AQA GCSE Combined Science: Trilogy Physics Paper 2 (Higher), 2020: Question 4
11 marks · Standard Demand difficulty · Short Answer
Explain and calculate aspects of a bowling ball’s motion, including scalar and vector quantities, resistive forces, momentum, and conservation of momentum in a collision with a pin.
Practise this questionQuestion
Question text
04 Figure 8 shows a girl bowling a ball along a ten-pin bowling lane.
Figure 8
The girl is trying to knock down the ten pins at the end of the bowling lane.
04.1 Velocity is a vector quantity, speed is a scalar quantity.
Describe what is meant by a vector quantity and a scalar quantity.
[2 marks]
Vector quantity
Scalar quantity
04.2 The bowling lane is horizontal.
Explain why the bowling ball decelerates as it travels along the lane.
[2 marks]
Figure 9 shows the bowling ball hitting one of the pins.
Figure 9
04.3 Write down the equation that links mass (m), momentum (p) and velocity (v).
[1 mark]
04.4 The bowling ball has a velocity of 5.0 m/s when it hits the pin.
The momentum of the bowling ball is 26 kg m/s
Calculate the mass of the bowling ball.
[3 marks]
12 Mass = kg
04.5 Explain why the bowling ball slows down when it hits the pin.
You should use ideas about momentum in your answer.
[3 marks]
Mark scheme
Show the mark scheme
AO /
Question Answers Extra information Mark
Spec. Ref.
04.1 (vector quantity) has magnitude 1 AO1
and a direction 6.5.4.1.3
(scalar quantity) has magnitude 1
only
04.2 resistive force acts on the ball allow friction or air resistance 1 AO2
6.5.4.2.1
so (resultant) force in opposite
direction to velocity 1
or
so work is done on the ball
04.3 momentum = mass × velocity 1 AO2
6.5.5.1
or
p = mv
04.4 26 = m × 5.0 1 AO2
6.5.5.1
26 1
m =
5.0
5.2 (kg)
04.5 momentum is conserved in the 1 AO1
collision (assuming no external 6.5.5.2
forces)
momentum of the pin increases 1
therefore the momentum of the
ball must decrease. 1
if no other mark is awarded,
allow 1 mark for when the ball
exerts a force on the pin, the pin
exerts an equal and opposite 11
force on the ball
Total 11
How to answer it
Bowling Ball, Speed and Momentum
- define vector and scalar quantities
- explain slowing down using forces and friction
- recall and use the formula p = mv
- carry out a simple rearrangement and calculation
- explain a collision using momentum conservation
Study Guide: Bowling Ball Momentum
This is a straight GCSE physics question on motion, forces and momentum. Full marks come from giving the exact physics wording and showing calculations clearly.
04.1 Vector and scalar quantities
Describe what is meant by a vector quantity and a scalar quantity.
✅ Correct answers
- Vector quantity: has magnitude and direction
- Scalar quantity: has magnitude only
💡 Key knowledge
- Magnitude means size or amount.
- Examples of vectors: velocity, force, momentum.
- Examples of scalars: speed, distance, time, mass.
🧠 Exam technique
- Use the exact wording “magnitude and direction” for a vector.
- Use the exact wording “magnitude only” for a scalar.
- Keep it short: these are definition marks.
❌ Common errors
- Saying a vector has “size and speed” or “force and direction” only.
- Writing that a scalar has “no direction” without saying it has magnitude only.
- Confusing speed and velocity.
04.2 Why the bowling ball decelerates
Explain why the bowling ball decelerates as it travels along the lane.
✅ Correct answers
- A resistive force acts on the ball.
- This force is in the opposite direction to the motion/velocity.
- Accept: friction or air resistance.
- Alternative mark point: work is done on the ball.
💡 Key knowledge
- When an object has a resultant force opposite its motion, it slows down.
- The lane is horizontal, so weight and normal contact force balance vertically.
- The slowing is caused by horizontal resistive forces.
🧠 Exam technique
- State the cause first: friction / air resistance.
- Then link it to motion: it acts opposite to velocity.
- Use the word decelerates or slows down.
❌ Common errors
- Saying “gravity slows it down” on a horizontal lane.
- Writing only “there is friction” without explaining direction.
- Using “force” with no clue that it is resistive/opposite.
04.3 Momentum equation
Write down the equation that links mass (m), momentum (p) and velocity (v).
✅ Correct answers
- momentum = mass × velocity
- p = mv
💡 Key knowledge
- Momentum is measured in kg m/s.
- Mass is in kg.
- Velocity is in m/s.
🧠 Exam technique
- Remember: p stands for momentum, not pressure here.
- If you write words, make sure they are in the right order: mass × velocity.
❌ Common errors
- Writing p = m/v or v = mp instead.
- Leaving out the multiplication sign or using the wrong symbols.
04.4 Calculate the mass of the bowling ball
Velocity = 5.0 m/s, momentum = 26 kg m/s. Find the mass.
📐 Calculations: step-by-step
- Use the equation p = mv
- Substitute the values: 26 = m × 5.0
- Rearrange: m = 26 ÷ 5.0
- Calculate: m = 5.2
- Write the unit: kg
Mass = 5.2 kg
✅ Correct answer
5.2 kg
🧠 Exam technique
- Always start by writing the formula.
- Show the rearrangement, not just the final answer.
- Keep the unit kg in your final answer.
- Use the given values exactly: 26 and 5.0.
❌ Common errors
- Dividing the wrong way round: 5.0 ÷ 26 .
- Writing the answer without units.
- Rounding badly: 5 is not as good as 5.2 here.
- Forgetting that momentum is mass × velocity, so mass must be momentum ÷ velocity.
04.5 Why the bowling ball slows down on impact
Explain why the bowling ball slows down when it hits the pin. Use ideas about momentum.
✅ Correct answers
- Momentum is conserved in the collision, if there are no external forces.
- The pin gains momentum.
- So the ball must lose momentum, which means it slows down.
- Accept extra credit idea: the ball and pin exert equal and opposite forces on each other.
💡 Key knowledge
- In a closed system, total momentum before = total momentum after.
- During collision, momentum is transferred from the ball to the pin.
- Less momentum usually means lower velocity if mass stays the same.
🧠 Exam technique
- Use the phrase “momentum is conserved”.
- Then explain the transfer: pin gains, ball loses.
- Finish by linking loss of momentum to slowing down.
❌ Common errors
- Saying the ball slows because “it uses up momentum” — momentum is not used up.
- Claiming momentum disappears.
- Forgetting the pin’s momentum increases.
- Talking only about force, with no momentum explanation.
Examiner insight: what separates full-mark answers
💡 What examiners wanted
- Precise definitions for vector and scalar.
- A clear resistive-force explanation for slowing down on the lane.
- Correct recall of p = mv .
- A calculation with rearrangement and unit.
- A momentum-transfer explanation for the collision.
🧠 How to score the marks
- Use the correct keywords: magnitude, direction, friction, momentum conserved.
- Write short, direct statements for definition questions.
- For calculations, show every step clearly.
- Always include units in the final answer.
Topics
Physics · P5: Forces
Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Physics Paper 2 (Higher), 2020. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.