AQA GCSE Physics Physics Paper 2 (Higher), June 2022: Question 5
9 marks · Standard Demand difficulty · Short Answer
Define centre of mass, calculate the mean weight of a tomato from a balance reading, determine the spring constant of a compression spring, and explain a property of the spring suitable for the balance.
Practise this questionQuestion
Question text
05 Figure 9 shows a balance used to measure the mass of five tomatoes.
Figure 9
05.1 What is meant by ‘centre of mass’?
[1 mark]
05.2 Calculate the mean weight of a tomato in Figure 9.
Use the Physics Equations Sheet.
gravitational field strength = 9.8 N/kg
[3 marks]
21 Weight = N
05.3 The balance in Figure 9 contains a spring that compresses when the tomatoes are
placed on the balance.
Figure 10 shows the spring with no force acting and with a 6.0 N force acting.
Figure 10
Determine the spring constant of the spring.
Use the Physics Equations Sheet.
[3 marks]
Spring constant = N/m
05.4 Explain one property of the spring that makes it suitable for use in the balance.
[2 marks]
Mark scheme
Show the mark scheme
Question 5
AO /
Question Answers Extra information Mark
Spec. Ref.
05.1 the point from which weight may allow the point through which 1 AO1
be considered to act the line of action of the weight 4.5.1.3
acts
or
the point where the mass allow the point at which the
appears to be concentrated mass is concentrated
AO /
Spec. Ref.
05.2 mass of 5 tomatoes = 0.425 (kg) 1 AO2
4.5.1.3
mass of 1 tomato = 0.085 (kg) allow an incorrect and / or not 1
converted reading correctly
divided by 5
W = (0.085 × 9.8) = 0.833 (N) allow a correct calculation using 1
their value of mass
AO /
Spec. Ref.
AO2
05.3 6.0 = k × 0.015 1 4.5.3
6.0 allow correct rearrangement 1
k = using an incorrectly calculated
0.015
value of e
k = 400 (N/m) allow a correct calculation using 1
an incorrectly calculated value
of e
AO /
Spec. Ref.
18 05.4 deforms elastically 1 AO3
4.5.3
(so) will return to its original 1
length / shape (after force is
removed)
OR
compression is directly
proportional to the force
(applied) (1)
(so) gives a linear scale (1) allow easy to calibrate
Total Question 5 9
How to answer it
Forces, Weight & Hooke's Law
This question assesses your ability to recall core definitions of centre of mass, accurately read analog scales, apply the weight equation (W = mg) with unit conversions (g to kg), determine the spring constant using Hooke's Law (F = ke), and explain the physical properties of a spring (elastic deformation and proportionality) required for measuring devices.
Definition of Centre of Mass
What is meant by 'centre of mass'?
✅ Correct Answer
Either of the following standard AQA definitions:
- The point from which weight may be considered to act.
- The point where the mass appears to be concentrated.
💡 Key Knowledge
- Every object behaves as if all its mass is focused at one single point.
- Gravity pulls down on all parts of an object, but we represent the total weight force as an arrow drawn downwards directly from the centre of mass.
🧠 Exam Technique
Be careful not to mix up "mass" and "weight". Notice how the words pair up:
- "Point where mass is concentrated"
- "Point from which weight acts"
❌ Common Errors
- Vague answers like "the exact middle of the tomato" (only true for symmetrical objects of uniform density).
- Saying "where gravity starts" (unscientific phrasing that scores 0).
Mean Weight of One Tomato
Calculate the mean weight of a tomato in Figure 9 (g = 9.8 N/kg).
📐 Step-by-Step Calculation
1 Read scale and convert mass to kg:
Pointer indicates 425 g (each major mark is 100 g; the needle points halfway between 400 g and 450 g).
Total mass = 425 ÷ 1000 = 0.425 kg [1 mark]
2 Find mass of one tomato:
There are 5 identical tomatoes:
Mean mass = 0.425 kg ÷ 5 = 0.085 kg [1 mark]
3 Calculate weight using W = mg:
W = 0.085 kg × 9.8 N/kg = 0.833 N [1 mark]
❌ Calculation Traps
- Forgetting to divide by 5: Calculating the weight of all 5 tomatoes (4.165 N) instead of the mean weight of a single tomato.
- Scale misread: Mistaking the pointer reading as 450 g or 420 g. Look closely at the interval divisions.
- Unit error: Multiplying grams directly by 9.8 (e.g., 85 × 9.8 = 833 N). In physics equations, mass must always be in kilograms (kg)!
Spring Constant Calculation
Determine the spring constant of the spring compressed from 5.0 cm to 3.5 cm by a 6.0 N force.
📐 Step-by-Step Calculation
1 Calculate compression (extension e):
Compression = Original length - Compressed length
e = 5.0 cm - 3.5 cm = 1.5 cm
Convert to metres: 1.5 ÷ 100 = 0.015 m
2 Substitute into Hooke's Law:
Equation: F = k × e
6.0 = k × 0.015 [1 mark]
3 Rearrange and solve for k:
k = 6.0 ÷ 0.015 [1 mark]
k = 400 N/m [1 mark]
🧠 Exam Technique & Units
- Check the printed unit on the answer line: it specifies N/m.
- If you keep extension as 1.5 cm, your answer would be 4 N/cm, but the given unit line says N/m, which will lose you the final mark! Always convert cm to m first.
- Error Carried Forward (ECF): If you calculated compression wrong (e.g., 2.0 cm), you can still get 2 marks for correctly rearranging and dividing 6.0 by your value.
Spring Properties in Measuring Scales
Explain one property of the spring that makes it suitable for use in the balance.
✅ Acceptable Answers (Choose ONE pair)
Option 1 (Elasticity):
- Property: It deforms elastically [1 mark]
- Explanation: (so) it will return to its original length / shape once the tomatoes are removed [1 mark]
Option 2 (Linearity / Hooke's Law):
- Property: Compression is directly proportional to the force applied [1 mark]
- Explanation: (so) it gives a linear scale / evenly spaced markings / is easy to calibrate [1 mark]
❌ Common Misconceptions
- Writing everyday descriptions like "it is flexible", "it bounces back", or "it is stretchy". Use the technical physics term: deforms elastically.
- Only giving the property without the explanation: stating "it obeys Hooke's Law" only earns 1 mark unless you explain that this provides an evenly spaced / linear dial scale.
Topics
Physics · P5: Forces
Question and mark scheme from the AQA GCSE Physics examination, Physics Paper 2 (Higher), June 2022. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.