AQA GCSE Combined Science: Trilogy Physics Paper 1 (Higher), June 2025: Question 4
14 marks · Standard Demand difficulty · Short Answer
Describe nuclear radiations, complete a beta decay equation, determine half-life and percentage activity decrease from a decay curve, and explain its medical use in cancer treatment.
Practise this questionQuestion
Question text
04 Three types of radiation emitted by unstable nuclei are:
• alpha particle
• beta particle
• gamma ray.
04.1 Describe each type of radiation.
[3 marks]
Alpha particle
Beta particle
Gamma ray
04.2 The radioactive isotope gold-198 (Au) decays to mercury (Hg) by emitting
beta radiation.
Complete the nuclear equation for the decay of gold-198.
[2 marks]
Gold-198 is used in the treatment of cancer.
A small sample containing gold-198 is surgically implanted into a patient, very near to
the cancer cells.
Figure 4 shows how the activity of the sample changes after it has been implanted.
Figure 4
04.3 Determine the half-life of gold-198.
[2 marks]
15 Half-life = days
04.4 Determine the percentage decrease in the activity at 5 days.
Give your answer to 2 significant figures.
*14* [4 marks]
Percentage decrease (2 significant figures) = %
04.5 The sample containing gold-198 is implanted very near to the cancer cells.
Give two reasons why.
[2 marks]
04.6 After treatment, the sample containing gold-198 is not removed from the patient.
Suggest why the sample is left in the patient and not removed.
[1 mark]
Mark scheme
Show the mark scheme
Question 4
AO /
Question Answers Extra information Mark
Spec. Ref.
04.1 alpha particle AO1
6.4.2.1
(a particle consisting of) two allow helium nucleus 1
neutrons and two protons (from
the nucleus)
beta particle
(a high-speed) electron (from 1
the nucleus)
gamma ray
(a high frequency / energy) 1
electromagnetic wave / radiation
(from the nucleus)
AO /
Spec. Ref.
04.2 198 0 1 mark for the top row 1 AO1
6.4.2.2
80 –1 1 mark for the bottom row 1
AO /
Spec. Ref.
04.3 2.75 (days) allow 2.7 to 2.8 2 AO2
allow an answer consistent with 6.4.2.3
a correct pair of values for
activity
allow 1 mark for a horizontal line
– drawn from 11 – 8464/P/1H –
AO /
Spec. Ref.
04.4 activity = 6.0 (kBq) subsequent marks may be 1 AO3
awarded if an activity of 7.0
(kBq) is used
22 – 6.0 1 AO2
×100
72.7…(%) 1 AO2
73 (%) allow a percentage calculated 1 AO2
using data from the graph given
to two significant figures
6.4.2.3
AO /
Spec. Ref.
04.5 Any two from: 2 AO3
6.4.2.1
• beta only has a short range
(in tissue)
• increases the chance of
killing the cancer cells
• decreases the risk to healthy
cells
AO /
Spec. Ref.
04.6 the risk of removing the sample allow the risk of leaving the 1 AO3
is greater than the risk of leaving sample in the patient is very 6.4.2.1
the sample in the patient small 6.4.2.4
or
the activity will reduce to a safe
level in a short time
Total Question 4 14
How to answer it
Types of Radiation, Decay Equations & Half-Life Analysis
This question assesses fundamental knowledge of nuclear physics (AQA Specification 6.4.2): the physical nature of alpha, beta, and gamma radiation; balancing nuclear decay equations; extracting half-life values and reading quantities accurately from decay curves; calculating percentage change to a specified number of significant figures; and evaluating the medical risks and benefits of internal radiotherapy implants.
Describing Types of Nuclear Radiation
3 Marks • AO1 (Knowledge & Recall)
✅ Model Answer
- Alpha particle: Consists of two protons and two neutrons (or a helium nucleus). [1 mark]
- Beta particle: A fast-moving / high-speed electron (emitted from the nucleus). [1 mark]
- Gamma ray: A high-energy / high-frequency electromagnetic wave (or electromagnetic radiation). [1 mark]
💡 Key Scientific Facts
- Alpha (α) is identical to a Helium-4 nucleus (⁴₂He).
- Beta (β) is formed when a neutron in an unstable nucleus turns into a proton and an electron; the electron is ejected at high speed.
- Gamma (γ) has no mass and no charge; it is an electromagnetic wave from the top end of the EM spectrum.
❌ Common Traps
- Beta: Saying "an orbital electron" or "an electron from an outer shell". Beta particles come strictly from inside the nucleus.
- Alpha: Stating "a helium atom" instead of "a helium nucleus" (atoms include electrons; alpha particles have no electrons).
Completing a Beta Decay Equation
2 Marks • AO1 / AO2 (Application)
✅ Correct Values
- Top row (mass numbers): 198 for Hg and 0 for β [1 mark]
- Bottom row (atomic numbers): 80 for Hg and -1 for β [1 mark]
🧠 Conservation Law Method
Total Mass Number and Total Atomic Number must balance across the arrow:
- Top: 198 = 198 + 0 ✓
- Bottom: 79 = 80 + (-1) ✓
❌ Common Error
Writing the atomic number of Hg as 78 instead of 80 . Remember, a neutron becomes a proton, so the atomic number increases by 1!
Determining Half-Life from a Decay Curve
2 Marks • AO2 (Data Analysis)
🔧 Step-by-Step Graphical Working
- Find initial activity: At time = 0 days, Activity = 22 kBq .
- Halve the initial activity: 22 ÷ 2 = 11 kBq .
- Read from the graph: Draw a horizontal line from 11 kBq to the decay curve, then drop straight down to the time axis.
- Value: Reads exactly at 2.75 days (acceptable range: 2.7 to 2.8 days).
✅ Mark Allocation
- 1 mark: Showing evidence of halving the activity (e.g. a horizontal construction line drawn from 11 kBq across to the curve).
- 1 mark: Final answer in range 2.75 days (allow 2.7 – 2.8).
🧠 Examiner Tip
Always draw your construction lines clearly on the exam graph with a ruler. If your final reading has a slight misread, you can still secure the method mark if examiners see your line drawn from 11 kBq!
Percentage Decrease in Activity
4 Marks • AO2 / AO3 (Complex Calculation)
🔧 Step-by-Step Calculation
- Step 1: Read activity at 5 days from graph:
At t = 5 days, Activity = 6.0 kBq (allow 7.0 kBq). [1 mark] - Step 2: Find decrease in activity:
Initial = 22 kBq, New = 6.0 kBq
Decrease = 22 − 6.0 = 16.0 kBq . - Step 3: Calculate percentage decrease:
Formula: (Decrease ÷ Original) × 100
(22 − 6.0) ÷ 22 × 100 [1 mark]
= 16 ÷ 22 × 100 = 72.7272...% [1 mark] - Step 4: Round to 2 significant figures:
72.72...% rounds to 73%. [1 mark]
(Note: If 7.0 kBq was read, (15/22)×100 = 68.18...% → 68%)
❌ Pitfalls to Avoid
- Calculating remaining percentage instead of decrease: Doing (6.0 ÷ 22) × 100 = 27% gives the percentage remaining, not the percentage decrease.
- Ignoring Significant Figures: Leaving the answer as 72.7% loses the final mark. The question explicitly states: "Give your answer to 2 significant figures".
- Wrong denominator: Always divide by the original value (22), never the new value (6.0).
Reasons for Implanting Close to Tumours
2 Marks • AO3 (Contextual Understanding)
✅ Model Answer (Any TWO)
- Beta radiation has a short range in human tissue (a few millimetres to centimetres). [1 mark]
- It increases the chance of destroying/killing the cancer cells. [1 mark]
- It minimises/decreases radiation damage to surrounding healthy cells. [1 mark]
🧠 Exam Technique: The "Dual Benefit"
In radiotherapy questions, top students always link the properties of the radiation to two contrasting impacts:
- Maximising harm to the target (cancer cells).
- Minimising harm to the surroundings (healthy tissue).
Why the Implant is Left in the Patient
1 Mark • AO3 (Risk vs. Benefit Evaluation)
✅ Accepted Marking Points (Any ONE)
- The risk (or trauma) of a second surgical procedure to remove the sample is greater than the risk of leaving it inside. [1 mark]
- The activity will quickly decrease to a safe/negligible level due to its short half-life (~2.8 days). [1 mark]
- Also allowed: The risk of leaving the sample in the patient is very small.
💡 Connecting the Half-Life
With a half-life of roughly 2.75 days, after about a month (around 10 half-lives), the activity of Gold-198 drops to less than 0.1% of its starting level, rendering it virtually harmless without requiring invasive surgery.
Topics
Physics · P4: Atomic Structure
Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Physics Paper 1 (Higher), June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.