AQA GCSE Combined Science: Trilogy Physics Paper 2 (Foundation), November 2021: Question 1

8 marks · Low Demand difficulty · Short Answer

Identify contact and non-contact forces, calculate weight from mass and gravitational field strength, and determine the resultant force on a person jumping.

Practise this question

Question

Question 01 consists of seven parts about forces. Sub-question 01.1 asks to identify a non-contact force from electrostatic force, friction force, or tension force. Figure 1 shows a top-down view of a person's bare feet standing on analog bathroom scales reading approximately 55 kg. Sub-questions 01.2 and 01.3 ask about the relationship and name of the forces between the person and scales. Sub-question 01.4 gives a mass of 55 kg and gravitational field strength of 9.8 N/kg to calculate weight. Sub-question 01.5 asks how weight changes when moving to the equator where gravity is weaker. Figure 2 shows an illustration of a person about to jump, with an upward vertical force arrow labelled 1100 N and a downward vertical arrow labelled 800 N originating from a point labelled X. Sub-questions 01.6 and 01.7 ask to name point X and calculate the resultant force.
Question text

01 Forces are either contact forces or non-contact forces.

01.1 Which of the following is a non-contact force?

[1 mark]

Tick ( ) one box.

Electrostatic force

Friction force

Tension force 3

Figure 1 shows a person standing on some bathroom scales.

Figure 1

The person exerts a downward force on the scales and the scales exert an upward

force on the person.

01.2 Which sentence about the forces is true?

[1 mark]

Tick ( ) one box.

The downward force is less than the upward force.

The downward force is the same size as the upward force.

The downward force is greater than the upward force.

*0021.*3 What is the name of the upward force on the person?

[1 mark]

Tick ( ) one box.

Air resistance

Normal contact force

Weight 4

01.4 The person on the scales has a mass of 55 kg.

gravitational field strength = 9.8 N/kg

Calculate the weight of the person.

Use the equation:

weight = mass × gravitational field strength

[2 marks]

Weight = N

01.5 The gravitational field strength is not the same at all points on the surface of

the Earth.

The gravitational field strength is weakest at the equator.

A person travelled from the UK to the equator.

What happened to the weight of the person?

[1 mark]

Tick ( ) one box.

The weight decreased.

The weight remained the same.

The weight increased. 5

Figure 2 shows the forces acting on a person.

The person is about to jump.

Figure 2

01.6 The arrow representing the weight of the person is drawn from point X.

What is the name given to point X?

[1 mark]

Tick ( ) one box.

Centre of force

Centre of mass

Centre of weight

01.7 Determine the size of the resultant force on the person in Figure 2.

[1 mark]

Resultant force = N

Mark scheme

Show the mark scheme Mark scheme table for question 01. 01.1: electrostatic force (1 mark, AO1). 01.2: the downward force is the same size as the upward force (1 mark, AO2). 01.3: normal contact force (1 mark, AO1). 01.4: W = 55 × 9.8 (1 mark), 539 (N), allow 540 (N) (1 mark, AO2). 01.5: the weight decreased (1 mark, AO3). 01.6: centre of mass (1 mark, AO3). 01.7: 300 (N) (1 mark, AO2). Total marks: 8.

AO /

Question Answers Extra information Mark

Spec. Ref.

01.1 electrostatic force 1 AO1

6.5.1.2

01.2 the downward force is the same 1 AO2

size as the upward force 6.5.1.2

01.3 normal contact force 1 AO1

6.5.1.2

01.4 W = 55 × 9.8 1 AO2

6.5.1.3

539 (N) allow 540 (N) 1

01.5 the weight decreased 1 AO3

6.5.1.3

01.6 centre of mass 1 AO3

6.5.1.3

01.7 300 (N) 1 AO2

6.5.1.4

Total 8

How to answer it

Forces: Contact Forces, Weight, and Resultant Forces

📋 What this question tests

This Foundation-tier question covers fundamental concepts from AQA GCSE Physics / Combined Science: Trilogy (Topic 6.5 Forces):

  • Distinguishing between contact and non-contact forces (Specification 6.5.1.2).
  • Understanding Newton's Third Law / balanced contact forces when stationary.
  • Identifying the normal contact force supporting an object on a surface.
  • Calculating weight using W = m × g (Specification 6.5.1.3).
  • Deducing how variation in gravitational field strength ( g ) affects weight.
  • Identifying the centre of mass as the point through which weight acts.
  • Calculating a resultant force along a straight vertical line (Specification 6.5.1.4).
Part 01.1 • 1 Mark

Non-Contact Forces

Identifying force types

✅ Correct Answer

Tick the box for: Electrostatic force

💡 Key Knowledge

  • Non-contact forces act at a distance without physical contact: gravity, electrostatic force, magnetic force.
  • Contact forces require objects to physically touch: friction, tension, air resistance, normal contact force.
Mark Scheme: 1 mark for selecting 'electrostatic force'. Any other choice scores 0.
Part 01.2 • 1 Mark

Interaction Forces on Scales

Comparing forces between person and scales

✅ Correct Answer

Tick the box for: The downward force is the same size as the upward force.

🧠 Exam Technique & Physics Insight

Newton's Third Law states that when two objects interact, they exert equal and opposite forces on each other. The downward push of the person on the scales equals the upward push of the scales on the person.

❌ Common Errors

Thinking the downward force must be greater because the person is pushing down or "weighs a lot". If one force were larger, the scales or the person would accelerate into the ground!

Mark Scheme: 1 mark for 'the downward force is the same size as the upward force'.
Part 01.3 • 1 Mark

Naming the Upward Force

Support force from a solid surface

✅ Correct Answer

Tick the box for: Normal contact force

💡 Key Knowledge

  • Normal contact force: The perpendicular push exerted by a solid surface supporting an object. "Normal" means at right angles (90°) to the surface.
  • Weight: Acts downwards towards the centre of the Earth.
  • Air resistance: Only acts when an object is moving through air.
Mark Scheme: 1 mark for 'normal contact force'.
Part 01.4 • 2 Marks

Calculating Weight

Using the formula: weight = mass × gravitational field strength

📐 Step-by-Step Calculation

  1. Identify the formula:
    W = m × g
  2. Substitute the values:
    W = 55 kg × 9.8 N/kg [1 mark]
  3. Calculate final answer:
    W = 539 N [1 mark]

Note: The mark scheme also allows rounding to 540 (2 sig figs).

❌ Common Errors & Traps

  • Dividing instead of multiplying: Always follow the formula provided in the question.
  • Omitting working: Always show substitution ( 55 × 9.8 ) to secure the method mark if a calculation error occurs.
  • Mass vs Weight: Mass is in kilograms ( kg ); Weight is a force measured in newtons ( N ).
Mark Scheme: 1 mark for correct substitution ( 55 × 9.8 ), 1 mark for correct answer ( 539 or 540 ).
Part 01.5 • 1 Mark

Variation of Weight with Location

Relationship between weight and gravitational field strength

✅ Correct Answer

Tick the box for: The weight decreased.

💡 Key Knowledge

Since Weight = mass × g , weight is directly proportional to gravitational field strength ( g ).

  • The question states g is weakest at the equator.
  • A lower value of g means a lower value of weight.
  • The person's mass remains constant, but their weight decreases.

❌ Misconception

Confusing mass and weight. Students often incorrectly choose "The weight remained the same", confusing weight with mass.

Mark Scheme: 1 mark for 'the weight decreased'.
Part 01.6 • 1 Mark

Centre of Mass

Point of action for weight

✅ Correct Answer

Tick the box for: Centre of mass

💡 Key Knowledge

The centre of mass of an object is the single point at which the entire mass (and therefore weight) of the object may be thought to act.

❌ Common Errors

Guessing "centre of weight" or "centre of force" — these are made-up distractor terms not used in GCSE physics.

Mark Scheme: 1 mark for 'centre of mass'.
Part 01.7 • 1 Mark

Determining Resultant Force

Subtracting opposing vertical forces

📐 Step-by-Step Calculation

  1. Identify forces and directions:
    Upward force = 1100 N
    Downward force = 800 N
  2. Subtract opposing forces:
    1100 − 800 = 300
  3. State final value:
    Resultant force = 300 N (upwards)

🧠 Exam Technique

When two forces act along the same line in opposite directions, the resultant force is found by subtracting the smaller force from the larger force. (If they acted in the same direction, you would add them).

Mark Scheme: 1 mark for 300 (N).

Topics

Physics · P5: Forces

Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Physics Paper 2 (Foundation), November 2021. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.