AQA GCSE Physics Physics Paper 1 (Higher), November 2020: Question 9

10 marks · Standard Demand difficulty · Short Answer

Calculate the resistance of a person given power and potential difference, explain why an electrician needs to disconnect a circuit before replacing a switch, and use a graph of maximum let-go current versus frequency to explain why a different frequency would be safer.

Practise this question

Question

Figure 13 shows a mains electricity lighting circuit diagram with a neutral wire connected to a lamp and a live wire connected to an open switch. Question 09.1 asks to calculate the resistance of a person given a mean power transfer of 5.75 W and potential difference of 230 V. Question 09.2 asks to explain why an electrician would receive an electric shock unless the circuit is disconnected from the mains supply. Question 09.3 includes Figure 14, a line graph plotting maximum current at which a person can let go in mA (y-axis, 0 to 20) against frequency in hertz (x-axis, 0 to 100), and asks to explain why it would be safer if the UK mains frequency was not 50 Hz.
Question text

09 Figure 13 shows part of a mains electricity lighting circuit in a house.

Figure 13

09.1 A fault in the switch caused a householder to receive a mild electric shock before a

safety device switched the circuit off.

The mean power transfer to the person was 5.75 W.

The potential difference across the person was 230 V.

Calculate the resistance of the person.

[5 marks]

Resistance = Ω

09.2 An electrician replaced the switch.

The electrician would have received an electric shock unless the circuit was

disconnected from the mains supply.

Explain why.

[3 marks]

09.3 The current from an electric shock causes a person’s muscles to contract. The

person cannot let go of the electrical circuit if the current is too high.

Figure 14 shows how the maximum current at which a person can let go depends on

the frequency of the electricity supply.

Figure 14

The UK mains frequency is 50 Hz.

Explain why it would be safer if the UK mains frequency was not 50 Hz.

[2 marks]

Mark scheme

Show the mark scheme The mark scheme outlines the answers and allocation of marks for questions 09.1, 09.2, and 09.3. For 09.1, it shows multi-step calculation paths using power, current, voltage, and resistance equations leading to 9200 ohms (5 marks). For 09.2, it credits points regarding live wires, the electrician being earthed, and potential difference (3 marks). For 09.3, it credits identifying 50 Hz as having the lowest let-go current and that different frequencies allow letting go at a greater current (2 marks).

Question 9

AO /

Question Answers Extra information Mark

Spec. Ref.

09.1 5.75 = I × 230 1 AO2

4.2.4.1

5.75 4.2.1.3

I = 1

I = 0.025 (A)

allow a correct substitution using

an incorrect value of I

230 = 0.025 × R 1

or

or

allow a correct rearrangement

230 using incorrect value of I

R =

0.025

allow a correct calculation of

resistance using an incorrect 1

R = 9200 (Ω)

value of I

alternative approach for 4th and

5th marks:

5.75 = 0.0252 × R (1)

or

5.75

R = 2

0.025

R = 9200 (Ω) (1)

alternative approach:

2302

5.75 = (3)

R

2302

R = (1)

5.75

R = 9200 (Ω) (1)

Extra information AO /

Question Answers Mark

Spec. Ref.

09.2 one wire in the switch is live allow the switch / circuit is live 1 AO1

allow one wire is at a potential of 4.2.3.2

230 V

the electrician is earthed 1

or

the electrician is at earth

potential

(so) there will be a (large) 1

potential difference between the

live wire and the electrician /

earth (if the electrician touched

the wire)

09.3 50 Hz has the lowest 1 AO3

(maximum) let-go current 4.2.3.1

a higher / lower / different allow a specific numerical 1

frequency would allow people to example as opposed to a trend

let go at a greater current

Total 10

How to answer it

Mains Electricity & Safety Study Guide

What this question tests

This question assesses your understanding of domestic mains electricity circuits, safety hazards, multi-step power and resistance calculations, and your ability to interpret safety data from line graphs.

Part 09.1

Calculating Resistance from Power and Potential Difference

📐 Step-by-Step Calculation

  1. Find current (I) first: Use the power formula P = V × I .
    Rearrange: I = P / V
    Substitute: I = 5.75 / 230 = 0.025 A
  2. Find resistance (R): Use Ohm's Law V = I × R .
    Rearrange: R = V / I
    Substitute: R = 230 / 0.025 = 9200 Ω

✅ Final Answer

Resistance = 9200 Ω (or 9,200 ohms)

Awarded 5 marks total: 3 marks for finding the correct current, and 2 marks for calculating the final resistance. ECF (Error Carried Forward) applies if you make an arithmetic error in step 1.

❌ Common Calculation Traps

  • Forgetting equations linking power, potential difference, and resistance ( P = V² / R can also be used directly in one step!).
  • Failing to rearrange equations properly before substituting numbers.

🧠 Exam Technique

Always write out the unadjusted formula first before substituting numbers. If you get stuck on multi-step calculations, look for alternative equations that combine variables (e.g., combining P = VI and V = IR into P = V² / R ).

Part 09.2

Explaining Electrical Shock Hazards

💡 Key Knowledge

  • Switches are always fitted to the live wire in domestic circuits.
  • The human body is mostly water and acts as a conductor, and humans standing on the ground are effectively earthed (at 0 V potential).
  • A potential difference causes charge to flow through a conductor.

✅ Marking Points (3 max)

  1. One wire connected to the switch is the live wire (at 230 V).
  2. The electrician is earthed / at earth potential (0 V).
  3. This creates a large potential difference between the live wire and the electrician, causing current to flow through them.
Part 09.3

Interpreting Graph Data on Frequency and Current Safety

🧠 Exam Technique & Graph Analysis

When looking at graphs with a curved minimum or maximum, locate the turning point first. Here, the minimum point of the curve occurs precisely at 50 Hz, meaning the lowest current required to trap someone occurs at the current UK mains frequency.

✅ Correct Answer & Mark Scheme

  • Point 1: 50 Hz has the lowest (maximum) let-go current.
  • Point 2: A higher, lower, or different frequency would allow people to let go at a greater current (making it safer).
2 marks. Note: Examiners accept general trends or specific numerical comparisons extracted from the vertical axis of Figure 14.

Topics

Physics · P2: Electricity

Question and mark scheme from the AQA GCSE Physics examination, Physics Paper 1 (Higher), November 2020. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.