AQA GCSE Combined Science: Trilogy Chemistry Paper 2 (Higher), 2022: Question 3

12 marks · Standard Demand difficulty · Extended Answer

Answer questions about the rate of reaction between sodium thiosulfate and hydrochloric acid, including explaining mass loss, identifying variables, plotting data, calculating a tangent gradient, and explaining why rate decreases.

Practise this question

Question

The question page is a multi-part chemistry question about the reaction between sodium thiosulfate solution and hydrochloric acid, with the word equation shown symbolically as Na2S2O3(aq) + 2HCl(aq) → 2NaCl(aq) + H2O(l) + SO2(g) + S(s). Part 03.1 asks why the mass of the conical flask and contents was greater at the start than at the end. A labelled diagram in Figure 3 shows a conical flask standing on paper with a black cross beneath it, liquid inside the flask, labels to sodium thiosulfate solution and hydrochloric acid, and a timer display reading 0.43; a five-step method describes adding 50 cm3 sodium thiosulfate, placing the flask on the cross, adding 10 cm3 hydrochloric acid and starting the timer, stopping when the cross can no longer be seen, and repeating at different temperatures. Part 03.2 asks what type of variable time is, with tick boxes for control, dependent, and independent. Part 03.3 provides Table 1 with temperatures 19, 32, 45, 52, 63, and 73 degrees Celsius and corresponding times 82, 48, 43, 15, 7, and 3 seconds, and asks students to plot these data and draw a line of best fit on a blank graph of time in seconds against temperature in degrees Celsius. Part 03.4 shows Figure 5, a curved graph of time in seconds against concentration of sodium thiosulfate solution in mol/dm3 with a tangent drawn at 0.4 mol/dm3, and asks for the gradient and unit. Part 03.5 asks why the rate decreased during the reaction, specifically using an explanation in terms of particles.
Question text

03 This question is about the reaction between sodium thiosulfate solution and

hydrochloric acid.

The equation for the reaction is:

Na2S2O3(aq) + 2 HCl(aq) → 2 NaCl(aq) + H2O(l) + SO2(g) + S(s)

03.1 The mass of the conical flask and contents was greater at the start of the reaction

than at the end.

Explain why.

[2 marks]

A teacher demonstrated the reaction between sodium thiosulfate solution and

hydrochloric acid.

Figure 3 shows the experiment.

The experiment was done in a fume cupboard.

Figure 3

This is the method the teacher used.

1. Pour 50 cm3 of sodium thiosulfate solution into a conical flask.

2. Put the conical flask on a black cross drawn on a piece of paper.

3. Pour 10 cm3 of hydrochloric acid into the conical flask and start a timer.

4. Stop the timer when the cross can no longer be seen.

5. Repeat the experiment at different temperatures.

03.2 What type of variable is time in this reaction?

[1 mark]

Tick ( ) one box.

Control

Dependent

Independent 9

03.3 Table 1 shows the results.

Table 1

Temperature in °C Time in seconds

19 82

32 48

45 43

52 15

63 7

73 3

Complete Figure 4.

You should:

• plot the data from Table 1 on Figure 4

• draw a line of best fit.

[3 marks]

Figure 4

03.4 A student investigated the effect of concentration of sodium thiosulfate on the time

taken for the reaction at room temperature.

Figure 5 shows the results with a tangent drawn at 0.4 mol/dm3

Figure 5

Calculate the gradient (slope) of the tangent at 0.4 mol/dm3

Give the unit.

[4 marks]

Gradient =

Unit =

03.5 The student determined the rate of the reaction at regular time intervals during

an experiment.

Explain why the rate decreased during the reaction.

You should give your answer in terms of particles.

[2 marks]

Mark scheme

Show the mark scheme The mark scheme is laid out in tables for questions 03.1 to 03.5 with columns for answers, extra information, marks, and AO/specification references. For 03.1 it awards marks for stating that sulfur dioxide, or a gas, is produced and escapes from the conical flask; for 03.2 the answer is dependent; for 03.3 marks are for correctly plotting the points from the table and drawing a line of best fit. For 03.4 it gives marks for choosing correct x-step and y-step values from the tangent, dividing y-step by x-step to calculate the gradient, and giving the unit s dm3/mol, allowing follow-through from incorrect tangent readings. For 03.5 it awards marks for stating that as the reaction proceeds there are fewer sodium thiosulfate particles per unit volume, or concentration decreases, so the frequency or probability of collisions decreases.

Question 3

AO /

Question Answers Extra information Mark

Spec. Ref.

03.1 sulfur dioxide produced allow a gas is produced 1 AO3

(which) escapes from the 1 AO2

(conical) flask

5.2.2.2

RPA11

AO /

Spec. Ref.

03.2 dependent 1 AO2

5.6.1.2

AO /

Spec. Ref.

03.3 all points correctly plotted allow 1 mark for 3, 4 or 5 points 2 AO2

correctly plotted

allow a tolerance of ± ½ a small

square

line of best fit 1 AO3

5.6.1.1

AO /

Spec. Ref.

03.4 correct values for x step 1 AO2

and y step from tangent 5.6.1.1

RPA11

value for y step allow correct use of an 1

(rate =) incorrectly determined value

value for x step

from tangent for x step and/or y

step 11

correct calculation of rate 1

s dm3/mol 1

AO /

Spec. Ref.

03.5 (as reaction proceeds) fewer allow (as reaction proceeds) 1 AO2

(sodium thiosulfate) particles per concentration (of sodium 5.6.1.2

unit volume thiosulfate) decreases 5.6.1.3

RPA11

allow (so) probability of collision 1

(so) frequency of (particle) decreases

collisions decreases

Total Question 3 12

How to answer it

Sodium Thiosulfate Reaction Rates

AQA GCSE Combined Science: Trilogy

What this question tests

You need to explain a simple reaction observation, identify the correct type of variable, plot data accurately, calculate a gradient from a tangent, and explain rate changes using particle theory. Marks are awarded for correct science words, accurate graph skills, and clear working with units.

Question 03

Rates of reaction: sodium thiosulfate and hydrochloric acid

Reaction: Na₂S₂O₃(aq) + 2HCl(aq) → 2NaCl(aq) + H₂O(l) + SO₂(g) + S(s)

The question is about why the reaction mixture becomes cloudy and how rate changes with temperature and concentration.

03.1 Explain why the mass of the conical flask and contents was greater at the start of the reaction. [2]

✅ Correct answer

Sulfur dioxide gas is produced and it escapes from the conical flask.

2 marks: 1 for naming the gas, 1 for saying it leaves the flask.

💡 Key knowledge

  • The reaction makes a gas: SO₂.
  • Open/flask experiments can lose gas to the surroundings, so mass decreases during the reaction.
  • The equation shows a gas product, which helps you spot the answer.

🧠 Exam technique

  • State the gas name first.
  • Then say it escapes or is lost from the flask.
  • Use the equation if you forget: SO₂(g) .

❌ Common errors

  • Saying the flask is heavier because the reaction “creates more substance” — this does not explain the mass difference.
  • Writing only “gas is produced” may be allowed, but naming sulfur dioxide is stronger and safer.
  • Confusing sulfur dioxide with sulfur or sulfate.

03.2 What type of variable is time in this reaction? [1]

✅ Correct answer

Dependent variable

The time changes in response to the independent variable being tested.

💡 Key knowledge

  • Independent variable = temperature or concentration, because that is changed.
  • Dependent variable = time taken for the cross to disappear.
  • Control variables = things kept the same, e.g. volume of acid/thiosulfate.

🧠 Exam technique

Ask yourself: what is measured? That is usually the dependent variable.

❌ Common errors

  • Calling time “independent” because it is on the graph axis.
  • Mixing up dependent and control variables.

03.3 Plot the data from Table 1 and draw a line of best fit. [3]

✅ Correct answer

  • Plot all points correctly: (19, 82), (32, 48), (45, 43), (52, 15), (63, 7), (73, 3).
  • Draw a smooth line of best fit through the pattern of points.

Mark scheme: 2 marks for correct plotting, 1 mark for line of best fit.

💡 Key knowledge

  • Temperature is on the x-axis.
  • Time in seconds is on the y-axis.
  • The graph should show a decreasing curve: higher temperature gives shorter time.

🧠 Exam technique

  • Use the correct scale before plotting.
  • Plot with a small, neat cross or dot.
  • For a best-fit line, do not join dot-to-dot.
  • A curve is expected, not a straight line, because the data are not linear.

❌ Common errors

  • Swapping the axes.
  • Missing one or more points.
  • Drawing a line through every point with sharp corners.
  • Forgetting the units on axis labels.
Examiner insight: students lost marks mainly by inaccurate plotting or by drawing a join-the-dots line instead of a smooth best-fit curve.

03.4 Calculate the gradient of the tangent at 0.4 mol/dm³. Give the unit. [4]

📐 Calculations step-by-step

  1. Choose two clear points on the tangent, not on the curve. For example, points near (0.10, 15) and (0.60, 7) are consistent with the drawn tangent.
  2. Find the y step: 15 − 7 = 8 seconds
  3. Find the x step: 0.60 − 0.10 = 0.50 mol/dm³
  4. Calculate gradient: gradient = y step ÷ x step = 8 ÷ 0.50 = 16
  5. Write the unit: s dm³/mol

Gradient = 16

Unit = s dm³/mol

🧠 Exam technique

  • Use the tangent line, not the curve.
  • Show your working clearly: one mark is often for the method.
  • Always include the unit.
  • Use points far apart on the tangent to reduce error.

💡 Key knowledge

  • Gradient here means the rate of reaction.
  • Because the graph is time against concentration, the slope has units of seconds per concentration.
  • Use the same concentration units as the graph: mol/dm³.

❌ Common errors

  • Using two points on the curve instead of the tangent.
  • Forgetting to subtract correctly: x step and y step must be differences.
  • Giving the wrong unit, such as mol/dm³/s .
  • Leaving the answer unitless.
Examiner insight: full marks needed correct x and y steps from the tangent, then a correct calculation and unit. If a student used slightly different but sensible points from the tangent, this could still score marks.

03.5 Explain why the rate decreased during the reaction. Use particles. [2]

✅ Correct answer

As the reaction proceeds, there are fewer sodium thiosulfate particles per unit volume, so the frequency of collisions decreases.

1 mark for fewer particles / lower concentration, 1 mark for fewer collisions.

💡 Key knowledge

  • Reactants are used up during the reaction.
  • This lowers concentration, so particles are less crowded.
  • Fewer collisions per second means a slower rate.

🧠 Exam technique

  • Link your answer in a chain:
    fewer particles → fewer collisions → slower rate
  • Use the key word concentration if you remember it, but the answer must still mention collisions.

❌ Common errors

  • Saying the rate falls because “temperature decreases” — not stated in the question.
  • Saying there are “fewer particles” without linking to collision frequency.
  • Talking about products instead of reactant concentration.

Big-picture revision points from this question

💡 What to remember

  • SO₂ gas is produced in the reaction.
  • Time is a dependent variable.
  • Higher temperature gives a shorter time.
  • Rate can be found from the gradient of a tangent.
  • Rate decreases when concentration falls because collisions become less frequent.

🧠 How to score well

  • Use scientific vocabulary precisely.
  • Show graph and calculation working clearly.
  • Include units in every numerical answer.
  • For explanation questions, always link cause and effect.

Topics

Chemistry · Required Practicals · C6: The Rate and Extent of Chemical Change · Chemistry Required Practicals

Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Chemistry Paper 2 (Higher), 2022. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.