OCR A-Level Chemistry Periodic table, elements and physical chemistry (01), June 2025: Question 10
1 mark · Medium difficulty · Multiple Choice
Identify the correct half-equation at the positive electrode of an alkaline hydrogen-oxygen fuel cell.
Practise this questionQuestion
Mark scheme
Show the mark scheme
How to answer it
Alkaline Hydrogen–Oxygen Fuel Cell Half-Equations
This question assesses your understanding of redox chemistry in fuel cells under alkaline conditions. Specifically, it tests your ability to deduce an electrode half-equation given the overall cell reaction and the complementary half-equation, while checking for charge and atom balance.
Electrode Half-Equation at the Positive Electrode (Cathode)
Identifying the reduction half-equation for oxygen in an alkaline electrolyte
✅ Correct Answer
C: ½O₂(g) + H₂O(l) + 2e⁻ → 2OH⁻(aq)
💡 Key Knowledge
- Electrode polarities: In an electrochemical/fuel cell:
- Negative electrode (anode): Site of oxidation (electron release).
- Positive electrode (cathode): Site of reduction (electron uptake).
- Alkaline conditions: The presence of OH⁻(aq) in the negative electrode equation confirms the electrolyte is alkaline, meaning the positive electrode must consume O₂ and produce OH⁻.
- Conservation of mass & charge: Summing both half-equations must yield the overall equation with electrons cancelling out.
📐 Step-by-Step Deduction Method
- Identify the process at the positive electrode:
The negative electrode undergoes oxidation: H₂(g) + 2OH⁻(aq) → 2H₂O(l) + 2e⁻ .
Therefore, reduction must occur at the positive electrode, meaning electrons ( e⁻ ) must appear on the left-hand side (reactants). This immediately eliminates options A and B. - Set up the algebraic cancellation:
Let the unknown half-equation be added to the negative electrode half-equation to give the overall equation:
Negative: H₂(g) + 2OH⁻(aq) → 2H₂O(l) + 2e⁻
+ Positive: [ ? ]
Overall: H₂(g) + ½O₂(g) → H₂O(l) - Determine required reactants and products:
To eliminate 2e⁻ on the right, the positive half-equation must consume 2e⁻ on the left.
To provide ½O₂ on the reactant side, ½O₂ must be on the left.
To cancel 2OH⁻ on the left, 2OH⁻ must be produced on the right.
To net H₂O(l) on the right (from 2H₂O ), one H₂O must be on the left:
½O₂(g) + H₂O(l) + 2e⁻ → 2OH⁻(aq) - Verify atom and charge balance:
Left: 1 O (from ½O₂) + 1 O (from H₂O) = 2 O; 2 H; charge = -2.
Right: 2 O; 2 H; charge = 2 × (-1) = -2. (Perfect match → C).
🧠 Exam Technique & Speed Tactics
- Quick charge check: Check which options are even balanced!
- In B: LHS charge is 0; RHS charge is -2 + (-2) = -4. Not balanced!
- In A: LHS charge is 0; RHS charge is -2. Not balanced!
- By simply checking charge neutrality on both sides, options A and B are instantly eliminated in seconds without even looking at fuel cell chemistry!
- Option D needlessly includes H₂ on the reactant side—hydrogen is already supplied and oxidised at the negative electrode, not the positive.
❌ Common Student Traps
- Confusing Acidic vs Alkaline Fuel Cells: In acidic fuel cells, the positive electrode equation is ½O₂ + 2H⁺ + 2e⁻ → H₂O . Memorising only the acidic version leads to panic when seeing OH⁻ . Always inspect the electrolyte species provided!
- Wrong side for electrons: Forgetting that reduction is gain of electrons (OIL RIG), which means electrons must be reactants at the positive cathode.
- Mixing fuel inputs: Selecting options that combine H₂ and O₂ on the same electrode (as in A and D). Fuel cells keep fuel and oxidant separated at different electrodes.
Topics
Module 5: Physical chemistry and transition elements · 5.2 Energy
Question and mark scheme from the OCR A-Level Chemistry examination, Periodic table, elements and physical chemistry (01), June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.