AQA GCSE Combined Science: Trilogy Physics Paper 1 (Higher), June 2025: Question 5

14 marks · Standard Demand difficulty · Short Answer

State properties of mains electricity and the colour codes of wires, explain the effect of laptop use on charging time, and calculate the time taken to charge the battery while in use.

Practise this question

Question

Question 5 shows Figure 5, illustrating a laptop computer and a charger plugged into a mains wall socket via a cable. Part 05.1 asks for the potential difference and frequency of the UK mains electricity supply. Part 05.2 states the charger cable has two wires and no earth wire, asking to name each wire and their insulation colours. Part 05.3 asks for the difference between alternating and direct potential difference. Part 05.4 asks to explain why the laptop takes longer to charge when in use. Part 05.5 provides data: laptop circuit potential difference of 15 V, average current of 4.8 A, charger power of 97 W, and battery storage capacity of 225 kJ, asking to calculate the time to fully charge the battery in hours.
Question text

05 Figure 5 shows a laptop computer, and a charger plugged into the mains supply.

Figure 5

05.1 Give the potential difference and frequency of the UK mains electricity supply.

[2 marks]

Potential difference V

Frequency Hz

05.2 The cable that connects the charger to the plug contains two wires that have

coloured insulation.

The cable does not contain an earth wire.

Name each wire in the cable.

Give the colour of the insulation covering each wire.

[2 marks]

Name of wire Colour of insulation

Name of wire 17 Colour of insulation

05.3 The input to the charger is an alternating potential difference.

The output from the charger is a direct potential difference.

Describe the difference between an alternating potential difference and a direct

potential difference.

[2 marks]

A student is using the laptop computer.

The student notices that the battery has no stored energy.

The student quickly plugs the charger into the laptop and continues to use the laptop.

05.4 The laptop charger provides a constant power to the laptop.

The laptop takes longer to charge when the student uses the laptop than when the

laptop is not used.

Explain why.

[2 marks]

05.5 The potential difference across the laptop circuit is 15 V.

The average current in the laptop circuit when it is being used is 4.8 A.

The laptop charger provides a constant power of 97 W.

The maximum energy that the battery can store is 225 kJ.

Calculate the time taken to fully charge the battery from zero when the laptop is

used continuously.

*17*Use the Physics Equations Sheet.

Give your answer in hours.

[6 marks]

Time = hours

Mark scheme

Show the mark scheme Mark scheme for Question 5. 05.1: 230 V (1 mark) and 50 Hz (1 mark). 05.2: live – brown (1 mark), neutral – blue (1 mark). 05.3: alternating continuously changes direction (1 mark), direct is always in the same direction (1 mark). 05.4: energy/power is transferred by the laptop when used (1 mark), so power delivered to the battery is reduced (1 mark). 05.5: P = 15 x 4.8 = 72 W (2 marks), useful power = 97 - 72 = 25 W (1 mark), 25 = 225,000 / t (1 mark), t = 9000 s (1 mark), t = 2.5 hours (1 mark). Total 14 marks.

Question 5

AO /

Question Answers Extra information Mark

Spec. Ref.

05.1 230 (V) allow about 230 (V) 1 AO1

6.2.3.1

50 (Hz) 1

AO /

Spec. Ref.

05.2 live – brown 1 AO1

6.2.3.2

neutral – blue 1

AO /

Spec. Ref.

05.3 alternating (potential difference) 1 AO1

continuously changes direction 6.2.3.1

direct (potential difference) is 1

always in the same direction

AO /

Spec. Ref.

05.4 energy / power is transferred by 1 AO2

the laptop (when being used)

(so) the power delivered to the allow (so) the rate at which 1 AO3

battery is reduced energy is transferred to the

battery is lower

6.1.1.4

– – 8464/P/1H – 6.1.2.1

AO /

Spec. Ref.

05.5 P = 15 × 4.8 1 AO2

6.2.4.1

P = 72 (W) 1 6.2.4.2

6.1.1.4

ΔP = 97 – 72 = 25 (W) 1

225 000 subsequent marks may be 1

25 = awarded if an incorrect / not

t

converted value of E is used.

t = 9000 (s) 1

t = 2.5 (hours) 1

Total Question 5 14

How to answer it

AQA GCSE Physics: Mains Electricity & Power Calculation

WHAT THIS QUESTION TESTS

This question assesses core recall and application skills from Topic 2: Electricity:

  • Recall of standard UK mains potential difference ( 230 V ) and frequency ( 50 Hz ).
  • Wire colours and names in a two-core cable ( live = brown , neutral = blue ).
  • The clear physical distinction between alternating (a.c.) and direct (d.c.) potential difference.
  • Qualitative reasoning around energy conservation, power diversion, and charging rates.
  • A multi-step 6-mark calculation linking P = V × I , net power, energy conversion ( kJ to J ), and time conversion ( seconds to hours ).
Question 05.1

UK Mains Electricity Supply Values

Recall of standard voltage and frequency values [2 Marks]

✅ Correct Answers

  • Potential difference: 230 V (allow "about 230") [1 mark]
  • Frequency: 50 Hz [1 mark]
Total: 2 marks (AO1 Recall)

💡 Key Knowledge

  • UK domestic electricity is supplied as alternating current (a.c.).
  • Units are already provided in this question ( V and Hz ), but you must remember them when writing numerical answers from scratch.

❌ Common Errors

  • Writing US values (e.g., 110 V or 60 Hz).
  • Swapping the numbers around (e.g., writing 50 V and 230 Hz).

🧠 Exam Technique

These two numbers are purely recall facts from the specification. Make sure they are committed to memory before entering the exam.

Question 05.2

Two-Core Cable Wire Identification

Names and colours of insulation in a two-wire cable [2 Marks]

✅ Correct Answers

  • live – brown [1 mark]
  • neutral – blue [1 mark]
Total: 2 marks (AO1 Recall)

💡 Key Knowledge

Standard UK 3-core plug wiring colours:

  • Live wire (Brown) – Carries alternating potential difference from the supply (~230 V).
  • Neutral wire (Blue) – Completes the circuit (at or near 0 V).
  • Earth wire (Green/yellow stripes) – Safety wire; not present here because the charger is double-insulated.

🧠 Exam Technique & Memory Hook

  • bLue goes to the Left (Neutral).
  • bRown goes to the Right (Live).
  • Striped goes to the Top (Earth).

❌ Common Errors

  • Naming the earth wire despite the question explicitly stating: "The cable does not contain an earth wire."
  • Mismatched pairings (e.g., writing live – blue).
Question 05.3

Alternating vs Direct Potential Difference

Describing directional behaviour of a.c. and d.c. [2 Marks]

✅ Correct Answers

  • Alternating: continuously changes direction [1 mark]
  • Direct: always remains in the same direction (one direction only) [1 mark]
Total: 2 marks (AO1 Recall & Description)

❌ Common Errors

  • Vague terms like "a.c. moves up and down" or "d.c. is a straight flat line" without mentioning direction.
  • Confusing direction with magnitude (e.g., saying "d.c. stays at the same voltage"). Even if d.c. fluctuates in size, it is still direct if it does not change direction.

🧠 Examiner Commentary

Always use the word direction. Mentioning that alternating current/p.d. reverses or alternates continuously, whereas direct current/p.d. flows/acts in one direction only, gets full marks every time.

Question 05.4

Charging Rate While in Use

Explaining power division and charging times [2 Marks]

✅ Correct Answers

  • Energy or power is transferred / used by the laptop screen and components (when in use) [1 mark]
  • Therefore, the power delivered to the battery is reduced / the rate of energy transfer to the battery is lower [1 mark]
Total: 2 marks (AO2 Application / AO3 Analysis)

🧠 Exam Technique: Power Sharing

Think of charger power as a fixed flow of water:

  • Total Power = Power to run laptop + Power to charge battery
  • If total power is fixed, any power consumed by the running laptop directly subtracts from the rate of energy entering the battery.

❌ Common Errors

Simply stating "the laptop is on so it takes longer" just repeats the question stem without explaining the split in energy transfer or reduced power to the battery.

Question 05.5

Full Charging Time Calculation

Multi-step calculation involving power, energy, and unit conversions [6 Marks]

📐 Step-by-Step Calculation

  1. Calculate the power used by the laptop:
    Formula: P = V × I
    P = 15 V × 4.8 A = 72 W
    [2 marks awarded: 1 for working, 1 for 72 W]
  2. Calculate the net power available to charge the battery:
    Charger supplies 97 W; laptop uses 72 W.
    ΔP = 97 - 72 = 25 W
    [1 mark awarded]
  3. Convert battery energy capacity to standard SI units (Joules):
    E = 225 kJ = 225 × 1000 = 225 000 J
  4. Substitute into power-energy equation:
    Formula: Power = Energy ÷ time → 25 = 225 000 / t
    [1 mark awarded]
  5. Calculate time in seconds:
    t = 225 000 / 25 = 9 000 s
    [1 mark awarded]
  6. Convert seconds into hours:
    1 hour = 60 × 60 = 3600 seconds.
    t = 9 000 ÷ 3 600 = 2.5 hours
    [1 mark awarded]

❌ Common Calculation Traps

  • Trap 1 (Unit conversion): Forgetting to multiply 225 kJ by 1000 to get Joules.
  • Trap 2 (Time conversion): Dividing by 60 instead of 3600 (converting to minutes instead of hours).
  • Trap 3 (Wrong power): Using 97 W or 72 W in the time equation instead of finding the difference ( 25 W ).

🧠 Examiner Commentary

This is an extended 6-mark calculation that rewards structured, tidy working. Even if an arithmetic error occurs mid-way, error-carried-forward (ecf) marks can be awarded if your formula substitutions and conversion steps are clear.

Topics

Physics · P1: Energy · P2: Electricity

Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Physics Paper 1 (Higher), June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.