Forgetting that the force on the whole mattress is the sum of the forces on all springs.
  • Writing m = 588 × 9.8 instead of dividing.
  • Leaving the answer in newtons instead of kilograms.

Examiner insight

Many students gained early marks by correctly calculating the total force first. Some lost marks by not linking the total force to the equation F = mg . Top answers were clear, organised, and showed each stage.

Part (05.3) Calculate the spring constant of each spring

4 marks

📐 Calculation: step by step

  1. Use Hooke’s law: F = kx
  2. Substitute values: 0.49 = k × 3.5 × 10⁻³
  3. Rearrange: k = 0.49 ÷ (3.5 × 10⁻³)
  4. Calculate: k = 140
  5. Write the unit: N/m

✅ Full-mark answer

Spring constant = 140 N/m

The mark scheme accepts the correct answer of 140 with the unit N/m.

💡 Key knowledge

  • Hooke’s law: F = kx
  • k = spring constant
  • x = extension or compression in metres
  • The force and compression must be in the correct units before calculating.

🧠 Exam technique

  • Always rearrange the equation clearly.
  • Give the unit for the spring constant: N/m .
  • Notice the compression is given in standard form: 3.5 × 10⁻³ m .

❌ Common errors

  • Using the whole mattress force instead of the force on one spring.
  • Forgetting to divide by the compression.
  • Writing the unit as N instead of N/m .
  • Missing the unit mark even if the number is correct.

Common calculation trap

The biggest trap is mixing up the force on one spring with the total force on the mattress. In this question, 0.49 N is for each spring, so you use that value when finding k .

Part (05.4) Explain what property of the springs would make the mattress soft

2 marks

✅ Correct answer

The springs should have a low spring constant, so they compress by a larger amount for the same force.

💡 Key knowledge

  • A soft mattress gives more under your weight.
  • That means the springs are easier to compress.
  • Lower stiffness = larger compression for the same force.

🧠 Exam technique

  • For 2 marks, give both the property and the reason.
  • A good answer links the spring constant to how much the spring compresses.

❌ Common errors

  • Saying “strong springs” or “stiff springs” would make it soft — this is the opposite of the correct idea.
  • Just saying “it compresses a lot” without mentioning a low spring constant.
  • Confusing “soft” with “long” or “large”.

What distinguished top-level responses

The best answers used the phrase low spring constant and then explained that the springs compress more for the same force. That is exactly what the examiner was looking for.

Quick revision summary

Key equations

  • F = mg
  • F = kx

Remember

  • Force in newtons (N)
  • Mass in kilograms (kg)
  • Extension/compression in metres (m)
  • Spring constant in N/m

Final exam tip

  • Show the full working for calculations.
  • Check whether a force is for one spring or all springs.
  • Use the correct units to secure the final mark.

Topics

Physics · P5: Forces

Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Physics Paper 2 (Higher), 2019. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.