AQA GCSE Physics Physics Paper 2 (Foundation), June 2023: Question 1
7 marks · Standard Demand difficulty · Short Answer
Investigate the extension of a spring, calculate weight and spring constant, and identify the correct force-extension graph.
Practise this questionQuestion
Question text
01 A student carried out an investigation to determine the spring constant of a spring.
Figure 1 shows the spring before and after a mass was hung from the end of
the spring.
Figure 1
01.1 What is the extension of the spring in Figure 1?
[1 mark]
Tick ( ) one box.
1.5 cm
3.5 cm
13.5 cm 3
01.2 Give one safety precaution the student should have taken during this investigation.
[1 mark]
*0021.*3 The student hung a mass of 0.050 kg from the spring.
gravitational field strength = 9.8 N/kg
Calculate the weight of the 0.050 kg mass.
Use the equation:
weight = mass × gravitational field strength
[2 marks]
Weight = N
01.4 The weight of the mass applies a force to the spring.
The student added more masses and recorded the extension of the spring.
Which graph in Figure 2 shows the relationship between the force applied to the
spring and the extension of the spring?
[1 mark]
Tick ( ) one box.
Figure 2
01.5 A force of 2.0 N was applied to a different spring.
*03* The extension of the spring was 0.080 m.
Calculate the spring constant of the spring.
Use the equation:
force
spring constant =
extension
[2 marks]
Spring constant = N/m
Mark scheme
Show the mark scheme
Question 1
AO /
Question Answers Extra information Mark
Spec. Ref.
01.1 1.5 cm 1 AO1
4.5.3
RPA6
AO /
Spec. Ref.
01.2 any one from: 1 AO1
• clamp the stand to the desk 4.5.3
• wear safety goggles / glasses RPA6
• stand up / away from
apparatus
• limit the total mass used
• have masses over the base of
the stand
AO /
Spec. Ref.
01.3 W = 0.050 × 9.8 1 AO2
4.5.1.3
W = 0.49 (N) do not accept 0.50 (N) alone 1
AO /
Spec. Ref.
01.4 1 AO1
4.5.3
RPA6
AO /
Spec. Ref.
01.5 2.0 1 AO2
k =
0.080 4.5.3
RPA6 7
k = 25 (N/m) 1
Total Question 1 7
How to answer it
Investigating Springs Study Guide
This question assesses your understanding of required practical work involving springs (Hooke's Law), data reading from a metre rule, calculating weight (force), and applying the spring constant equation. It tests recall of practical safety, graph interpretation, and basic calculation skills (AO1 and AO2).
Part (01.1) - Reading Extension from a Metre Rule
What is the extension of the spring in Figure 1? [1 mark]
✅ Correct Answer
1.5 cm
💡 Key Knowledge
- Extension is the increase in length from the original (unstretched) position.
- Before position pointer = 10.0 cm
- After position pointer = 11.5 cm
- Calculation: 11.5 cm - 10.0 cm = 1.5 cm
Part (01.2) - Practical Safety Precautions
Give one safety precaution the student should have taken during this investigation. [1 mark]
✅ Correct Answers (Any one of):
- Clamp the stand to the desk (to stop it toppling over).
- Wear safety goggles / glasses (in case the spring snaps).
- Stand up / away from the apparatus.
- Limit the total mass used (to prevent exceeding the limit of proportionality).
- Have masses over the base of the stand (for stability).
🧠 Exam Technique
Learn standard practical safety hazards and precautions by heart. For stretched springs, the main risks are falling heavy masses and the spring snapping or the stand toppling over.
Part (01.3) - Calculating Weight
Calculate the weight of the 0.050 kg mass. Use equation: weight = mass × gravitational field strength [2 marks]
📐 Step-by-Step Calculation
- Identify values: Mass ( m ) = 0.050 kg, Gravitational field strength ( g ) = 9.8 N/kg.
- Substitute into equation: Weight = 0.050 × 9.8
- Calculate final value: 0.49 N
❌ Common Errors
Do NOT write 0.50 N! Students often round 0.49 to 0.50 incorrectly. The exact calculator value must be shown or rounded properly to 2 significant figures ( 0.49 ).
Part (01.4) - Force-Extension Graphs
Which graph in Figure 2 shows the relationship between the force applied and the extension? [1 mark]
✅ Correct Answer
The middle graph (showing a straight line passing directly through the origin, indicating direct proportionality).
💡 Key Knowledge
Hooke’s Law states that extension is directly proportional to the force applied, provided the limit of proportionality is not exceeded. On a graph, direct proportionality is shown by a straight line through (0,0).
Part (01.5) - Calculating Spring Constant
Calculate the spring constant for a force of 2.0 N and extension of 0.080 m. Use equation: spring constant = force / extension [2 marks]
📐 Step-by-Step Calculation
- Identify values: Force = 2.0 N, Extension = 0.080 m.
- Substitute into equation: k = 2.0 / 0.080
- Calculate final value: 25 N/m
🧠 Exam Technique & Units
Always double-check your units. Here, extension is already given in metres (m), and force in Newtons (N), giving the standard unit for spring constant: N/m .
Topics
Physics · Required Practicals · P5: Forces · Required Practicals
Question and mark scheme from the AQA GCSE Physics examination, Physics Paper 2 (Foundation), June 2023. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.