AQA GCSE Combined Science: Trilogy Physics Paper 2 (Higher), 2020: Question 4

11 marks · Standard Demand difficulty · Short Answer

Explain and calculate aspects of a bowling ball’s motion, including scalar and vector quantities, resistive forces, momentum, and conservation of momentum in a collision with a pin.

Practise this question

Question

The question page shows a photograph labelled Figure 8 of a girl bowling a ball down a ten-pin bowling lane, with arrows identifying the pins, lane and ball. Below it are five short-answer parts: define vector and scalar quantities; explain why the ball decelerates on a horizontal lane; write the equation linking mass, momentum and velocity; calculate the mass of the ball from a velocity of 5.0 m/s and momentum of 26 kg m/s; and explain why the ball slows down when it hits a pin using momentum. A simple line diagram labelled Figure 9 shows the bowling ball touching one pin, and each part has answer lines with marks shown as 2, 2, 1, 3 and 3 respectively.
Question text

04 Figure 8 shows a girl bowling a ball along a ten-pin bowling lane.

Figure 8

The girl is trying to knock down the ten pins at the end of the bowling lane.

04.1 Velocity is a vector quantity, speed is a scalar quantity.

Describe what is meant by a vector quantity and a scalar quantity.

[2 marks]

Vector quantity

Scalar quantity

04.2 The bowling lane is horizontal.

Explain why the bowling ball decelerates as it travels along the lane.

[2 marks]

Figure 9 shows the bowling ball hitting one of the pins.

Figure 9

04.3 Write down the equation that links mass (m), momentum (p) and velocity (v).

[1 mark]

04.4 The bowling ball has a velocity of 5.0 m/s when it hits the pin.

The momentum of the bowling ball is 26 kg m/s

Calculate the mass of the bowling ball.

[3 marks]

12 Mass = kg

04.5 Explain why the bowling ball slows down when it hits the pin.

You should use ideas about momentum in your answer.

[3 marks]

Mark scheme

Show the mark scheme The mark scheme is a table with columns for Question, Answers, Extra information, Mark, and AO/Spec. Ref. It awards marks for stating that a vector has magnitude and direction and a scalar has magnitude only; for identifying a resistive force such as friction or air resistance causing a resultant force opposite to velocity or work done on the ball; for the equation p = mv; for calculating mass using 26 = m × 5.0 to give 5.2 kg; and for explaining that momentum is conserved in the collision so the pin gains momentum and the ball’s momentum decreases. An additional note allows credit in the final part for mentioning equal and opposite forces if no other mark is awarded, and the total is 11 marks.

AO /

Question Answers Extra information Mark

Spec. Ref.

04.1 (vector quantity) has magnitude 1 AO1

and a direction 6.5.4.1.3

(scalar quantity) has magnitude 1

only

04.2 resistive force acts on the ball allow friction or air resistance 1 AO2

6.5.4.2.1

so (resultant) force in opposite

direction to velocity 1

or

so work is done on the ball

04.3 momentum = mass × velocity 1 AO2

6.5.5.1

or

p = mv

04.4 26 = m × 5.0 1 AO2

6.5.5.1

26 1

m =

5.0

5.2 (kg)

04.5 momentum is conserved in the 1 AO1

collision (assuming no external 6.5.5.2

forces)

momentum of the pin increases 1

therefore the momentum of the

ball must decrease. 1

if no other mark is awarded,

allow 1 mark for when the ball

exerts a force on the pin, the pin

exerts an equal and opposite 11

force on the ball

Total 11

How to answer it

Bowling Ball, Speed and Momentum

What this question tests
This question checks whether you can:
  • define vector and scalar quantities
  • explain slowing down using forces and friction
  • recall and use the formula p = mv
  • carry out a simple rearrangement and calculation
  • explain a collision using momentum conservation
Question parts: 04.1–04.5

Study Guide: Bowling Ball Momentum

This is a straight GCSE physics question on motion, forces and momentum. Full marks come from giving the exact physics wording and showing calculations clearly.

04.1 Vector and scalar quantities

Describe what is meant by a vector quantity and a scalar quantity.

✅ Correct answers

  • Vector quantity: has magnitude and direction
  • Scalar quantity: has magnitude only
Marks are awarded separately: 1 mark for the vector definition and 1 mark for the scalar definition.

💡 Key knowledge

  • Magnitude means size or amount.
  • Examples of vectors: velocity, force, momentum.
  • Examples of scalars: speed, distance, time, mass.

🧠 Exam technique

  • Use the exact wording “magnitude and direction” for a vector.
  • Use the exact wording “magnitude only” for a scalar.
  • Keep it short: these are definition marks.

❌ Common errors

  • Saying a vector has “size and speed” or “force and direction” only.
  • Writing that a scalar has “no direction” without saying it has magnitude only.
  • Confusing speed and velocity.

04.2 Why the bowling ball decelerates

Explain why the bowling ball decelerates as it travels along the lane.

✅ Correct answers

  • A resistive force acts on the ball.
  • This force is in the opposite direction to the motion/velocity.
  • Accept: friction or air resistance.
  • Alternative mark point: work is done on the ball.
To get 2 marks, you need both the force idea and the opposite-direction idea.

💡 Key knowledge

  • When an object has a resultant force opposite its motion, it slows down.
  • The lane is horizontal, so weight and normal contact force balance vertically.
  • The slowing is caused by horizontal resistive forces.

🧠 Exam technique

  • State the cause first: friction / air resistance.
  • Then link it to motion: it acts opposite to velocity.
  • Use the word decelerates or slows down.

❌ Common errors

  • Saying “gravity slows it down” on a horizontal lane.
  • Writing only “there is friction” without explaining direction.
  • Using “force” with no clue that it is resistive/opposite.

04.3 Momentum equation

Write down the equation that links mass (m), momentum (p) and velocity (v).

✅ Correct answers

  • momentum = mass × velocity
  • p = mv
This is a 1-mark recall question: one correct equation is enough.

💡 Key knowledge

  • Momentum is measured in kg m/s.
  • Mass is in kg.
  • Velocity is in m/s.

🧠 Exam technique

  • Remember: p stands for momentum, not pressure here.
  • If you write words, make sure they are in the right order: mass × velocity.

❌ Common errors

  • Writing p = m/v or v = mp instead.
  • Leaving out the multiplication sign or using the wrong symbols.

04.4 Calculate the mass of the bowling ball

Velocity = 5.0 m/s, momentum = 26 kg m/s. Find the mass.

📐 Calculations: step-by-step

  1. Use the equation p = mv
  2. Substitute the values: 26 = m × 5.0
  3. Rearrange: m = 26 ÷ 5.0
  4. Calculate: m = 5.2
  5. Write the unit: kg

Mass = 5.2 kg

✅ Correct answer

5.2 kg

Marks are usually awarded for: using the correct equation, rearranging correctly, and giving the correct final answer with unit.

🧠 Exam technique

  • Always start by writing the formula.
  • Show the rearrangement, not just the final answer.
  • Keep the unit kg in your final answer.
  • Use the given values exactly: 26 and 5.0.

❌ Common errors

  • Dividing the wrong way round: 5.0 ÷ 26 .
  • Writing the answer without units.
  • Rounding badly: 5 is not as good as 5.2 here.
  • Forgetting that momentum is mass × velocity, so mass must be momentum ÷ velocity.

04.5 Why the bowling ball slows down on impact

Explain why the bowling ball slows down when it hits the pin. Use ideas about momentum.

✅ Correct answers

  • Momentum is conserved in the collision, if there are no external forces.
  • The pin gains momentum.
  • So the ball must lose momentum, which means it slows down.
  • Accept extra credit idea: the ball and pin exert equal and opposite forces on each other.
Full marks come from linking the pin’s gain in momentum to the ball’s decrease in momentum.

💡 Key knowledge

  • In a closed system, total momentum before = total momentum after.
  • During collision, momentum is transferred from the ball to the pin.
  • Less momentum usually means lower velocity if mass stays the same.

🧠 Exam technique

  • Use the phrase “momentum is conserved”.
  • Then explain the transfer: pin gains, ball loses.
  • Finish by linking loss of momentum to slowing down.

❌ Common errors

  • Saying the ball slows because “it uses up momentum” — momentum is not used up.
  • Claiming momentum disappears.
  • Forgetting the pin’s momentum increases.
  • Talking only about force, with no momentum explanation.

Examiner insight: what separates full-mark answers

💡 What examiners wanted

  • Precise definitions for vector and scalar.
  • A clear resistive-force explanation for slowing down on the lane.
  • Correct recall of p = mv .
  • A calculation with rearrangement and unit.
  • A momentum-transfer explanation for the collision.

🧠 How to score the marks

  • Use the correct keywords: magnitude, direction, friction, momentum conserved.
  • Write short, direct statements for definition questions.
  • For calculations, show every step clearly.
  • Always include units in the final answer.

Topics

Physics · P5: Forces

Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Physics Paper 2 (Higher), 2020. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.