Edexcel A-Level Chemistry Paper 1, June 2019: Question 1

4 marks · Medium difficulty · Multiple Choice

Identify subatomic particles in 18O, select the correct mass spectrum for bromine molecules, determine the number of electrons in occupied p orbitals of a chloride ion, and identify the isoelectronic ion with the largest ionic radius.

Practise this question

Question

A multiple-choice question with four parts (a to d) about atoms, molecules and ions. Part (a) asks for the numbers of subatomic particles in an 18O atom with options A, B, C, D. Part (b) asks to identify the correct mass spectrum for a sample of bromine molecules with equal proportions of 79Br and 81Br isotopes, showing four mass spectra graphs A, B, C, and D with m/z values on the x-axis and relative intensity on the y-axis. Part (c) asks for the total number of electrons in all occupied p orbitals in a chloride ion, Cl-, with options A, B, C, D. Part (d) asks which of the isoelectronic ions N3-, O2-, Na+, and Al3+ has the largest ionic radius, with options A, B, C, D.
Question text

1 This question is about atoms, molecules and ions.

(a) The numbers of subatomic particles in an 18O atom are

(1)

A 8 protons, 10 neutrons and 8 electrons

B 9 protons, 9 neutrons and 9 electrons

C 10 protons, 8 neutrons and 10 electrons

D 18 protons, 18 neutrons and 18 electrons

(b) The mass spectrum of a sample of bromine molecules with approximately equal

proportions of the 79Br and 81Br isotopes is

(1)

A B

Relative Relative

intensity intensity

60 80 100 120 140 160 60 80 100 120 140 160

m/z m/z

C D

Relative Relative

intensity intensity

60 80 100 120 140 160 60 80 100 120 140 160

m/z m/z

(c) The total number of electrons in all the occupied p orbitals in a chloride ion, Cl–, is

(1)

A 5

B 6

2 C 12

D 18 *P58306A0228*

(d) Which of these isoelectronic ions has the largest ionic radius?

(1)

A N3–

B O2–

C Na+

D Al3+

(Total for Question 1 = 4 marks)

Mark scheme

Show the mark scheme The mark scheme showing the correct answers for Question 1: 1(a) is A, 1(b) is D, 1(c) is C, and 1(d) is A, along with brief explanations for why the other options are incorrect.

How to answer it

Atoms, Molecules and Ions (Edexcel A-Level Chemistry)

What this question tests

This foundational multiple-choice question set assesses core atomic structure and subatomic particle calculations, mass spectrometry fragmentation patterns for diatomic molecules with isotopes, electronic configurations of ions in terms of subshell orbitals, and periodic trends in ionic radius across isoelectronic series.

Part (a)

Subatomic Particles in an Oxygen-18 Atom

✅ Correct Answer: A

8 protons, 10 neutrons and 8 electrons

Awarded 1 mark for identifying the correct combination.

💡 Key Knowledge

  • Atomic number (proton number) of oxygen is 8, meaning it always has 8 protons.
  • In a neutral atom, number of electrons equals the number of protons (8 electrons).
  • Neutrons = Mass Number (18) minus Atomic Number (8) = 10 neutrons.

❌ Common Errors

Options B, C, and D are incorrect because oxygen atoms always possess 8 protons. Changing the proton number changes the element entirely.

Part (b)

Mass Spectrum of Bromine Molecules

✅ Correct Answer: D

Reflects three sets of molecular ion peaks corresponding to 79Br2 , 79Br-81Br , and 81Br2 in a 1:2:1 ratio due to roughly equal isotopic abundance.

Awarded 1 mark for selecting spectrum D.

🧠 Exam Technique

  • Bromine exists as a diatomic molecule ( Br₂ ) with two main isotopes: ⁷⁹Br and ⁸¹Br in a 1:1 ratio.
  • Molecular ion peaks ( m/z ) form at:
    • 79 + 79 = 158 (Height 1)
    • 79 + 81 = 160 (Height 2, because it can form two ways: ⁷⁹Br-⁸¹Br or ⁸¹Br-⁷⁹Br)
    • 81 + 81 = 162 (Height 1)

❌ Common Errors

A has no peaks at the molecular mass range (158-162). B misses the mixed isotopic peak at m/z 160. C incorrectly shows a 1:1:1 ratio instead of accounting for statistical probability (1:2:1).

Part (c)

Electrons in Occupied p Orbitals of a Chloride Ion

✅ Correct Answer: C

12 electrons in occupied p orbitals.

Awarded 1 mark for selecting C.

💡 Key Knowledge

  • Chloride ion ( Cl⁻ ) has an electron configuration of 1s² 2s² 2p⁶ 3s² 3p⁶ .
  • Occupied p orbitals include 2p (6 electrons) and 3p (6 electrons).
  • Total p-electrons = 6 + 6 = 12.

❌ Common Errors

A (5) and B (6) fail to account for all occupied p subshells across different principal energy levels. D (18) represents the total number of electrons in the chloride ion, not just those in p orbitals.

Part (d)

Ionic Radius in an Isoelectronic Series

✅ Correct Answer: A

N³⁻ has the largest ionic radius.

Awarded 1 mark for selecting A.

🧠 Exam Technique

  • All listed ions ( N³⁻ , O²⁻ , Na⁺ , Al³⁺ ) are isoelectronic—they all have the exact same electron configuration (10 electrons, like Neon).
  • When electronic structure is constant, ionic radius is governed entirely by nuclear charge (proton number).
  • As nuclear charge increases, the inward electrostatic pull from the nucleus on the electron cloud increases, pulling electrons closer and shrinking the radius.

❌ Common Errors

Students often confuse isoelectronic species with atomic radius trends. Aluminium ( Al³⁺ , 13 protons) exerts the strongest nuclear attraction, resulting in the smallest radius, whereas nitrogen ( N³⁻ , 7 protons) has the weakest nuclear pull, resulting in the largest radius.

Topics

Physical Chemistry · Organic Chemistry · Topic 1: Atomic Structure and the Periodic Table · Topic 7: Modern Analytical Techniques I

Question and mark scheme from the Edexcel A-Level Chemistry examination, Paper 1, June 2019. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.