Edexcel A-Level Chemistry AS Paper 2, June 2017: Question 4
16 marks · Hard difficulty · Open Response
Deduce the molecular formula, molar mass, mass spectral fragmentation, infrared spectroscopy peaks, chemical tests, and addition reaction isomers of the terpene geraniol.
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Question text
4 (a) The characteristic smell of pine wood is due, partly, to the presence of a group of
compounds called terpenes. One of the simpler terpenes is a compound called geraniol,
which is an oily liquid at room temperature and pressure. The structure of geraniol is
OH
Deduce the molecular formula of geraniol. Use your answer to calculate the
molar mass of geraniol in g mol–1.
(2)
(b) The mass spectrum of geraniol is shown.
0.0
0.0 40 80 120 160
m / z
(i) Show that this mass spectrum can be used to confirm the molar mass of geraniol.
(1)
(ii) Identify an ion that could be responsible for the peak at m / z = 69.
(1)
(c) The infrared spectrum of geraniol is shown.
*P49857A0624*
4000 3000 2000 1500 1000 500
Wavenumber / cm–1
Using the table of absorptions from the Data Booklet and the infrared spectrum,
give the names of the two functional groups present in geraniol.
To confirm these functional groups, give the wavenumber ranges and their
corresponding bonds.
(2)
First functional group …
Second functional group …
(d) Give one chemical test that you could use to confirm the presence of each of the
two functional groups suggested in part (c). Predict a result for each test.
(4) 7
Test and result for first functional group*P49857A0724* …
Test and result for second functional group …
(e) Some plants are able to make terpenes by linking together several molecules of
2-methylbuta-1,3-diene, also known as isoprene.
The skeletal formula of 2-methylbuta-1,3-diene is
Predict the number of isoprene molecules that would be needed to make a single
geraniol molecule. Justify your answer.
(2)
(f ) 2-methylbuta-1,3-diene can react with hydrogen bromide.
When 2-methylbuta-1,3-diene reacts with excess hydrogen bromide, several
isomeric products are possible. Give the structures of four isomeric products.
(4)
*P49857A0824*
(Total for Question 4 = 16 marks)
Mark scheme
Show the mark scheme
Question
Acceptable Answer Additional Guidance Mark
Number
4(a) C10H18O (1) Ignore C10H17OH (2)
154 (g mol-1) (1) no TE on incorrect molecular
formula except for C10 H17OH
Question
Acceptable Answer Additional Guidance Mark
Number
4(b)(i) furthest peak to right/ highest m / z = 154 Ignore just ‘ highest peak’ (1)
may be shown on spectrum alone
provided 154 stated
Allow parent ion/molecular ion/last
peak at 154
Must see the figure 154 in text or on
graph
Question
Acceptable Answer Additional Guidance Mark
Number
4(b)(ii) C H + / [C H ]+ + charge is essential, allow charge (1)
59 5 9
anywhere on the ion/ outside /
inside brackets
Allow displayed/structural/skeletal
formula or any combination of
these.
Ignore name of ion even if incorrect
(Correct name: 2-methylbut-2-ene
ion)
Question
Answer Acceptable Additional Guidance Mark
Number
4(c) alkene and can be in either order (2)
C=C and
(IR) peak between 1669 and 1645 (cm-1 )
OR
alkene and
C-H and Allow CH (bond)
(IR) peak between 3095 and 3010
OR 3095 and 2995 (cm-1 ) (1)
alcohol and Ignore any qualification of the
O-H and wavenumber range eg isolated
(IR) peak between 3750 and 3200 (cm-1 ) (1) alcohol or phenol
Allow Hydroxyl
Do not award Hydroxide
Allow OH (bond)
Do not award –OH /–O–H
If both bonds missing and
everything else correct, award 1
mark
Ignore all references to alkanes
Allow single IR value or range within
the data book range
Question
Acceptable Answer Additional Guidance Mark
Number
4(d) An answer that makes reference to the following points: Allow alkene and alcohol (4)
in either order.
No TE for other groups
incorrectly identified in 4c
or alkanes
Result dependent on
correct test for both
functional groups
Alkene
bromine water/Br2(aq)/bromine (1) allow acidified potassium
manganate/KMnO4.
decolorised or orange/yellow/brown to colourless (1) Decolourised (from
purple)
Alcohol
PCl5/phosphorus pentachloride /phosphorus(V)chloride (1)
allow (warm with)
Misty/steamy/white fumes (1) acidified Cr O 2-
turns from orange to
green / blue
If name and formula,
both must be correct
sodium (metal)
effervescence
OR
any other workable test
and correct result
Question
Acceptable Answer Additional Guidance Mark
Number
4(e) 2 (1) Note: this must be a (2)
whole number
number of C atoms in geraniol = 10, C atoms in isoprene = 5, Allow answers using C
(10/5 = 2) (1) chain length ie isoprene =
4, geraniol = 8
Ignore number of
hydrogens in both
isoprene and geraniol
Do not award answers
using Mr
Question
Acceptable Answer Additional Guidance Mark
Number
(4)
4(f) accept displayed/structural/skeletal formulae
Allow 2 marks for 4 different and correct
monobromo isomers
one mark for each structure Allow 1 mark for 2/3 different and correct
monobromo isomers
Zero for 1 monobromoisomer
accept correct enantiomers (provided both C=C
bond react)
Deduct one mark only for use of HCl
Deduct one mark for (any number of) missing
hydrogens
(Total for Question 4 = 16 mark)
How to answer it
Analysis and Reactions of Geraniol Study Guide
What this question tests
This comprehensive structured question evaluates core AS organic analysis and reaction mechanisms: counting atoms from skeletal structures to find molecular formulae and molar mass, interpreting mass spectra (molecular ion peaks and fragment ions), reading infrared (IR) spectra to identify functional groups and bonds, selecting chemical tests with clear observations, applying stoichiometric reasoning to terpene structures, and drawing multiple isomeric addition products (including structural and stereochemical awareness) from electrophilic addition reactions.
Part (a): Molecular Formula and Molar Mass
Determining formula and relative molecular mass from a skeletal structure
✅ Correct Answer
- Molecular formula: C₁₀H₁₈O
- Molar mass: 154 g mol⁻¹ (units required)
💡 Key Knowledge
Each vertex in a skeletal structure represents a carbon atom. Terminals represent methyl groups (unless stated otherwise). Hydrogen atoms must be deduced by ensuring each carbon forms 4 covalent bonds.
📐 Calculation Steps
- Count carbons: 10 carbon atoms in the main chain and branches.
- Count hydrogens: Account for 2 double bonds (each losing 2 H compared to an alkane) and the OH group. Total = 18 hydrogens.
- Calculate molar mass: (10 × 12.0) + (18 × 1.0) + (1 × 16.0) = 154 g mol⁻¹.
❌ Common Errors
Forgetting to include units for molar mass, or miscounting hydrogen atoms on terminal methyl groups or near double bonds.
Part (b): Mass Spectrometry
Interpreting molecular ions and fragment ions
✅ Correct Answers
(i) The furthest peak to the right (molecular ion peak / parent ion) is at m/z = 154 , which confirms the molar mass.
(ii) C₅H₅⁺ (or [C₅H₅]⁺ )
💡 Key Knowledge
The molecular ion peak corresponds to the molecular mass of the intact molecule losing one electron. Fragment peaks correspond to stable carbocations formed during fragmentation.
🧠 Exam Technique
For part (ii), ensure the positive charge is clearly indicated (e.g. superscript plus sign) on the ion formula. Brackets around the formula with an external plus sign are also fully accepted.
Part (c): Infrared Spectroscopy
Identifying functional groups and absorbance ranges
✅ Correct Answer
- First functional group: Alkene. Bond: C=C (Range: 1645–1669 cm⁻¹) OR C-H alkene stretch (Range: 3010–3095 cm⁻¹).
- Second functional group: Alcohol (or Hydroxyl). Bond: O-H (Range: 3200–3750 cm⁻¹).
❌ Common Errors
Writing "hydroxide" instead of "alcohol" or "hydroxyl" loses the functional group mark. Quoting wavenumber ranges outside the Data Booklet values or missing bond assignments will lose credit.
Part (d): Chemical Tests
Confirming alkenes and alcohols chemically
✅ Correct Answers
- Alkene Test: Add bromine water ( Br₂(aq) ). Observation: Changes from orange/brown/yellow to colourless.
- Alcohol Test: Add phosphorus pentachloride ( PCl₅ ). Observation: Misty / steamy / white fumes produced. (Alternative: Acidified potassium dichromate turns orange to green upon warming).
❌ Common Errors
Writing "clear" instead of "colourless" when describing the bromine water test is a frequent penalty. Ensure reagent names and distinct observations are explicitly paired.
Part (e): Terpene Stoichiometry
Relating isoprene units to the target molecule
✅ Correct Answer
2 isoprene molecules.
💡 Key Knowledge
Isoprene (2-methylbuta-1,3-diene) has 5 carbon atoms. Geraniol has 10 carbon atoms.
📐 Calculation & Justification
Number of carbon atoms in geraniol = 10. Number of carbon atoms in isoprene = 5. Therefore, ratio = 10 / 5 = 2.
Part (f): Electrophilic Addition Isomers
Drawing multiple structural/positional isomers from excess HBr addition
✅ Correct Answers
When excess hydrogen bromide ( HBr ) reacts with 2-methylbuta-1,3-diene, both double bonds undergo electrophilic addition. Four distinct dibromovaler / dibromomethylbutane isomeric structures can be formed depending on Markovnikov addition across the conjugated/isolated double bond positions:
- 1,2-dibromo-2-methylbutane structure
- 2,3-dibromo-2-methylbutane structure
- 1,3-dibromo-3-methylbutane structure
- 2,4-dibromo-2-methylbutane (or equivalent positional/skeletal monobromo/dibromo combinations accepted by mark scheme)
🧠 Exam Technique
Use displayed, structural, or clear skeletal formulae. Check that all carbon atoms have 4 bonds and every added bromine atom is correctly placed. Examiners award 1 mark per correct unique isomer up to 4 marks.
❌ Common Errors
Drawing duplicate identical molecules rotated in space, or failing to add HBr across both double bonds when "excess" is specified.
Topics
Physical Chemistry · Organic Chemistry · Core Practicals · Topic 5: Formulae, Equations and Amounts of Substance · Topic 6: Organic Chemistry I · Topic 7: Modern Analytical Techniques I · Core Practical 7: Identify unknown organic liquids and inorganic solids
Question and mark scheme from the Edexcel A-Level Chemistry examination, AS Paper 2, June 2017. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.