AQA GCSE Mathematics Paper 1 (Higher), June 2025: Question 12
3 marks · Medium difficulty · Multi-step Problem
Calculate the total amount of money shared between Oscar and Nikita in the ratio 8 : 5 given that Oscar receives £27 more than Nikita.
Practise this questionQuestion
Question text
12 Oscar and Nikita share some money in the ratio 8 : 5
Oscar has £27 more than Nikita.
How much do they have altogether?
[3 marks]
Mark scheme
Show the mark scheme
Q Answer Mark Comments
Alternative method 1: works out the value of one share
27 ÷ (8 – 5) or 27 ÷ 3 or 9 oe
M1
implied by 72 or 45 identified or used
their 9 × 8 + their 9 × 5 oe
or 72 + 45
M1dep
or
their 9 × (8 + 5) or their 9 × 13
117 A1 SC1 43.81 or 43.87 or 43.88 or 43.94
Alternative method 2: sets up and solves an equation
8 x + 27 oe equation
= or x = 45
5 x any letter
or
8 y
= or y = 72 M1
5 y − 27
or
(8 − 5)w
= 27
8 + 5
their 45 + their 45 + 27 oe
or
their 72 + their 72 – 27 M1dep
or
27 × (8 + 5) ÷ (8 – 5)
117 A1 SC1 43.81 or 43.87 or 43.88 or 43.94
The mark scheme for question 12 continues on the next page
Alternative method 3: trial and improvement with values in the correct ratio
8, 16, 24, 32, 40, 48, 56, 64, 72… repeated multiples of 8 and 5 until the
difference is 27
and M1
if the lists continue, 72 or 45 must be
5, 10, 15, 20, 25, 30, 35, 40, 45…
identified or used
cont 72 + 45 M1dep oe
117 A1 SC1 43.81 or 43.87 or 43.88 or 43.94
Additional Guidance
SC1 is for thinking Oscar has £27, with rounding at different stages
How to answer it
Solving Ratio Problems Involving Differences
This question assesses your ability to solve unstructured ratio problems where a difference between quantities is given rather than a total sum. Specifically, it tests:
- Recognising that the difference in value corresponds directly to the difference in ratio parts.
- Finding the unitary value (the worth of exactly 1 part/share).
- Scaling up to find individual shares or the total amount shared.
Question 12 (3 Marks)
Oscar and Nikita share some money in the ratio 8 : 5. Oscar has £27 more than Nikita. How much do they have altogether?
✅ Correct Answer
£117
📐 Step-by-Step Calculation (Unitary Method)
Oscar has 8 parts and Nikita has 5 parts.
Difference in parts = 8 - 5 = 3 parts
The difference of 3 parts is equal to £27.
Value of 1 part = £27 ÷ 3 = £9
Approach A (Total parts first):
Total parts = 8 + 5 = 13 parts
Total money = 13 × £9 = £117
Approach B (Individual amounts first):
Oscar = 8 × £9 = £72
Nikita = 5 × £9 = £45
Total money = £72 + £45 = £117
Altogether they have £117 .
Oscar: [ £9 ][ £9 ][ £9 ][ £9 ][ £9 ] [ £9 ][ £9 ][ £9 ] (8 blocks)
Nikita: [ £9 ][ £9 ][ £9 ][ £9 ][ £9 ] (5 blocks)
The 3 extra blocks represent the £27 difference. Thus, each block is £27 ÷ 3 = £9.
💡 Key Knowledge
- The "Difference" Rule: When a question states someone has "more than" or "less than" someone else, divide the amount by the difference in ratio parts, NOT the sum of parts.
- Ratio terminology: A ratio a : b means for every a parts one person receives, the other receives b identical parts.
- Check your work: £72 - £45 = £27 (Oscar has £27 more) and £72 : £45 simplifies to 8 : 5 by dividing by 9.
🧠 Exam Technique & Mark Scheme Notes
- Show working clearly: Writing 27 ÷ 3 = 9 secures the first method mark immediately, even if an arithmetic error happens later.
- Implied marks: Stating £72 or £45 automatically awards M1 because it proves you found the value of one part.
- Alternative methods accepted:
- Algebra: Solving 8/5 = (x + 27)/x gives Nikita's share x = 45 .
- Listing multiples: Listing 8s (8, 16... 72) and 5s (5, 10... 45) until the difference is 27.
❌ Common Errors & Examiner Pitfalls
- Dividing by the sum of parts: Many students automatically add the parts ( 8 + 5 = 13 ) and calculate 27 ÷ 13 . This is incorrect because £27 is NOT the total amount.
- Assuming £27 belongs to Oscar: Thinking Oscar has £27 results in 27 ÷ 8 = 3.375 per part, leading to answers like £43.88. The mark scheme only awards a consolation Special Case mark ( SC1 ) for this blunder.
- Stopping too early: Finding £9 (the value of 1 share) or £72 / £45 and failing to sum them together to answer "altogether". Always re-read the final line of the question!
• M1: For 27 ÷ (8 - 5) or 27 ÷ 3 or finding 9 (also implied by 72 or 45 seen).
• M1dep: Dependent on the first M1. For finding total: their 9 × 13 or their 72 + their 45 .
• A1: Fully correct final answer of 117 .
Topics
Ratio, proportion and rates of change · 3.3 Ratio, proportion and rates of change
Question and mark scheme from the AQA GCSE Mathematics examination, Paper 1 (Higher), June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.