AQA GCSE Combined Science: Trilogy Physics Paper 1 (Higher), June 2025: Question 4

14 marks · Standard Demand difficulty · Short Answer

Describe nuclear radiations, complete a beta decay equation, determine half-life and percentage activity decrease from a decay curve, and explain its medical use in cancer treatment.

Practise this question

Question

Question 4 consists of six parts: 04.1 asks to describe alpha particles, beta particles, and gamma rays; 04.2 asks to complete a nuclear equation for gold-198 decaying into mercury by beta emission; Figure 4 displays a decay curve of Activity in kBq against Time in days, starting at 22 kBq at day 0; 04.3 asks to determine the half-life from the graph; 04.4 asks to calculate the percentage decrease in activity at 5 days to 2 significant figures; 04.5 asks for two reasons why gold-198 is implanted near cancer cells; and 04.6 asks why the sample is not removed after treatment.
Question text

04 Three types of radiation emitted by unstable nuclei are:

• alpha particle

• beta particle

• gamma ray.

04.1 Describe each type of radiation.

[3 marks]

Alpha particle

Beta particle

Gamma ray

04.2 The radioactive isotope gold-198 (Au) decays to mercury (Hg) by emitting

beta radiation.

Complete the nuclear equation for the decay of gold-198.

[2 marks]

Gold-198 is used in the treatment of cancer.

A small sample containing gold-198 is surgically implanted into a patient, very near to

the cancer cells.

Figure 4 shows how the activity of the sample changes after it has been implanted.

Figure 4

04.3 Determine the half-life of gold-198.

[2 marks]

15 Half-life = days

04.4 Determine the percentage decrease in the activity at 5 days.

Give your answer to 2 significant figures.

*14* [4 marks]

Percentage decrease (2 significant figures) = %

04.5 The sample containing gold-198 is implanted very near to the cancer cells.

Give two reasons why.

[2 marks]

04.6 After treatment, the sample containing gold-198 is not removed from the patient.

Suggest why the sample is left in the patient and not removed.

[1 mark]

Mark scheme

Show the mark scheme Mark scheme for Question 4: 04.1 awards 1 mark each for describing alpha (two protons and two neutrons/helium nucleus), beta (high-speed electron from nucleus), and gamma (high-frequency EM wave/radiation); 04.2 gives 1 mark for top row numbers 198 and 0, and 1 mark for bottom row 80 and -1; 04.3 awards 2 marks for 2.75 days (allow 2.7 to 2.8); 04.4 awards up to 4 marks for reading activity at 5 days (6.0 kBq), calculating percentage decrease ((22-6)/22 * 100), getting 72.7%, and rounding to 73%; 04.5 awards 2 marks for points including short range, killing cancer cells, and reduced damage to healthy cells; 04.6 gives 1 mark for the risk of removal being greater than leaving it or activity quickly falls to a safe level.

Question 4

AO /

Question Answers Extra information Mark

Spec. Ref.

04.1 alpha particle AO1

6.4.2.1

(a particle consisting of) two allow helium nucleus 1

neutrons and two protons (from

the nucleus)

beta particle

(a high-speed) electron (from 1

the nucleus)

gamma ray

(a high frequency / energy) 1

electromagnetic wave / radiation

(from the nucleus)

AO /

Spec. Ref.

04.2 198 0 1 mark for the top row 1 AO1

6.4.2.2

80 –1 1 mark for the bottom row 1

AO /

Spec. Ref.

04.3 2.75 (days) allow 2.7 to 2.8 2 AO2

allow an answer consistent with 6.4.2.3

a correct pair of values for

activity

allow 1 mark for a horizontal line

– drawn from 11 – 8464/P/1H –

AO /

Spec. Ref.

04.4 activity = 6.0 (kBq) subsequent marks may be 1 AO3

awarded if an activity of 7.0

(kBq) is used

22 – 6.0 1 AO2

×100

72.7…(%) 1 AO2

73 (%) allow a percentage calculated 1 AO2

using data from the graph given

to two significant figures

6.4.2.3

AO /

Spec. Ref.

04.5 Any two from: 2 AO3

6.4.2.1

• beta only has a short range

(in tissue)

• increases the chance of

killing the cancer cells

• decreases the risk to healthy

cells

AO /

Spec. Ref.

04.6 the risk of removing the sample allow the risk of leaving the 1 AO3

is greater than the risk of leaving sample in the patient is very 6.4.2.1

the sample in the patient small 6.4.2.4

or

the activity will reduce to a safe

level in a short time

Total Question 4 14

How to answer it

Types of Radiation, Decay Equations & Half-Life Analysis

What this question tests

This question assesses fundamental knowledge of nuclear physics (AQA Specification 6.4.2): the physical nature of alpha, beta, and gamma radiation; balancing nuclear decay equations; extracting half-life values and reading quantities accurately from decay curves; calculating percentage change to a specified number of significant figures; and evaluating the medical risks and benefits of internal radiotherapy implants.

Question 04.1

Describing Types of Nuclear Radiation

3 Marks • AO1 (Knowledge & Recall)

✅ Model Answer

  • Alpha particle: Consists of two protons and two neutrons (or a helium nucleus). [1 mark]
  • Beta particle: A fast-moving / high-speed electron (emitted from the nucleus). [1 mark]
  • Gamma ray: A high-energy / high-frequency electromagnetic wave (or electromagnetic radiation). [1 mark]

💡 Key Scientific Facts

  • Alpha (α) is identical to a Helium-4 nucleus (⁴₂He).
  • Beta (β) is formed when a neutron in an unstable nucleus turns into a proton and an electron; the electron is ejected at high speed.
  • Gamma (γ) has no mass and no charge; it is an electromagnetic wave from the top end of the EM spectrum.

❌ Common Traps

  • Beta: Saying "an orbital electron" or "an electron from an outer shell". Beta particles come strictly from inside the nucleus.
  • Alpha: Stating "a helium atom" instead of "a helium nucleus" (atoms include electrons; alpha particles have no electrons).
Question 04.2

Completing a Beta Decay Equation

2 Marks • AO1 / AO2 (Application)

¹⁹⁸₇₉Au → ¹⁹⁸₈₀ Hg + ⁰₋₁ β

✅ Correct Values

  • Top row (mass numbers): 198 for Hg and 0 for β [1 mark]
  • Bottom row (atomic numbers): 80 for Hg and -1 for β [1 mark]

🧠 Conservation Law Method

Total Mass Number and Total Atomic Number must balance across the arrow:

  • Top: 198 = 198 + 0 ✓
  • Bottom: 79 = 80 + (-1) ✓

❌ Common Error

Writing the atomic number of Hg as 78 instead of 80 . Remember, a neutron becomes a proton, so the atomic number increases by 1!

Question 04.3

Determining Half-Life from a Decay Curve

2 Marks • AO2 (Data Analysis)

🔧 Step-by-Step Graphical Working

  1. Find initial activity: At time = 0 days, Activity = 22 kBq .
  2. Halve the initial activity: 22 ÷ 2 = 11 kBq .
  3. Read from the graph: Draw a horizontal line from 11 kBq to the decay curve, then drop straight down to the time axis.
  4. Value: Reads exactly at 2.75 days (acceptable range: 2.7 to 2.8 days).

✅ Mark Allocation

  • 1 mark: Showing evidence of halving the activity (e.g. a horizontal construction line drawn from 11 kBq across to the curve).
  • 1 mark: Final answer in range 2.75 days (allow 2.7 – 2.8).

🧠 Examiner Tip

Always draw your construction lines clearly on the exam graph with a ruler. If your final reading has a slight misread, you can still secure the method mark if examiners see your line drawn from 11 kBq!

Question 04.4

Percentage Decrease in Activity

4 Marks • AO2 / AO3 (Complex Calculation)

🔧 Step-by-Step Calculation

  1. Step 1: Read activity at 5 days from graph:
    At t = 5 days, Activity = 6.0 kBq (allow 7.0 kBq). [1 mark]
  2. Step 2: Find decrease in activity:
    Initial = 22 kBq, New = 6.0 kBq
    Decrease = 22 − 6.0 = 16.0 kBq .
  3. Step 3: Calculate percentage decrease:
    Formula: (Decrease ÷ Original) × 100
    (22 − 6.0) ÷ 22 × 100 [1 mark]
    = 16 ÷ 22 × 100 = 72.7272...% [1 mark]
  4. Step 4: Round to 2 significant figures:
    72.72...% rounds to 73%. [1 mark]
    (Note: If 7.0 kBq was read, (15/22)×100 = 68.18...% → 68%)

❌ Pitfalls to Avoid

  • Calculating remaining percentage instead of decrease: Doing (6.0 ÷ 22) × 100 = 27% gives the percentage remaining, not the percentage decrease.
  • Ignoring Significant Figures: Leaving the answer as 72.7% loses the final mark. The question explicitly states: "Give your answer to 2 significant figures".
  • Wrong denominator: Always divide by the original value (22), never the new value (6.0).
Question 04.5

Reasons for Implanting Close to Tumours

2 Marks • AO3 (Contextual Understanding)

✅ Model Answer (Any TWO)

  • Beta radiation has a short range in human tissue (a few millimetres to centimetres). [1 mark]
  • It increases the chance of destroying/killing the cancer cells. [1 mark]
  • It minimises/decreases radiation damage to surrounding healthy cells. [1 mark]

🧠 Exam Technique: The "Dual Benefit"

In radiotherapy questions, top students always link the properties of the radiation to two contrasting impacts:

  • Maximising harm to the target (cancer cells).
  • Minimising harm to the surroundings (healthy tissue).
Question 04.6

Why the Implant is Left in the Patient

1 Mark • AO3 (Risk vs. Benefit Evaluation)

✅ Accepted Marking Points (Any ONE)

  • The risk (or trauma) of a second surgical procedure to remove the sample is greater than the risk of leaving it inside. [1 mark]
  • The activity will quickly decrease to a safe/negligible level due to its short half-life (~2.8 days). [1 mark]
  • Also allowed: The risk of leaving the sample in the patient is very small.

💡 Connecting the Half-Life

With a half-life of roughly 2.75 days, after about a month (around 10 half-lives), the activity of Gold-198 drops to less than 0.1% of its starting level, rendering it virtually harmless without requiring invasive surgery.

Topics

Physics · P4: Atomic Structure

Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Physics Paper 1 (Higher), June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.