AQA GCSE Combined Science: Trilogy Chemistry Paper 1 (Higher), 2022: Question 7
17 marks · Standard Demand difficulty · Short Answer
Answer a set of chemistry questions on extracting metals using the reactivity series, balancing and interpreting redox equations, calculating the limiting reactant and maximum mass of product, and explaining electrical conduction in sodium metal and sodium chloride.
Practise this questionQuestion
Question text
07 This question is about elements and compounds.
07.1 Figure 8 shows a reactivity series.
Figure 8
Most reactive
Potassium
Magnesium
Metal Y
Carbon
Iron
Hydrogen
Copper
Least reactive
Give the method and conditions used to extract metal Y from a compound of metal Y.
[2 marks]
Sodium reacts with titanium chloride (TiCl4) to produce titanium.
07.2 Complete the equation.
You should balance the equation.
[2 marks]
Na + TiCl4 → +
07.3 The reaction between sodium and titanium chloride is a redox reaction.
Write a half-equation to show that sodium is oxidised in this reaction.
[2 marks]
07.4 108 g of aluminum reacts with 1.21 kg of copper chloride to produce copper.
The equation for the reaction is:
2 Al + 3 CuCl2 → 3 Cu + 2 AlCl3
Calculate the maximum mass of copper produced in grams (g).
You should determine the limiting reactant.
Relative atomic masses (Ar): Al = 27 Cu = 63.5
Relative formula masses (Mr): CuCl2 = 134.5 AlCl3 = 133.5
[6 marks]
Limiting reactant is
Mass of copper = g
Sodium metal and sodium chloride are both able to conduct electricity.
07.5 Describe how sodium metal conducts electricity.
[2 marks]
07.6 Explain how sodium chloride can conduct electricity.
[3 marks]
Mark scheme
Show the mark scheme
Question 7
AO /
Question Answers Extra information Mark
Spec. Ref.
07.1 electrolysis 1 AO3
5.4.1.3
of molten compound (of metal allow liquid for molten 1 5.4.3.2
Y) 5.4.3.3
OR
displacement (1)
by heating with a more reactive
metal
or
by heating with potassium /
magnesium (1)
AO /
Spec. Ref.
07.2 4 Na + TiCl4 → 4 NaCl + Ti allow multiples 2 AO2
5.1.1.1
5.3.1.1
allow 1 mark for NaCl and Ti
with incorrect / no balancing
AO /
Spec. Ref.
ignore state symbols
07.3
Na → Na+ + e– allow multiples 2 AO2
5.4.1.2
5.4.1.4
allow 1 mark for
Na → Na+ + e–
with incorrect balancing
AO /
Spec. Ref.
07.4 method 1: AO2
108 5.3.2.2
(moles of Al = =) 4 1 5.3.2.4
1210
(moles CuCl2 = = ) allow 9
134.5 1
8.996
(identifying limiting reactant)
allow correct use of an
4 moles Al gives 6 moles Cu incorrectly calculated value(s)
8.996 moles CuCl2 gives for moles of Al and / or CuCl2
8.996 moles Cu
therefore aluminium is the must follow on from MP3 1
limiting reactant
(mass of Cu = 2 × 3 × 63.5) 1
= 6 × 63.5
= 381 (g) 1
method 2:
07.4
cont. 2Al + 3CuCl2 → 3Cu + 2AlCl3
(2×27) (3×134.5) (3×63.5)
54(g) 403.5(g) 190.5(g)
(1) (1) (1)
(so)
108 g Al (reacts with 807 g allow correct use of an incorrect
CuCl2) to produce 381 g Cu (1) calculation of mass for Al /
CuCl2 / Cu
(so) there is excess CuCl2
or
807 g CuCl2 is less than 1210 g
CuCl2 (1)
therefore aluminium is limiting must follow on from MP4 / MP5
reactant (1)
method 3:
134.5 g CuCl2 produces 63.5 g
Cu (1)
(mass conversion 1.21 kg CuCl2
=) 1210 (g) (1)
63.5
1210 g CuCl2 produces ( × allow correct use of an incorrect
134.5 / no conversion of mass of
1210 =) 571 g Cu (1)
CuCl2
54 g Al produces 190.5 g Cu (1)
190.5
108 g Al produces ( × 108
=) 381 (g) (1)
(therefore) aluminium is the must follow on from MP3 and
limiting reactant (1) MP5
AO / 21
Spec. Ref.
07.5 delocalised electrons allow free electrons 1 AO1
5.2.2.8
carry (electrical) charge through ignore throughout for through 1
the metal / sodium
ignore current / electricity
MP2 is dependent upon MP1
AO /
Spec. Ref.
07.6 (conducts electricity) 1 AO1
when liquid / molten 5.2.2.3
or
(conducts electricity) allow (conducts electricity)
in (aqueous) solution when dissolved in water
(because) ions 1
(ions) are free to move 1
or
(ions) allow charge to flow
Total Question 7 17
How to answer it
Elements and Compounds: Extraction, Redox, and Conductivity
Part (a): How is metal Y extracted from its compound?
✅ Correct answer
Electrolysis of a molten compound of metal Y.
Alternative accepted answer: displacement by heating with a more reactive metal , such as potassium or magnesium.
💡 Key knowledge
- Metal Y is above carbon in the reactivity series, so it cannot be extracted by reduction with carbon.
- More reactive metals are extracted by electrolysis.
- If a metal is extracted by displacement, a more reactive metal can reduce its compound.
- The mark scheme allows molten or liquid compound.
🧠 Exam technique
- Always link the method to the reactivity series.
- For full marks, name both the method and the condition: molten for electrolysis.
- If using displacement, name the more reactive metal used.
❌ Common errors
- Saying reduction with carbon when the metal is above carbon.
- Just writing electrolysis without saying the compound must be molten.
- Giving a vague answer like “heat it” without the method.
Part (b): Balance the equation
✅ Correct answer
4 Na + TiCl₄ → 4 NaCl + Ti
💡 Key knowledge
- This is a displacement reaction: sodium is more reactive than titanium.
- The chlorine atoms must balance on both sides: 4 chlorines in TiCl₄ means 4 NaCl on the product side.
- Titanium is left as the single element Ti.
🧠 Exam technique
- Check atoms one type at a time.
- Balance metals last if needed.
- Use whole-number coefficients only.
❌ Common errors
- Writing NaCl but forgetting to balance it to 4 NaCl.
- Putting TiCl₄ on the product side.
- Changing the formula of titanium chloride instead of balancing the equation.
Part (c): Show sodium is oxidised
✅ Correct answer
Na → Na⁺ + e⁻
💡 Key knowledge
- Oxidation means loss of electrons.
- Sodium atoms lose one electron to form sodium ions.
- State symbols are ignored here.
🧠 Exam technique
- Write the atom on the left and the ion on the right.
- Make sure the charge is correct: Na⁺.
- Only one electron is lost by sodium, so write e⁻ once.
❌ Common errors
- Writing Na + e⁻ → Na⁺ instead of showing oxidation.
- Forgetting the positive charge on the sodium ion.
- Balancing with extra electrons when only one is needed.
Part (d): Maximum mass of copper produced
🧠 Mark scheme insight
Students could score the calculation using moles, by using the mass ratio from the equation, or by converting masses through copper chloride first. The key distinctions for full marks were:
- Correctly converting 1.21 kg to 1210 g.
- Using the balanced equation 2 Al + 3 CuCl₂ → 3 Cu + 2 AlCl₃.
- Identifying the limiting reactant correctly.
- Giving the final answer as 381 g.
📐 Step-by-step method 1: moles
- Calculate moles of aluminium: 108 ÷ 27 = 4 mol
- Calculate moles of copper chloride: 1210 ÷ 134.5 = 8.996 mol
- Compare with the ratio in the equation: 2 Al reacts with 3 CuCl₂.
- For 4 mol Al, required CuCl₂ = 6 mol.
- Since 8.996 mol CuCl₂ is available, aluminium is the limiting reactant.
- From the equation, 2 Al → 3 Cu, so 4 mol Al gives 6 mol Cu.
- Mass of copper = 6 × 63.5 = 381 g
📐 Step-by-step method 2: mass ratio from the equation
- Find the reacting masses:
2 Al = 2 × 27 = 54 g
3 CuCl₂ = 3 × 134.5 = 403.5 g
3 Cu = 3 × 63.5 = 190.5 g - 108 g Al is twice 54 g, so it would react with 807 g CuCl₂ and produce 381 g Cu.
- Since there is 1210 g CuCl₂, there is excess copper chloride.
- Therefore, aluminium is the limiting reactant.
✅ Final answer
Limiting reactant: aluminium
Mass of copper: 381 g
❌ Common calculation traps
- Forgetting to convert 1.21 kg to 1210 g.
- Using the wrong ratio from the equation: it is 2 : 3 : 3 : 2 for Al : CuCl₂ : Cu : AlCl₃.
- Stating the limiting reactant without showing the comparison.
- Using the mass of CuCl₂ directly to find copper without checking the reactant ratio.
- Losing the final mark by not writing the answer with units: g.
Part (e): How does sodium metal conduct electricity?
✅ Correct answer
- Sodium metal has delocalised electrons.
- These electrons carry electrical charge through the metal.
💡 Key knowledge
- Metallic bonding contains positive ions in a sea of delocalised electrons.
- The electrons are free to move, so they transfer charge.
- Sodium metal conducts as a solid.
🧠 Exam technique
- Use the exact term delocalised electrons.
- Say they carry charge or transfer charge through the metal.
- You do not need to mention current unless you want to.
❌ Common errors
- Saying only “electrons move” without linking to charge.
- Talking about ions moving in metal — this is not the main reason metals conduct.
- Writing “free electrons” is usually accepted, but delocalised electrons is safer.
Part (f): Why does sodium chloride conduct electricity?
✅ Correct answer
Sodium chloride conducts electricity when molten or in aqueous solution because ions are free to move and carry charge.
💡 Key knowledge
- In solid sodium chloride, ions are fixed in place, so it does not conduct.
- When molten or dissolved in water, ions can move.
- Charge is carried by moving ions, not by electrons in the ionic compound.
🧠 Exam technique
- Always mention the correct condition: molten or aqueous.
- Then explain that ions are free to move.
- Finish by linking movement to charge flow or conducting electricity.
❌ Common errors
- Saying sodium chloride conducts when solid.
- Talking about delocalised electrons in sodium chloride — that applies to metals, not ionic compounds.
- Forgetting to explain why the ions matter.
Top-scoring response pattern
💡 What examiners wanted
- Correct scientific terms: electrolysis, molten, oxidised, delocalised electrons, ions, limiting reactant.
- Balanced equations and correct chemical formulas.
- Clear logic in calculations, showing how the answer is obtained.
🧠 How to secure marks quickly
- Use the reactivity series to choose extraction methods.
- Balance before calculating.
- State the limiting reactant before the final mass.
- Use units at every stage.
Topics
Chemistry · C1: Atomic Structure and the Periodic Table · C2: Bonding, Structure and the Properties of Matter · C3: Quantitative Chemistry · C4: Chemical Changes
Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Chemistry Paper 1 (Higher), 2022. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.