AQA GCSE Combined Science: Trilogy Physics Paper 1 (Higher), 2024: Question 5

10 marks · Standard Demand difficulty · Extended Answer

Explain the hazards of irradiated versus contaminated water from a radioactive revigator, identify the correct beta decay equation for vanadium-52, describe activity changes using half-life data, and name the process of checking scientific work before publication.

Practise this question

Question

The question page is labelled Question 05 and describes a historical water container called a revigator whose walls contain radioactive isotopes. A black-and-white photograph of a ceramic jug-like container is shown with labels pointing to the body as 'Revigator' and to a small spout as 'Tap'. Part 05.1 asks for a 4-mark explanation of how irradiating and contaminating the water affected the hazard caused by drinking it, with separate answer lines for 'Irradiating' and 'Contaminating'; part 05.2 asks for the correct nuclear equation for beta decay of vanadium-52 from four multiple-choice equations using isotope notation for vanadium, titanium, chromium and beta particles; part 05.3 provides a table of half-lives for radon-222 as 3.8 days and vanadium-52 as 3.7 minutes and asks for a 4-mark explanation of how their activities changed after 7.4 minutes; part 05.4 asks for the term used when other scientists check work before publication.
Question text

05 Some people used to think that radioactive substances had health benefits.

In the 1920s, a water container called a revigator was sold.

The walls of a revigator contain radioactive isotopes.

Figure 6 shows a revigator.

Figure 6

The revigator was filled with water and left overnight.

People then drank the water from the revigator.

05.1 The water was irradiated and contaminated by the radioactive isotopes in the walls of

the revigator.

Explain how irradiating and contaminating the water affected the hazard caused by

drinking the water.

[4 marks]

Irradiating

Contaminating

*18* A scientist tested some water that had been left in a revigator.

The water contained radon-222 and vanadium-52.

05.2 Vanadium-52 (V) decays by emitting beta particles.

What is the correct nuclear equation for this process?

[1 mark]

Tick ( ) one box.

05.3 Table 2 shows the half-lives of radon-222 and vanadium-52.

Table 2

Isotope Half-life

Radon-222 3.8 days

Vanadium-52 3.7 minutes

The scientist measured the radiation emitted by a sample of radon-222 and the

radiation emitted by a sample of vanadium-52.

The scientist repeated the measurements 7.4 minutes later.

Explain how the activity of the radon-222 and vanadium-52 had changed after

7.4 minutes.

[4 marks]

Radon-222

*20* Vanadium-52

05.4 Scientists monitored the effects of drinking the water from a revigator.

Their methods and results were checked by other scientists.

What name is given to the process of other scientists checking work before it

is published?

[1 mark]

Mark scheme

Show the mark scheme Mark scheme for AQA GCSE Combined Science: Trilogy Physics Paper 1 (Higher), 2024: Question 5

Question 5

AO /

Question Answers Extra information Mark

Spec. Ref.

05.1 allow risk for hazard throughout AO1

6.4.2.4

Irradiating

EITHER

radiation enters the water allow alpha / beta / gamma 1

enters the water

allow the water does not

become radioactive

(which) does not affect the dependent on MP1 1

hazard

OR

because radiation can kill allow named pathogens e.g.

pathogens (1) bacteria, viruses

(irradiating) decreases the dependent on MP1

hazard (1)

contaminating

because radioactive isotopes

will enter the water / body 1

(contaminating) increases the dependent on MP3 1

hazard

AO /

Spec. Ref.

05.2 1 AO2

– – – 6.4.2.2

AO /

Spec. Ref.

05.3 radon-222 AO3

activity remained (almost) the allow the radiation emitted (each 1 6.4.2.3

same second) decreased by a small

amount

because 7.4 minutes is only a allow 7.4 minutes is much 1

very small fraction of 3.8 days smaller than 3.8 days

allow the time is much less than

the half-life

vanadium-52

activity decreased by a factor of 1

because 2 half-lives had passed 1

AO /

Spec. Ref.

05.4 peer review 1 AO1

6.4.2.4

Total Question 5 10

How to answer it

Revigator: radiation, half-life and peer review

What this question tests

You need to understand the difference between irradiation and contamination, write a correct beta decay nuclear equation, compare changes in activity using half-life, and know the meaning of peer review. Full marks come from using the right radioactive vocabulary and linking each idea to how the hazard changes.

Question 05

Radioactive revigator water

Context

A revigator had radioactive isotopes in its walls. Water was left in it overnight, then people drank the water. The question checks whether you can distinguish between being near radiation and being made radioactive.

Part (a) / 05.1 — Irradiating and contaminating the water

✅ Correct answers

  • Irradiating: radiation enters the water, so the water is exposed to radiation.
  • This does not make the water radioactive, so it does not increase the hazard in the same way as contamination.
  • Contaminating: radioactive isotopes enter the water / the body.
  • This increases the hazard because the source is now inside the water you drink.

💡 Key knowledge

  • Irradiation means exposure to radiation from a source.
  • Contamination means radioactive material gets onto or into something.
  • In this question, the revigator walls contain the radioactive source, so the water can be irradiated without becoming radioactive.
  • If radioactive atoms get into the water, then the water is contaminated and the hazard is greater.

🧠 Exam technique

  • Use the command word: Explain means give a reason, not just a definition.
  • To score both marks, link the idea to hazard.
  • Good wording: “radiation enters the water, but the water does not become radioactive”.
  • For contamination, mention that radioactive isotopes enter the water or body.

❌ Common errors

  • Writing that irradiation and contamination mean the same thing.
  • Saying irradiation “makes the water radioactive” — this is wrong.
  • Not mentioning the effect on hazard.
  • Using vague phrases like “it gets dangerous” without explaining why.
How marks were awarded: 1 mark for the irradiation idea and 1 mark for the hazard link, then 1 mark for the contamination idea and 1 mark for the hazard increase.

Part (b) / 05.2 — Nuclear equation for beta decay

✅ Correct answer

²³₅ V → ²⁴₂ Cr + ⁰₋₁ β

This is the correct option because beta decay increases the atomic number by 1, but the mass number stays the same.

💡 Key knowledge

  • A beta particle is written as ⁰₋₁ β .
  • In beta decay, a neutron changes into a proton.
  • That means:
    • mass number stays the same,
    • atomic number increases by 1.
  • So vanadium-52 becomes chromium-52.

🧠 Exam technique

  • Check both sides of the equation balance.
  • Mass numbers must add up: 52 = 52 + 0.
  • Atomic numbers must add up: 23 = 24 + (−1).
  • If you are unsure, remember: beta minus = atomic number +1.

❌ Common errors

  • Changing the mass number to 51 or 53.
  • Using the wrong daughter nucleus, such as titanium or potassium.
  • Forgetting the beta particle is on the product side.
  • Mixing up alpha and beta decay rules.

Part (c) / 05.3 — Comparing activity after 7.4 minutes

📐 Calculations / reasoning

Step 1: Compare the time passed with each half-life.

  • Radon-222 half-life = 3.8 days
  • Vanadium-52 half-life = 3.7 minutes
  • Time elapsed = 7.4 minutes

Step 2: Decide how many half-lives have passed.

  • For radon-222, 7.4 minutes is a very small fraction of 3.8 days, so activity is almost unchanged.
  • For vanadium-52, 7.4 minutes is exactly 2 half-lives because 7.4 ÷ 3.7 = 2.

Step 3: State the effect on activity.

  • Radon-222 activity remains almost the same.
  • Vanadium-52 activity decreases by a factor of 4.

✅ Correct answers

  • Radon-222: activity remained (almost) the same because 7.4 minutes is much smaller than 3.8 days.
  • Vanadium-52: activity decreased by a factor of 4 because 2 half-lives had passed.

💡 Key knowledge

  • After 1 half-life, activity halves.
  • After 2 half-lives, activity becomes one quarter.
  • When the time is tiny compared with the half-life, the activity changes very little.

🧠 Exam technique

  • Always compare the time with the half-life before deciding the change.
  • Use “factor of 4” rather than “decreases a lot” for full credit.
  • Make the link: time passed → number of half-lives → change in activity.

❌ Common errors

  • Saying radon-222 changes a lot just because any time has passed.
  • Missing that 7.4 minutes is tiny compared with 3.8 days.
  • For vanadium-52, saying the activity halves instead of quartering.
  • Forgetting that 2 half-lives means the activity is divided by 2 twice.
Examiner insight: Top answers named the isotope first, then gave the correct activity change, then explained it using the half-life comparison.

Part (d) / 05.4 — Checking work before publication

✅ Correct answer

Peer review

💡 Key knowledge

  • Peer review means other scientists check the methods, data, and conclusions before publication.
  • It helps spot mistakes and improve reliability.

🧠 Exam technique

  • For 1 mark, the exact term is enough: peer review.
  • Do not write vague answers like “testing” or “checking” on their own.

One-line memory summary

  • Irradiation = exposed to radiation; contamination = radioactive material gets into the water/body.
  • Beta decay keeps the mass number the same and increases atomic number by 1.
  • If time is much less than the half-life, activity changes very little.
  • Peer review = other scientists check the work before it is published.

Topics

Physics · P4: Atomic Structure

Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Physics Paper 1 (Higher), 2024. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.