OCR A-Level Chemistry AS Breadth in chemistry (01), June 2018: Question 9

1 mark · Medium difficulty · Multiple Choice

Deduce the formula of the chloride of element Y using its first five successive ionisation energies.

Practise this question

Question

Multiple choice question 9 showing a table of the first five successive ionisation energies for element Y: 1st is 496, 2nd is 4563, 3rd is 6913, 4th is 9544, and 5th is 13352 kJ mol-1. Four options for the formula of a chloride of Y are given: A YCl, B YCl2, C YCl3, and D YCl4. A box for the student's answer is at the bottom left.
Question text

9 The first five successive ionisation energies of an element Y are shown below.

1st 2nd 3rd 4th 5th

496 4563 6913 9544 13352

What is the formula of a chloride of Y?

A YCl

B YCl2

C YCl3

D YCl4

Your answer [1]

Mark scheme

Show the mark scheme Mark scheme indicating the correct answer for question 9 is option A.

9 A 1

How to answer it

Successive Ionisation Energies & Formula Determination

What this question tests

This question assesses your understanding of successive ionisation energies, how to identify an element's group number from a table of ionisation energy data, and how to use valency/oxidation states to deduce the chemical formula of an ionic or binary chloride compound.

Question 9 (Multiple Choice)

Determining the formula of a chloride from ionisation energies

✅ Correct Answer

A: YCl

Element Y is in Group 1 because the huge jump in ionisation energy occurs between the 1st and 2nd values. Group 1 elements form ions with a +1 charge, combining with chloride ions (Cl⁻) in a 1:1 ratio.

💡 Key Knowledge

  • Successive Ionisation Energies: Removing each subsequent electron requires more energy because the remaining electrons are pulled closer to the increasingly positive nucleus.
  • Identifying Groups: A massive, abrupt increase in ionisation energy indicates that an electron is being removed from a new, inner shell closer to the nucleus.
  • Group 1 Clues: If the 1st IE is relatively low and the 2nd IE shows a massive jump, the element has 1 valence electron and belongs to Group 1 (e.g., Sodium, Potassium).

🧠 Exam Technique

  • Scan the data row from left to right and look for the biggest jump in magnitude.
  • Here, values go: 496 → 4563 (approx. a 9-fold increase!). Subsequent increases (4563 to 6913) are steady shell-filling increases.
  • The jump occurs after the 1st electron is removed, meaning the 1st electron was the only valence electron in the outer shell. Therefore, element Y is in Group 1.
  • Group 1 elements form Y⁺ ions, reacting with Cl⁻ to make YCl .

❌ Common Errors

  • Miscounting the jump: Students sometimes confuse a steady increase across a shell with a shell change, or misinterpret which electron number corresponds to the inner shell breach.
  • Defaulting to Group 2: Seeing multiple numbers makes students guess YCl₂ out of habit. Always check where the largest multiplicative leap occurs.
  • Formula writing slip: Even when correctly identifying Group 1, students occasionally misapply valency rules for chlorides.
Mark Scheme Allocation: 1 mark for selecting option A.

Topics

Module 2: Foundations in chemistry · Module 3: Periodic table and energy · 2.1 Atoms and reactions · 2.2 Electrons, bonding and structure · 3.1 The periodic table

Question and mark scheme from the OCR A-Level Chemistry examination, AS Breadth in chemistry (01), June 2018. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.