AQA GCSE Combined Science: Trilogy Physics Paper 1 (Higher), 2021: Question 5
9 marks · Standard Demand difficulty · Short Answer
Calculate current from power and potential difference, interpret a potential difference–time graph, identify the current–potential difference relationship for a resistor, and compare ammeter and voltmeter readings in series and parallel circuits.
Practise this questionQuestion
Question text
05 A TENS machine uses an electrical current to relieve pain.
Figure 8 shows the electrodes of a TENS machine connected across an ankle.
Figure 8
05.1 The maximum power of the TENS machine is 240 mW.
The potential difference across the battery in the TENS machine is 2.5 V.
Calculate the maximum current from the battery.
[4 marks]
Maximum current =21 A
05.2 Figure 9 is a sketch graph showing how the potential difference across the electrodes
varies with time.
Figure 9
A student concluded that there was an alternating potential difference across
the electrodes.
How does Figure 9 show that the student was not correct?
[1 mark]
Figure 10 shows a circuit the student built using the battery from the
TENS machine.
Figure 10
The student recorded how the current in the resistor varied with the potential
*21* difference across the resistor.
Figure 11 shows a sketch graph of the results.
Figure 11
05.3 What relationship does Figure 11 show?
[1 mark]
05.4 Figure 12 shows two more circuits that the student built using the battery from the
TENS machine.
Figure 12
The resistors all have the same resistance.
Compare the readings on the voltmeter and ammeter in circuit A and circuit B.
[3 marks]
Voltmeter
Ammeter
Mark scheme
Show the mark scheme
AO /
Question Answers Extra information Mark
Spec. Ref.
05.1 240 mW = 0.24 W 1 AO2
6.2.4.1
0.24 = 2.5 × I allow a correct substitution using 1
an incorrectly/not converted
value of power
0.24 allow a correct re-arrangement 1
𝐼𝐼 = using an incorrectly/not
2.5
converted value of power
allow a correct calculation using 1
I = 0.096 (A)
an incorrectly/not converted
value of power
05.2 because the potential difference allow because potential 1 AO1
is always positive difference does not change 6.2.3.1
direction
05.3 potential difference is (directly) 1 AO2
proportional to current 6.2.1.4
05.4 voltmeter: the reading is the 1 AO2
same in both circuits 6.2.2
ammeter: the reading in circuit B allow 1 mark for the reading in 2
is twice the reading of circuit A circuit B is bigger than circuit A
Total 9
How to answer it
TENS Machine Calculations and Circuit Comparisons
This question checks power, current and potential difference calculations, using the formula P = I × V , understanding that alternating potential difference must change direction, and comparing readings in simple series and parallel circuits.
To score full marks, you need to convert units correctly, rearrange a formula, read a graph carefully, and explain circuit behaviour using correct physics vocabulary.
Using electrical power, AC graphs and circuit rules
This question is mainly about applying GCSE electricity facts in a clear, exam-style way. The mark scheme rewards correct physics method and clear explanations, not just final answers.
Part (a) Maximum current from power and voltage
05.1 Calculate the maximum current from the battery
📐 Calculations: step-by-step
- Use the power equation: P = I × V
- Convert the power first: 240 mW = 0.24 W
- Substitute values: 0.24 = I × 2.5
- Rearrange: I = 0.24 ÷ 2.5
- Calculate: I = 0.096 A
Maximum current = 0.096 A
✅ Correct answer
- 240 mW = 0.24 W
- 0.24 = 2.5 × I
- I = 0.24 ÷ 2.5
- I = 0.096 A
Why this gets 4 marks: one mark for converting units, one for substitution, one for rearranging, and one for the final correct current.
💡 Key knowledge
- Power is measured in watts (W).
- Current is measured in amperes (A).
- Potential difference is measured in volts (V).
- mW must be changed into W before using the equation.
🧠 Exam technique
- Always write the formula first: P = I × V .
- Show the unit conversion clearly to gain the first mark.
- Keep the answer in A, not mA, unless you convert it correctly.
- If you use the wrong power value but the method is right, you can still gain method marks.
❌ Common errors
- Forgetting to convert 240 mW into 0.24 W .
- Using I = P × V instead of dividing.
- Writing the answer as 0.096 mA instead of 0.096 A .
- Leaving out units completely.
Part (b) Interpreting the TENS waveform
05.2 Explain why Figure 9 shows the student was not correct
✅ Correct answer
The potential difference is always positive.
The graph shows the voltage changing in size, but it does not change direction because it never goes below zero.
💡 Key knowledge
- Alternating potential difference must change direction.
- On a graph, that means the line should go above and below zero.
- If it stays above zero, it is pulsing DC or a positive-only signal, not true alternating p.d.
🧠 Exam technique
- Use the graph evidence directly: “it stays above zero” or “it does not cross zero”.
- The mark scheme accepts either always positive or does not change direction.
❌ Common errors
- Saying “it goes up and down” without mentioning zero or direction.
- Thinking any wavy graph is automatically alternating.
- Writing “alternating current” when the question is about potential difference.
Part (c) Relationship between current and potential difference
05.3 What relationship does Figure 11 show?
✅ Correct answer
Potential difference is directly proportional to current.
💡 Key knowledge
- Direct proportion means if one increases, the other increases by the same factor.
- This is the usual relationship for an ohmic conductor at constant temperature.
- A straight line through the origin shows this relationship.
🧠 Exam technique
- Use the words directly proportional for full credit.
- If unsure, describe the pattern as “the more potential difference, the more current”.
❌ Common errors
- Saying “current causes voltage” without describing the relationship.
- Mixing up inverse and direct proportionality.
- Forgetting that the graph is a straight line through the origin.
Part (d) Comparing series and parallel circuits
05.4 Compare the voltmeter and ammeter readings in circuit A and circuit B
✅ Correct answers
Voltmeter: the reading is the same in both circuits.
Ammeter: the reading in circuit B is twice the reading in circuit A.
💡 Key knowledge
- The voltmeter measures the p.d. across one resistor in each circuit.
- Because the resistors have the same resistance, the p.d. across each one is the same in both circuits.
- Circuit B has two resistors in parallel, so the total current is larger.
- In a parallel circuit, the total current is the sum of the branch currents.
🧠 Exam technique
- For the voltmeter, say “same” clearly: “the reading is the same in both circuits”.
- For the ammeter, state the size of the difference: “twice” is the full-mark answer.
- Marks are awarded for comparing the readings, not for describing the diagram.
❌ Common errors
- Saying the voltmeter reading is bigger in circuit B.
- Saying the ammeter reading is “higher” without explaining how much higher.
- Confusing series and parallel rules.
- Thinking the voltage is shared between parallel branches in the same way as series circuits.
Examiner insight: what got marks here?
✅ What distinguished top answers
- Clear unit conversion before calculation.
- Correct rearrangement of P = I × V .
- Using graph evidence, especially “always positive”.
- Precise comparison words: “same” and “twice”.
❌ Where students lost marks
- Not converting mW to W.
- Writing vague explanations about AC.
- Using “directly proportional” incorrectly or not at all.
- Giving only one circuit reading instead of comparing both.
Topics
Physics · P2: Electricity
Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Physics Paper 1 (Higher), 2021. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.