AQA GCSE Physics Physics Paper 1 (Higher), June 2024: Question 8

8 marks · Standard Demand difficulty · Short Answer

Explain why pressure increases when a syringe's volume is decreased, identify the effect of temperature increase on particles, and calculate temperature change using specific heat capacity.

Practise this question

Question

A three-part physics question about gas pressure and internal energy. Part 08.1 asks to explain why pressure increases when air in a syringe is compressed at constant temperature, accompanied by Figure 12 showing a syringe connected to a pressure gauge. Part 08.2 asks how temperature increase affects air particles, with three tick-box options, accompanied by Figure 13 showing a fire piston. Part 08.3 asks to calculate the temperature change of air given energy transferred, mass, and specific heat capacity.
Question text

08 A student investigated how the pressure in a fixed mass of air varies with the volume

of the air.

Figure 12 shows the equipment used.

Figure 12

08.1 When the plunger was pushed slowly into the syringe, the pressure in the

syringe increased.

The temperature of the air remained constant.

Explain why the pressure increased.

[3 marks]

A fire piston is a special type of syringe that can be used to start fires.

Figure 13 shows a fire piston.

Figure 13

The plunger is pushed quickly downwards and compresses the air.

When the air is compressed quickly, the temperature of the air increases.

08.2 How does an increase in temperature affect the air particles inside the piston?

[1 mark]

Tick ( ) one box.

The mean kinetic energy of the particles increases.

The mean potential energy of the particles increases.

The mean separation of the particles increases.28

08.3 When the air is hot enough, a small piece of cotton wool in the piston catches fire.

The energy transferred to the air in the piston is 0.0130 J.

The mass of air in the piston is 2.60 × 10–8 kg.

specific heat capacity of air = 1.01 kJ/kg °C

*27* Calculate the temperature change of the air.

Use the Physics Equations Sheet.

[4 marks]

Temperature change = °C

Mark scheme

Show the mark scheme Mark scheme for Question 8 showing answers and allocation for parts 08.1, 08.2, and 08.3. Part 08.1 awards 3 marks for particles closer together, increased frequency of collisions with walls, and larger force on a smaller area. Part 08.2 awards 1 mark for mean kinetic energy increasing. Part 08.3 awards 4 marks for converting and substituting values into the specific heat capacity equation to find a temperature change of 495 degrees Celsius.

Question 8

AO /

Question Answers Extra information Mark

Spec. Ref.

08.1 (air) particles are closer together ignore reference to kinetic 1 AO1

energy of particles 4.3.3.2

ignore reference to

concentration of air particles

(so) frequency of collision do not credit MP2 if linked to an 1

between air particles and increase in kinetic energy

syringe walls increased

larger (total) force on a smaller allow larger force per unit area 1

(surface) area

if no other marks score allow

1 mark for pressure increases

because volume decreases and

pV = constant

AO /

Spec. Ref.

08.2 the mean kinetic energy of the 1 AO1

particles increases 4.3.3.1

AO /

Question Answers Extra information Mark Spec.

08.3 c = 1010 (J/kg °C) allow full credit for a correct 1 AO2Ref.

method using E = 0.0000130 4.1.1.3

(kJ) 4.3.2.2

0.0130 = 2.60×10–8 × 1010 × Δθ allow a correct substitution of an 1

incorrectly / not converted value

of c

0.0130 allow a correct rearrangement of 1

∆θ = –8 an incorrectly / not converted

(2.60 × 10 × 1010)

value of c

Δθ = 495 (°C) allow an answer consistent with 1

an incorrectly / not converted

value of c

allow a correct answer given to

more than 3 sig figs

Total Question 8 8

How to answer it

Particle Model of Matter & Energy Study Guide

AQA GCSE Physics

What this question tests

This question assesses your understanding of the particle model of matter, specifically how pressure relates to volume and particle collisions in gases at a constant temperature, the relationship between temperature and particle kinetic energy, and applying the specific heat capacity equation to calculate temperature changes.

Part 08.1: Explaining Pressure and Volume

When the plunger was pushed slowly into the syringe, the pressure increased. Explain why. (3 marks)

✅ Correct Answer Structure

  • Air particles are closer together (smaller volume).
  • The frequency of collisions between air particles and the syringe walls increases.
  • This creates a larger force on a smaller surface area, resulting in higher pressure.

💡 Key Knowledge

  • Pressure in a gas is caused by particles colliding with container walls.
  • If volume decreases, particles have less distance to travel between walls, causing them to collide more often.
  • Boyle's Law concept: Pressure × Volume = Constant (at constant temperature).

🧠 Exam Technique

  • This is a classic 3-mark causal chain question. You must explain step-by-step: distance/volume change → collision frequency → force/area.
  • Alternative acceptable marking point: Mentioning that pressure increases because volume decreases and pV = constant .

❌ Common Errors

  • Stating that particle speed or kinetic energy increases (the question states temperature remains constant!).
  • Failing to link collision frequency specifically to the walls of the container.
Mark breakdown: 1 mark for particles closer together, 1 mark for increased collision frequency with walls, 1 mark for larger force on a smaller area.

Part 08.2: Temperature and Particle Energy

How does an increase in temperature affect the air particles inside the piston? Tick one box. (1 mark)

✅ Correct Answer

The mean kinetic energy of the particles increases. (Tick the first box)

💡 Key Knowledge

Temperature is directly proportional to the mean (average) kinetic energy of the particles in a system. When a gas is compressed quickly, work is done on it, increasing its internal energy and temperature.

Mark breakdown: 1 mark for selecting the correct statement.

Part 08.3: Specific Heat Capacity Calculation

Calculate the temperature change of the air. (4 marks)

Given data: Energy ( E ) = 0.0130 J, Mass ( m ) = 2.60 × 10⁻⁸ kg, Specific heat capacity ( c ) of air = 1.01 kJ/kg °C

📐 Step-by-Step Calculation

  1. Convert units: Convert c from kJ/kg °C to J/kg °C.
    1.01 kJ = 1010 J, so c = 1010 J/kg °C .
  2. Recall equation:
    E = m × c × Δθ
  3. Substitute values:
    0.0130 = (2.60 × 10⁻⁸) × 1010 × Δθ
  4. Rearrange and solve for Δθ:
    Δθ = 0.0130 / ((2.60 × 10⁻⁸) × 1010)
    Δθ = 0.0130 / 0.00002626
    Δθ = 495 °C

❌ Common Calculation Traps

  • Unit prefix trap: Forgetting to convert kJ to J by multiplying by 1000. Examiners allow error-carried-forward (ECF) if you forgot to convert, but getting it right gets full marks!
  • Standard form input errors: Entering numbers incorrectly into the calculator with powers of 10. Always use brackets around scientific notation.
Mark breakdown: 1 mark for converting c to 1010 J/kg °C, 1 mark for correct substitution, 1 mark for correct rearrangement, 1 mark for final answer of 495 °C (allow answers to more than 3 significant figures if derived correctly).

Topics

Physics · P1: Energy · P3: Particle Model of Matter

Question and mark scheme from the AQA GCSE Physics examination, Physics Paper 1 (Higher), June 2024. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.