AQA GCSE Combined Science: Trilogy Physics Paper 1 (Higher), 2021: Question 1

11 marks · Standard Demand difficulty · Short Answer

Answer questions about a mobile phone battery circuit using equations for potential difference, resistance, power and energy, and identify and explain the behaviour of a thermistor.

Practise this question

Question

The question page shows a photograph labelled Figure 1 of a mobile phone with its back removed and the battery placed beside it, with arrows labelling the phone and battery. Below are six parts: a multiple-choice question asking for the equation linking current, potential difference and resistance; a calculation using current 0.12 A and potential difference 3.9 V to find resistance; a recall question for the equation linking energy, power and time; a calculation using power 0.46 W and discharge time 2500 minutes to find energy transferred; Figure 2 showing the circuit symbol of a resistor rectangle crossed by a diagonal line, used in a temperature sensor; and final questions asking to identify the component and explain what happens to current when its temperature increases at constant potential difference.
Question text

01 Figure 1 shows a mobile phone with its battery removed.

Figure 1

A student measured the potential difference across the battery and then put the

battery into the phone.

01.1 What is the equation linking current (I), potential difference (V) and resistance (R)?

[1 mark]

Tick ( ) one box.

I = V R

R = I V

V = I R

V = I 2 R

01.2 The current in the electronic circuit in the mobile phone was 0.12 A.

The potential difference across the battery was 3.9 V.

Calculate the resistance of the electronic circuit in the mobile phone.

[3 marks]

Resistance = Ω

01.3 Write down the equation which links energy (E), power (P) and time (t).

[1 mark]

01.4 The battery was fully charged when it was put into the mobile phone.

The battery discharged when the mobile phone was switched on.

The average power output of the battery as it discharged was 0.46 watts.

The time taken to fully discharge the battery was 2500 minutes.

Calculate the energy transferred by the battery.

[3 marks]

Energy transferred = J

The mobile phone includes a sensor to monitor the temperature of the battery.

*04* Figure 2 shows the circuit symbol for a component used in the sensor.

Figure 2

01.5 What component does the circuit symbol shown in Figure 2 represent?

[1 mark]

01.6 The temperature of the component in Figure 2 increases.

The potential difference across the component remains constant.

Explain what happens to the current in the component.

[2 marks]

Mark scheme

Show the mark scheme The mark scheme is a table listing answers, marks and specification references for questions 01.1 to 01.6, total 11 marks. It gives V = I R for the first question; calculates resistance from 3.9 = 0.12 × R to give 32.5 ohms, allowing 33 ohms; gives energy = power × time or E = P t; converts 2500 minutes to 150000 seconds and calculates energy as 69000 J; identifies the component as a thermistor; and explains that the current increases because the resistance decreases.

AO /

Question Answers Extra information Mark

Spec. Ref.

01.1 V = I R 1 AO1

6.2.1.3

01.2 3.9 = 0.12 × R 1 AO2

6.2.1.3

3.9 1

R =

0.12

R = 32.5 (Ω) allow R = 33 (Ω) 1

01.3 energy = power × time 1 AO1

6.2.4.2

or

E = P t

01.4 time = 150 000s 1 AO2

6.2.4.2

energy = 0.46 × 150 000 allow a substitution using an 1

incorrectly/not converted value

of time

energy = 69 000 (J) allow a correct calculation using 1

an incorrectly/not converted

value of time

01.5 thermistor 1 AO1

6.2.1.1

01.6 the current will increase 1 AO1

6.2.1.4

(because) the resistance 1

decreases

Total 11

How to answer it

Mobile Phone Battery, Resistance and Energy

What this question tests

Using circuit equations correctly, rearranging equations, doing a straightforward resistance calculation, recalling the energy equation, converting minutes to seconds, identifying a thermistor symbol, and explaining how temperature affects resistance and current.

Question Overview

💡 Key facts

  • Ohm’s law: V = I R
  • Energy transferred: E = P t
  • Thermistor resistance decreases when temperature increases.

🧠 What examiners want

  • Correct formula first.
  • Substitute values with units.
  • Show rearrangement and final answer with units.

❌ Common traps

  • Using the wrong version of the equation.
  • Forgetting to convert minutes to seconds.
  • Saying “temperature increases so current decreases” for a thermistor.

Part (01.1)

What is the equation linking current (I), potential difference (V) and resistance (R)?

✅ Correct answer

V = I R

1 mark for selecting the correct equation.

💡 Key knowledge

This is Ohm’s law. It links voltage, current and resistance in a circuit.

❌ Common errors

  • I = V R is wrong.
  • R = I V is wrong.
  • V = I² R is the power equation for heating, not this one.

Part (01.2)

Calculate the resistance of the mobile phone circuit.

📐 Calculation steps

  1. Write the equation: V = I R
  2. Substitute values: 3.9 = 0.12 × R
  3. Rearrange: R = 3.9 ÷ 0.12
  4. Calculate: R = 32.5 Ω

✅ Correct answer

R = 32.5 Ω

Accept 33 Ω for rounding.

3 marks: equation, substitution/rearrangement, final answer with unit.

🧠 Exam technique

  • Use the numbers exactly as given: V = 3.9 , I = 0.12 .
  • Always include the unit Ω .
  • If you round, 33 Ω is fine.

❌ Common errors

  • Dividing the wrong way round: 0.12 ÷ 3.9
  • Using R = I / V
  • Forgetting the unit or writing V instead of Ω

Part (01.3)

Write down the equation which links energy (E), power (P) and time (t).

✅ Correct answer

E = P t

1 mark for the correct relationship.

💡 Key knowledge

Energy transferred = power × time.

❌ Common errors

  • E = P / t is incorrect.
  • P = E t is incorrect.

Part (01.4)

Calculate the energy transferred by the battery.

📐 Calculation steps

  1. Use E = P t
  2. Convert time to seconds: 2500 min × 60 = 150 000 s
  3. Substitute: E = 0.46 × 150 000
  4. Calculate: E = 69 000 J

✅ Correct answer

69 000 J

Equivalent to 6.9 × 10⁴ J .

3 marks: time conversion, substitution, final answer.

🧠 Exam technique

  • Power is in watts, so time must be in seconds.
  • Show the conversion clearly to gain method marks.
  • Use the given power: 0.46 W .

❌ Common errors

  • Using 2500 instead of converting to seconds.
  • Multiplying by 2500 and getting the wrong unit.
  • Writing the answer in Wh or kJ without being asked.

Part (01.5)

What component does the symbol in Figure 2 represent?

✅ Correct answer

Thermistor

1 mark for naming the component.

💡 Key knowledge

A thermistor is a temperature-dependent resistor, often used in sensors.

🧠 Exam technique

If you recognise a resistor symbol with a diagonal line, think “thermistor” for GCSE circuits.

Part (01.6)

The temperature of the component increases. The potential difference remains constant. Explain what happens to the current.

✅ Correct answer

The current will increase because the resistance decreases.

2 marks: one for current increasing, one for explaining resistance decreases.

💡 Key knowledge

  • For a thermistor, higher temperature means lower resistance.
  • With constant potential difference, lower resistance means higher current.
  • Use V = I R : if V stays the same and R goes down, I goes up.

❌ Common errors

  • Saying the current decreases.
  • Not linking the answer to resistance.
  • Talking only about temperature without using circuit ideas.

How the marks were earned

💡 Mark pattern

  • Simple recall questions: 1 mark for the exact equation or component name.
  • Calculation questions: marks for correct method and correct final answer.
  • Explanation questions: marks for the correct trend plus the reason.

🧠 Top-score habits

  • Write the equation before numbers.
  • Convert units first.
  • Use short, direct science sentences in explanations.

❌ Biggest traps

  • Mixing up V = I R with E = P t .
  • Forgetting 60 seconds in a minute.
  • Getting the thermistor direction backwards.

Topics

Physics · P2: Electricity

Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Physics Paper 1 (Higher), 2021. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.