OCR A-Level Chemistry AS Breadth in chemistry (01), June 2018: Question 2

1 mark · Medium difficulty · Multiple Choice

Calculate the number of oxygen atoms in 88.0 g of CO2

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Question

Multiple choice question 2 asking for the number of oxygen atoms in 88.0 g of CO2, with four options A (3.01 x 10^23), B (1.20 x 10^24), C (2.41 x 10^24), and D (4.82 x 10^24).
Question text

2 What is the number of oxygen atoms in 88.0 g of CO2?

A 3.01 × 1023

B 1.20 × 1024

C 2.41 × 1024

D 4.82 × 1024

Your answer [1]

Mark scheme

Show the mark scheme Mark scheme for question 2 showing the correct answer is C, worth 1 mark.

2 C 1

How to answer it

Calculating Number of Specific Atoms from Mass

OCR AS Level Chemistry • Multiple Choice Question

What this question tests

This question assesses your ability to interconvert between mass, moles, and the number of constituent particles (atoms/molecules) using the Avogadro constant, alongside applying correct chemical stoichiometry (the ratio of atoms within a chemical formula).

Question 2: Step-by-Step Breakdown

Determining the number of oxygen atoms in 88.0 g of CO₂

✅ Correct Answer: C

Option C ( 2.41 × 10²⁴ ) is the correct choice because 88.0 g of carbon dioxide contains 2 moles of molecules, which equates to 4 moles of oxygen atoms. Multiplying 4 by the Avogadro constant gives 2.41 × 10²⁴ atoms.

💡 Key Knowledge

  • Molar Mass: Calculated using Ar values (C = 12.0, O = 16.0), giving Mr(CO₂) = 44.0 g mol⁻¹ .
  • Avogadro Constant (N_A): 6.02 × 10²³ mol⁻¹ (number of particles in one mole).
  • Stoichiometric Ratio: Each individual molecule of CO₂ contains 2 oxygen atoms.

📐 Step-by-Step Calculation

  1. Find moles of CO₂ molecules:
    Moles = Mass / Mr = 88.0 / 44.0 = 2.00 mol
  2. Find moles of oxygen atoms:
    Since each CO₂ has 2 oxygen atoms, multiply moles of molecules by 2:
    2.00 mol × 2 = 4.00 mol of O atoms
  3. Convert moles of oxygen atoms to number of atoms:
    Number of atoms = Moles × Avogadro constant
    4.00 × (6.022 × 10²³) = 2.4088 × 10²⁴
  4. Round to appropriate significant figures:
    The input data (88.0 g) is given to 3 significant figures, so round the final answer to 3 s.f. → 2.41 × 10²⁴ .

❌ Common Errors & Examiner Pitfalls

  • Forgetting the atom ratio: Many students calculate the number of molecules of CO₂ (which is 1.20 × 10²⁴, Option B) and forget to multiply by 2 for the oxygen atoms.
  • Using atomic mass incorrectly: Using incorrect relative atomic masses or mixing up the mass of carbon and oxygen.
  • Power of 10 slips: Calculator entry errors involving standard form indices. Always double-check your exponent value.

🧠 Exam Technique & Examiner Commentary

In multiple-choice questions, examiners deliberately include distractors (wrong options) based on common student mistakes. For instance:

  • Option B ( 1.20 × 10²⁴ ) traps students who stop after finding the number of CO₂ molecules.
  • Option D ( 4.82 × 10²⁴ ) often catches students who accidentally multiply by 4 or miscalculate the Mr.

Top tip: Underline what the question is specifically asking for—in this case, oxygen atoms, not total atoms or molecules!

Marks available: [1 mark] — Awarded for selecting option C.

Topics

Module 2: Foundations in chemistry · 2.1 Atoms and reactions

Question and mark scheme from the OCR A-Level Chemistry examination, AS Breadth in chemistry (01), June 2018. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.