AQA GCSE Combined Science: Trilogy Physics Paper 2 (Foundation), November 2021: Question 5

14 marks · Standard Demand difficulty · Extended Answer

Answer questions on aeroplane acceleration, work done, and evaluate the radiation dose and risks of travelling in a rocket aeroplane compared to a jet aeroplane.

Practise this question

Question

Question 5 contains six sub-questions about a rocket aeroplane. Part 5.1 asks what happens to air resistance as the rocket accelerates. Part 5.2 asks to complete a sentence comparing lift force to weight using options 'less than', 'the same as', or 'greater than'. Part 5.3 asks to calculate distance given average speed of 35 m/s and time 14 s using distance = average speed × time. Part 5.4 asks for the equation linking distance, force, and work done. Part 5.5 asks to calculate the average force exerted when travelling 270 m with 54,000,000 J of work done. Part 5.6 provides Table 2 showing speed (rocket: 8000 m/s, jet: 250 m/s) and radiation dose each hour (rocket: 0.006 mSv, jet: 0.003 mSv) and asks to evaluate the risks and possible consequences of flying in a rocket aeroplane versus a jet aeroplane for the same journey.
Question text

05 Scientists are developing a rocket aeroplane designed to travel much faster than

jet aeroplanes.

05.1 The rocket aeroplane must accelerate along a runway to take off.

What would happen to the air resistance acting on the rocket aeroplane as

it accelerates?

[1 mark]

05.2 An upward force called lift will act on the wings of the rocket aeroplane when it moves.

Complete the sentence.

Choose the answer from the box.

[1 mark]

less than the same as greater than

As the rocket aeroplane starts to accelerate along the runway, the lift force on

the wings will be the

weight of the rocket aeroplane. 18

05.3 During the first 14 seconds the average speed of the rocket aeroplane on the runway

will be 35 m/s.

Calculate the distance that the rocket aeroplane will travel during the first 14 seconds.

Use the equation:

distance travelled = average speed × time

[2 marks]

Distance travelled = m

05.4 Write down the equation which links distance (s), force (F) and work done (W).

[1 mark]

05.5 When the rocket aeroplane travels a distance of 270 m on the runway the engines will

do 54 000 000 J of work.

Calculate the average force exerted by the engines.

[3 marks]

19Average force = N

05.6 The rocket aeroplane will fly at a greater height than a jet aeroplane.

The height that an aeroplane flies at affects the radiation dose a passenger will

receive each hour.

Table 2 shows the speed of each aeroplane and the radiation dose a passenger will

*18* receive each hour.

Table 2

Speed in Radiation dose each

Aeroplane

metres per second hour in millisieverts

Rocket aeroplane 8000 0.006

Jet aeroplane 250 0.003

Exposure to ionising radiation has risks and possible consequences.

Evaluate the risks and possible consequences of flying in a rocket aeroplane and in a

jet aeroplane.

Assume the same journey is made in each aeroplane.

Use values from Table 2.

[6 marks]

Mark scheme

Show the mark scheme Mark scheme for Question 5 with a total of 14 marks. 05.1: (air resistance) increases (1 mark). 05.2: less than (1 mark). 05.3: substitution s = 35 × 14, answer 490 (m) (2 marks). 05.4: work done = force × distance or W = Fs (1 mark). 05.5: 54 000 000 = F × 270, rearrangement F = 54 000 000 / 270, answer 200 000 (N) (3 marks). 05.6: Level 2 (4–6 marks) requires relevant features identified, differences noted with magnitude/calculation; Level 1 (1–3 marks) identifies relevant features and differences. Indicative content includes rocket being 32 times faster, radiation dose per hour 2 times greater, overall radiation dose 16 times less for rocket, and risks of ionising radiation causing skin cancer and gene mutations.

AO /

Question Answers Extra information Mark

Spec. Ref.

05.1 (air resistance) increases 1 AO1

6.5.4.1.5

05.2 less than 1 AO3

6.5.4.1.5

05.3 s = 35 × 14 1 AO2

6.5.4.1.2

s = 490 (m) 1

05.4 work done = force × distance 1 AO1

6.5.2

or

W = Fs

05.5 54 000 000 = F × 270 1 AO2

6.5.2

54 000 000 1

F =

F = 200 000 (N) – OMBINED SCIENCE: TRILOGY – 1 – JUNE 2021

AO /

Question Answers Mark

Spec. Ref.

05.6 Level 2: Scientifically relevant features are identified; the way(s) in 4–6 AO3

which they are similar/different is made clear and (where 6.5.4.1.2

appropriate) the magnitude of the similarity/difference is noted.

Level 1: Relevant features are identified and differences noted. 1–3

No relevant content 0

Indicative content

• distance travelled is the same for each aeroplane

• time in the air is much greater for jet aeroplane

12 • speed of rocket plane is much greater

• speed of rocket plane is 32 times greater

• radiation dose each hour greater for rocket aeroplane

• radiation dose each hour is 2 times greater for rocket aeroplane

• overall radiation dose is less for rocket plane

• dose in jet aeroplane is 16 times greater overall

• much higher risk in jet aeroplane

• increased risk of skin cancer

• increased risk of gene mutation and cancer

To access level 2, there must be a relevant calculation.

Total 14

How to answer it

Forces, Motion & Radiation Risk in Aeroplanes

📌 What This Question Tests

This question brings together core Physics topics across motion, work, and radiation:

  • Fluid resistance: Understanding how velocity affects drag/air resistance.
  • Resultant forces: Comparing vertical forces (lift vs weight) during a ground run.
  • Kinematics: Calculating distance from average speed and time ( s = v × t ).
  • Work Done: Recalling and rearranging W = F × s to solve for force.
  • Extended Evaluation (6 marks): Comparing ionising radiation risks across different flight scenarios using quantitative ratios and biological consequences.
Question 05.1

Air Resistance on an Accelerating Aeroplane

1 Mark • Assessment Objective: AO1

✅ Correct Answer

Increases (or goes up / gets bigger).

💡 Key Knowledge

Air resistance is a frictional drag force that increases as the speed of an object moving through a fluid increases.

Examiner Tip: "Increases" is all that is required for the mark. Avoid vague phrases like "it gets stronger" or "it changes".
Question 05.2

Vertical Forces During Runway Acceleration

1 Mark • Assessment Objective: AO3

✅ Correct Answer

less than

"As the rocket aeroplane starts to accelerate along the runway, the lift force on the wings will be less than the weight of the rocket aeroplane."

🧠 Exam Technique

  • If lift were greater than weight, the plane would accelerate upwards into the air.
  • If lift were equal to weight, the plane would be just on the verge of lifting off.
  • As it starts to accelerate along the runway, it is firmly on the ground, so lift is still less than weight.
Question 05.3

Distance Travelled from Average Speed

2 Marks • Assessment Objective: AO2

📐 Step-by-Step Calculation

Step 1: Identify values & equation

average speed (v) = 35 m/s
time (t) = 14 s
distance = average speed × time

Step 2: Substitute values

distance = 35 × 14

Step 3: Calculate final answer

Distance = 490 m

❌ Common Errors

  • Dividing speed by time ( 35 ÷ 14 = 2.5 ) instead of multiplying. The formula was given directly in the question—always read carefully!
  • Arithmetic slips when multiplying without a calculator.
Mark Scheme Breakdown:
• [1 mark] for correct substitution: 35 × 14
• [1 mark] for correct answer: 490 (m)
Question 05.4

Equation Linking Distance, Force, and Work Done

1 Mark • Assessment Objective: AO1

✅ Correct Equation

work done = force × distance

or in symbols: W = Fs (or W = Fd )

🧠 Exam Technique

Any correct rearrangement is also accepted, e.g.:

force = work done ÷ distance ( F = W / s )

Warning: Do not write just letters without standard meaning. Stick to words or the standard spec symbols ( W, F, s ).

Question 05.5

Calculating Average Force

3 Marks • Assessment Objective: AO2

📐 Step-by-Step Calculation

Step 1: Write down values
s = 270 m
W = 54 000 000 J

Step 2: Substitute into formula
54 000 000 = F × 270

Step 3: Rearrange to solve for force (F)
F = 54 000 000 ÷ 270

Step 4: State final value with units
Average force = 200 000 N (or 2 × 10⁵ N / 200 kN )

❌ Common Calculation Traps

  • Counting zeros incorrectly: 54 000 000 has six zeros. Double check when entering into your calculator.
  • Multiplying instead of dividing: Calculating 54 000 000 × 270 gives a nonsensical massive number.
Mark Scheme Breakdown:
• [1 mark] for substitution: 54 000 000 = F × 270
• [1 mark] for rearrangement: F = 54 000 000 ÷ 270
• [1 mark] for correct calculation: 200 000 (N)
Question 05.6

Evaluating Radiation Risk for Jet vs Rocket Aeroplane

6 Marks • Extended Response • Assessment Objective: AO3

Aeroplane Speed (m/s) Radiation dose each hour (mSv)
Rocket aeroplane 8000 0.006
Jet aeroplane 250 0.003

💡 The Key Scientific Paradox

At first glance, the rocket aeroplane seems more dangerous because its hourly radiation dose is double (0.006 vs 0.003 mSv/hr).

HOWEVER: The rocket travels 32 times faster, so it completes the journey in 1/32 of the time!

Therefore, the overall radiation dose received during the entire flight is significantly lower on the rocket aeroplane.

📐 Crucial Calculations (Required for Level 2 / 4–6 Marks)

1. Speed ratio:
8000 ÷ 250 = 32
The rocket is 32× faster (or jet takes 32× longer).

2. Dose rate ratio:
0.006 ÷ 0.003 = 2
Rocket has 2× higher hourly dose rate.

3. Overall total dose ratio:
Total dose = dose rate × time
Relative jet dose = 1 × 32 = 32
Relative rocket dose = 2 × 1 = 2
Jet passenger receives 32 ÷ 2 = 16 times greater total radiation dose!

✅ Model 6-Mark Structure

  • Journey comparison: Since the journey distance is the same, journey time depends entirely on speed.
  • Speed comparison: The rocket aeroplane travels at 8000 m/s compared to 250 m/s for the jet, making it 32 times faster. This means the jet spends 32 times longer in the air.
  • Dose rate comparison: The rocket exposes passengers to 0.006 mSv/hour, which is twice (2×) the rate of the jet (0.003 mSv/hour).
  • Total radiation dose: Overall dose is dose rate multiplied by time. Because the jet takes 32× longer but only has half the dose rate, the total dose received in the jet aeroplane is 16 times greater than in the rocket plane.
  • Biological risks & consequences: Ionising radiation can cause gene mutations, DNA damage, and increase the risk of cancers (e.g. skin cancer).
  • Conclusion: The risk of radiation damage is therefore significantly higher for a passenger in the jet aeroplane because of the much longer exposure time.

🧠 Level Descriptors & Examiner Notes

Level 2 (4–6 marks): Scientifically relevant features identified, differences made clear, magnitude of differences noted (e.g. 32× faster, 2× dose rate), links made to total exposure, and must include a calculation.

Level 1 (1–3 marks): Basic comparisons (e.g. rocket is faster, rocket has higher dose rate) but no quantification or fails to realise that shorter flight time reduces total dose.

Common Student Error: Claiming the rocket is more dangerous purely because 0.006 > 0.003 , forgetting to account for flight duration!

Topics

Physics · P4: Atomic Structure · P5: Forces

Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Physics Paper 2 (Foundation), November 2021. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.