AQA A-Level Chemistry Paper 3, June 2025: Question 6
6 marks · Medium difficulty · State/Explain/Numerical
Identify stereoisomerism in a triglyceride from rapeseed oil, determine double bond locants and stereoisomer counts for methyl esters, and state products and uses of saponification and transesterification.
Practise this questionQuestion
Question text
06 This question is about rapeseed oil.
Figure 2 shows the structure of compound Q found in rapeseed oil. Each branch in
the molecule is formed from a different long-chain carboxylic acid.
Figure 2
06.1 State the type of stereoisomerism shown in Branch A.
[1 mark]
06.2 Q can be reacted with methanol to form three different esters.
State the number used to identify the position of the C=C bond in the name of the
ester formed from Branch A.
State the number of different stereoisomers of the ester formed from Branch B.
Give a use for these esters.
[3 marks]
Number used in the name of the ester
Number of stereoisomers
Use for esters
06.3 Q also reacts with NaOH
State the formula of the product, formed by Branch B in Figure 2, in this reaction.
State a use for this product.
[2 marks]
Formula
Use for product
Section B
Answer all questions in this section.
Only one answer per question is allowed.
For each question completely fill in the circle alongside the appropriate answer.
CORRECT METHOD WRONG METHODS
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as shown.
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Mark scheme
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Question Answers Additional comments/Guidelines Mark
06.1 E-Z (isomerism) ALLOW Z / geometric / cis-trans / cis
(1 x AO1)
M1 9
06.2 M2 four (1 x AO1,
2 x AO3)
M3 biodiesel / biofuel
M1 C H O Na / C H COONa ALLOW C H O – / C H COO–
18 31 2 17 31 18 31 2 17 31
ALLOW any unambiguous formula/structure
ALLOW CHCH for CH=CH in structural formula
06.3 (1 x AO1,
NOT O–Na i.e. covalent bond between O & Na
1 x AO2)
M2 soaps / anionic surfactant NOT cationic surfactant / detergents / shampoo
How to answer it
Triglycerides: Stereoisomerism, Biodiesel & Saponification
This question assesses your understanding of lipid chemistry, specifically:
- Identifying forms of stereoisomerism in unsaturated aliphatic chains.
- Systematic numbering of long-chain fatty acids starting from the carbonyl carbon ( C-1 ).
- Calculating possible stereoisomers using the 2ⁿ rule for multiple double bonds.
- Industrial applications of transesterification (making biodiesel).
- Base-catalysed hydrolysis (saponification) of triglycerides to produce carboxylate salts (soap) and avoiding covalent bond errors.
Type of Stereoisomerism in Branch A
Identifying isomerism around the carbon-carbon double bond
✅ Correct Answer
- E-Z (isomerism)
💡 Key Knowledge
Two essential conditions give rise to E-Z stereoisomerism in unsaturated fatty acid tails:
- Restricted rotation about the planar C=C double bond.
- Two different groups attached to each carbon of the C=C bond (in Branch A, each alkene carbon has a –H and an alkyl chain).
Transesterification with Methanol: IUPAC Locants, Isomer Count & Uses
Analysis of Branch A & Branch B Methyl Esters
✅ Correct Answers
- Number in ester name: 9 [1 mark]
- Number of stereoisomers: 4 (or four) [1 mark]
- Use for these esters: biodiesel / biofuel [1 mark]
📐 Step-by-Step Chain Counting
1. Locant of the C=C bond (Branch A):
- Carbonyl carbon ( C=O ) is always C-1.
- Follow the chain: there are 7 methylene groups: –(CH₂)₇– (Carbons 2 to 8).
- The first alkene carbon encountered is therefore carbon number 9.
2. Stereoisomers for Branch B:
- Branch B contains 2 separate C=C double bonds ( n = 2 ).
- Each alkene centre independently exhibits E or Z geometry.
- Total possible stereoisomers = 2ⁿ = 2² = 4 ((E,E), (E,Z), (Z,E), (Z,Z)).
🧠 Exam Technique: Industrial Uses
Reacting vegetable oils (triglycerides) with methanol in the presence of a strong base catalyst (e.g. KOH/NaOH) yields a mixture of fatty acid methyl esters (FAME) and propane-1,2,3-triol (glycerol).
Whenever you see a triglyceride reacted with methanol or ethanol, think biodiesel production.
❌ Common Errors
- Counting backwards: Counting from the hydrocarbon methyl end gives 9 purely by coincidence here, but in other fatty acids this leads to incorrect locants. Always count from the ester carbonyl group as C-1!
- Vague uses: Writing general terms like "fuel" or "petrol" instead of the specific syllabus keyword biodiesel or biofuel.
Alkaline Hydrolysis (Saponification) of Branch B
Deducing carboxylate formula and product application
✅ Correct Answers
- Formula: C₁₇H₃₁COONa or C₁₈H₃₁O₂Na [1 mark]
- Use: soap / anionic surfactant [1 mark]
• ALLOW carboxylate ion alone: C₁₇H₃₁COO⁻ or C₁₈H₃₁O₂⁻
• ALLOW any unambiguous structural formula (e.g. condensed formula).
• NOT ALLOWED: Covalent bond between O and Na ( O–Na ).
• NOT ALLOWED for use: Cationic surfactant, detergents, shampoo.
📐 Deducing the Molecular Formula
Count the atoms in fatty acid tail B:
- Carboxyl carbon: 1 C ( C=O )
- Aliphatic spacer: 7 × CH₂ = 7 C, 14 H
- First alkene: CH=CH = 2 C, 2 H
- Methylene link: CH₂ = 1 C, 2 H
- Second alkene: CH=CH = 2 C, 2 H
- Aliphatic tail: 4 × CH₂ + CH₃ = 5 C, 11 H
- Total: 18 Carbons, 31 Hydrogens, 2 Oxygens, 1 Sodium
- Formula written as a salt: C₁₇H₃₁COONa or C₁₈H₃₁O₂Na
❌ Critical Trap: Covalent O–Na Bond
Never draw a bond line between O and Na!
Sodium carboxylates are ionic lattices/salts in aqueous media. A line indicates a shared electron pair (covalent bond). Drawing –C–O–Na will automatically forfeit the mark.
Always write it as either –COONa or with explicit charges: –COO⁻ Na⁺ .
💡 Soap vs Detergents
- Alkaline hydrolysis of fats produces carboxylate salts ( RCOO⁻Na⁺ ), which are traditional soaps (anionic surfactants).
- Synthetic detergents are typically derived from sulfonate salts ( RSO₃⁻Na⁺ ) or quaternary ammonium salts (cationic surfactants used in hair conditioners), not natural saponification products.
Topics
Organic Chemistry · 3.3.1 Introduction to Organic Chemistry · 3.3.9 Carboxylic Acids and Derivatives
Question and mark scheme from the AQA A-Level Chemistry examination, Paper 3, June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.