AQA GCSE Physics Physics Paper 1 (Higher), November 2020: Question 8
9 marks · Standard Demand difficulty · Short Answer
Calculate missing data, evaluate precision, analyze inverse proportionality from a graph, and explain the effect on total resistance when adding resistors in parallel.
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Question text
08 A student investigated how the total resistance of identical resistors connected in
parallel varied with the number of resistors.
The student used an ohmmeter to measure the total resistance of the resistors.
Figure 11 shows the student’s circuit with 3 resistors.
Figure 11
The student repeated each reading of resistance three times.
Table 1 shows some of the results for 3 resistors in parallel.
Table 1
Number of Total resistance in ohms
resistors
Reading 1 Reading 2 Reading 3 Mean
3 15.8 15.3 X 15.7
08.1 Calculate value X in Table 1.
[2 marks]
X = Ω
08.2 The student thought that taking a fourth reading would improve the precision of the
results.
The fourth reading was 16.2 Ω.
Explain why the student was wrong.
[2 marks]
Figure 12 shows the results from the investigation.
Figure 12
08.3 The student concluded that the number of resistors in parallel was inversely
proportional to the mean total resistance.
Explain why the student was correct.
Use data from Figure 12 in your answer.
[3 marks]
08.4 Explain why adding resistors in parallel decreases the total resistance.
[2 marks]
Mark scheme
Show the mark scheme
Question 8
AO /
Question Answers Extra information Mark
Spec. Ref.
08.1 AO2
15.8 + 15.3 + X 1 4.2.1.3
15.7 = RPA 3
X = 16.0 (Ω)
08.2 precise results show little 1 AO3
variation 4.2.1.3
RPA 3
the 4th result was further away allow the range of values has 1
from the mean than the other increased
values
ignore the 4th result was an
anomaly
08.3 two pairs of values of n and R eg 2 × 24 = 48, 3 × 16 = 48 1 AO3
showing that n × R = constant 4 × 12 = 48, 5 × 9.5 = 47.5 4.2.1.3
6 × 8 =48 RPA 3
third pair of values of n and R 1
showing that n × R = constant
(so) n × R = constant (showing 1
the student was correct)
allow 1 mark each for two
statements relating the change
in number of resistors to the
change in (mean total)
resistance
allow 1 mark for use of data
from graph to confirm at least
one statement
08.4 multiple paths for charge / allow current for charge 1 AO1
electrons to flow 4.2.1.3
RPA 3
total current is greater (for the 1
same potential difference when
more resistors are added)
Total 9
How to answer it
Resistance of Resistors in Parallel Study Guide
This question assesses your understanding of electrical circuits (specifically resistors in parallel), working with experimental data, calculating means, understanding precision, analyzing graphical relationships (inverse proportionality), and explaining current flow.
Part 08.1: Calculating Missing Data
Calculate value X in Table 1. [2 marks]
📐 Step-by-Step Calculation
- State the formula for a mean: Mean = (Sum of all values) / (Number of values)
- Rearrange the formula to find the total sum: 15.7 × 3 = 47.1
- Add the known readings together: 15.8 + 15.3 = 31.1
- Subtract from the total sum to find X: 47.1 - 31.1 = 16.0
✅ Correct Answer
X = 16.0 (Ω)
Part 08.2: Precision and Anomalies
Explain why taking a fourth reading of 16.2 Ω would not improve precision. [2 marks]
💡 Key Knowledge
Precision refers to how close repeated measurements are to each other (showing little variation). It is not the same as accuracy.
✅ Correct Answer
- Precise results show little variation.
- The 4th reading (16.2 Ω) is further away from the mean than the other readings, meaning it increases the range of values rather than clustering tightly.
Part 08.3: Inverse Proportionality Analysis
Explain why the student was correct that number of resistors is inversely proportional to resistance. Use data from Figure 12. [3 marks]
🧠 Exam Technique
To prove inverse proportionality using graph data, pick pairs of values for n (number of resistors) and R (resistance) and show that multiplying them together gives a constant value (or roughly the same product).
✅ Correct Answer
- Select pairs of coordinates from Figure 12: e.g., at 2 resistors, resistance = 24 Ω ( 2 × 24 = 48 ).
- Pick a second pair: e.g., at 3 resistors, resistance = 16 Ω ( 3 × 16 = 48 ).
- Pick a third pair: e.g., at 6 resistors, resistance = 8 Ω ( 6 × 8 = 48 ).
- Conclusion: Since n × R = constant (48), the student was correct.
Part 08.4: Circuit Theory Explanation
Explain why adding resistors in parallel decreases the total resistance. [2 marks]
❌ Common Errors
Students often lose marks by simply stating "current increases" without explaining why. You must mention multiple paths for charge.
✅ Correct Answer
- ">
- Adding resistors in parallel provides multiple pathways for charge (or electrons) to flow.
- Therefore, the total current is greater for the same potential difference, which means overall resistance decreases (since R = V / I ).
Topics
Physics · Required Practicals · P2: Electricity · Required Practicals
Question and mark scheme from the AQA GCSE Physics examination, Physics Paper 1 (Higher), November 2020. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.