Edexcel A-Level Chemistry Paper 1, June 2025: Question 1
6 marks · Easy difficulty · Short Open Response
Define relative isotopic mass and isotope using argon as an example, and calculate the relative atomic mass of argon to two decimal places.
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Mark scheme
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How to answer it
Isotopes, Relative Isotopic Mass & Atomic Mass of Argon
What this question tests
- Standard Definitions: Recalling the precise IUPAC-approved definition of relative isotopic mass compared to the carbon-12 standard.
- Sub-atomic Structure: Defining isotopes and calculating specific numbers of protons and neutrons from mass and atomic numbers.
- Quantitative Chemistry: Calculating weighted mean relative atomic mass (Ar) from percentage isotopic abundances and quoting to the specified degree of accuracy.
Relative Isotopic Mass Definition
Define the term ‘relative isotopic mass’
✅ Model Answer
The mass of an atom of an isotope [1 mark]
compared to (or relative to) 1/12th the mass of an atom of carbon-12 [1 mark]
(Mass of one atom of an isotope × 12) ÷ (Mass of one atom of carbon-12)
💡 Key Knowledge
- Isotopic vs Atomic: Isotopic mass refers to a single specific atom of an isotope, not an average.
- The Standard: Carbon-12 (12C) is the universal international standard, defined as having exactly 12 atomic mass units. Hence, 1 unit = 1/12th of an atom of 12C.
❌ Common Errors & Misconceptions
- Mentioning “average” or “weighted mean”: This confuses relative isotopic mass with relative atomic mass (Ar). Examiners penalise any mention of “average/mean mass”.
- Omitting “atom”: Saying “mass of an isotope relative to carbon-12” loses mark 1. You must state mass of an atom.
- Mentioning “moles”: Definitions are based on individual atoms, not molar masses (e.g. do not say “mass of 1 mole of an isotope relative to 1 mole of carbon-12”).
🧠 Exam Technique
- Commit the two distinct halves of the definition to memory: (1) mass of an atom of an isotope, (2) relative to 1/12th the mass of a carbon-12 atom.
- If you write the fraction form, ensure “atom” is written in both the numerator and denominator.
Defining Isotopes with Argon Data
Define ‘isotope’ and illustrate using the sub-atomic particles in the given argon isotopes
✅ Model Answer
- All isotopes have 18 protons (and 18 electrons) [1 mark]
- The isotopes have different numbers of neutrons: [1 mark]
- 36Ar has 18 neutrons (36 − 18)
- 38Ar has 20 neutrons (38 − 18)
- 40Ar has 22 neutrons (40 − 18)
| Isotope | Protons | Neutrons |
|---|---|---|
| 36Ar | 18 | 18 |
| 38Ar | 18 | 20 |
| 40Ar | 18 | 22 |
🧠 Exam Technique & Guidance
- Always link theory to the specific example: The question explicitly says “Illustrate your answer by referring to the numbers of sub-atomic particles in these isotopes of argon”. Giving only a generic textbook definition caps you at a maximum of 1 mark!
- Check your Periodic Table: Argon has atomic number Z = 18. Therefore, every argon atom must contain 18 protons.
- Number of neutrons = Mass number (A) − Atomic number (Z).
❌ Common Errors
- Giving vague terms: “Same atomic number, different mass number” does not satisfy the requirement to refer to sub-atomic particles.
- Incorrect electron counts: If you mention electrons, you must state 18 electrons. An incorrect electron number will lose mark 1.
💡 Key Knowledge
- Because all isotopes of an element have identical numbers and arrangements of electrons, they display identical chemical properties.
- Different neutron counts lead to differing physical properties (e.g. mass, density, rate of diffusion).
Relative Atomic Mass (Ar) Calculation
Calculate the relative atomic mass of argon to two decimal places
📐 Step-by-Step Calculation
Step 1: Set up the weighted mean formula
Ar = Σ (relative isotopic mass × % abundance) ÷ 100
Using the data from the table:
Ar = [(35.97 × 0.337) + (37.96 × 0.063) + (39.96 × 99.600)] ÷ 100
Step 2: Calculate intermediate sum
= (12.12189 + 2.39148 + 3980.016) ÷ 100
= 3994.52937 ÷ 100 = 39.9452937...
Step 3: Round to two decimal places (as instructed)
Ar = 39.95 [1 mark]
❌ Calculation Traps & Common Errors
- Rounding errors: Rounding to 40, 39.9, or 39.94 loses the second mark. Look at the third decimal digit (39.94 5 ...) → rounds up to 39.95.
- Using nominal mass numbers (36, 38, 40): When exact isotopic masses are provided (e.g. 35.97), you must use them. Using integer mass numbers leads to an inaccurate final value.
- Adding incorrect units: Relative atomic mass is a dimensionless ratio. Do not write “g” or “amu” (though the mark scheme ignores “g mol⁻¹”, it penalises other incorrect units).
🧠 Top-Scorer Reality Check
- Sanity check your answer: 40Ar makes up 99.600% of argon, so your calculated value must be extremely close to 39.96. If your result is 37 or 38, check your arithmetic!
- Always re-read the final line of the question: “Give your answer to two decimal places.” Highlight this instruction before writing down your final answer.
Topics
Physical Chemistry · Topic 1: Atomic Structure and the Periodic Table
Question and mark scheme from the Edexcel A-Level Chemistry examination, Paper 1, June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.