OCR A-Level Chemistry AS Breadth in chemistry (01), June 2018: Question 2
1 mark · Medium difficulty · Multiple Choice
Calculate the number of oxygen atoms in 88.0 g of CO2
Practise this questionQuestion
Question text
2 What is the number of oxygen atoms in 88.0 g of CO2?
A 3.01 × 1023
B 1.20 × 1024
C 2.41 × 1024
D 4.82 × 1024
Your answer [1]
Mark scheme
Show the mark scheme
2 C 1
How to answer it
Calculating Number of Specific Atoms from Mass
What this question tests
This question assesses your ability to interconvert between mass, moles, and the number of constituent particles (atoms/molecules) using the Avogadro constant, alongside applying correct chemical stoichiometry (the ratio of atoms within a chemical formula).
Question 2: Step-by-Step Breakdown
Determining the number of oxygen atoms in 88.0 g of CO₂
✅ Correct Answer: C
Option C ( 2.41 × 10²⁴ ) is the correct choice because 88.0 g of carbon dioxide contains 2 moles of molecules, which equates to 4 moles of oxygen atoms. Multiplying 4 by the Avogadro constant gives 2.41 × 10²⁴ atoms.
💡 Key Knowledge
- Molar Mass: Calculated using Ar values (C = 12.0, O = 16.0), giving Mr(CO₂) = 44.0 g mol⁻¹ .
- Avogadro Constant (N_A): 6.02 × 10²³ mol⁻¹ (number of particles in one mole).
- Stoichiometric Ratio: Each individual molecule of CO₂ contains 2 oxygen atoms.
📐 Step-by-Step Calculation
- Find moles of CO₂ molecules:
Moles = Mass / Mr = 88.0 / 44.0 = 2.00 mol - Find moles of oxygen atoms:
Since each CO₂ has 2 oxygen atoms, multiply moles of molecules by 2:
2.00 mol × 2 = 4.00 mol of O atoms - Convert moles of oxygen atoms to number of atoms:
Number of atoms = Moles × Avogadro constant
4.00 × (6.022 × 10²³) = 2.4088 × 10²⁴ - Round to appropriate significant figures:
The input data (88.0 g) is given to 3 significant figures, so round the final answer to 3 s.f. → 2.41 × 10²⁴ .
❌ Common Errors & Examiner Pitfalls
- Forgetting the atom ratio: Many students calculate the number of molecules of CO₂ (which is 1.20 × 10²⁴, Option B) and forget to multiply by 2 for the oxygen atoms.
- Using atomic mass incorrectly: Using incorrect relative atomic masses or mixing up the mass of carbon and oxygen.
- Power of 10 slips: Calculator entry errors involving standard form indices. Always double-check your exponent value.
🧠 Exam Technique & Examiner Commentary
In multiple-choice questions, examiners deliberately include distractors (wrong options) based on common student mistakes. For instance:
- Option B ( 1.20 × 10²⁴ ) traps students who stop after finding the number of CO₂ molecules.
- Option D ( 4.82 × 10²⁴ ) often catches students who accidentally multiply by 4 or miscalculate the Mr.
Top tip: Underline what the question is specifically asking for—in this case, oxygen atoms, not total atoms or molecules!
Topics
Module 2: Foundations in chemistry · 2.1 Atoms and reactions
Question and mark scheme from the OCR A-Level Chemistry examination, AS Breadth in chemistry (01), June 2018. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.