AQA A-Level Chemistry Paper 3, June 2025: Question 6

6 marks · Medium difficulty · State/Explain/Numerical

Identify stereoisomerism in a triglyceride from rapeseed oil, determine double bond locants and stereoisomer counts for methyl esters, and state products and uses of saponification and transesterification.

Practise this question

Question

Question 06 shows the skeletal structure of compound Q, a triglyceride from rapeseed oil with glycerol linked via ester bonds to three unsaturated long-chain fatty acid chains labelled Branch A, Branch B, and Branch C. Part 06.1 asks for the type of stereoisomerism shown in Branch A. Part 06.2 asks for the position number of the C=C bond in the methyl ester from Branch A, the total number of stereoisomers for the ester from Branch B, and a use for these methyl esters. Part 06.3 asks for the formula and use of the sodium salt formed when Branch B reacts with sodium hydroxide.
Question text

06 This question is about rapeseed oil.

Figure 2 shows the structure of compound Q found in rapeseed oil. Each branch in

the molecule is formed from a different long-chain carboxylic acid.

Figure 2

06.1 State the type of stereoisomerism shown in Branch A.

[1 mark]

06.2 Q can be reacted with methanol to form three different esters.

State the number used to identify the position of the C=C bond in the name of the

ester formed from Branch A.

State the number of different stereoisomers of the ester formed from Branch B.

Give a use for these esters.

[3 marks]

Number used in the name of the ester

Number of stereoisomers

Use for esters

06.3 Q also reacts with NaOH

State the formula of the product, formed by Branch B in Figure 2, in this reaction.

State a use for this product.

[2 marks]

Formula

Use for product

Section B

Answer all questions in this section.

Only one answer per question is allowed.

For each question completely fill in the circle alongside the appropriate answer.

CORRECT METHOD WRONG METHODS

If you want to change your answer you must cross out your original answer as shown.

If you wish to return to an answer previously crossed out, ring the answer you now wish to select

as shown.

You may do your working in the blank space around each question but this will not be marked.

Do not use additional sheets for this working.

Mark scheme

Show the mark scheme Mark scheme for Question 06: 06.1 awards 1 mark for E-Z (isomerism), allowing Z, geometric, cis-trans, or cis. 06.2 awards 3 marks: M1 for 9, M2 for four, and M3 for biodiesel or biofuel. 06.3 awards 2 marks: M1 for C18H31O2Na or C17H31COONa (allowing carboxylate ion, denying covalent O-Na), and M2 for soaps or anionic surfactant.

Question Answers Additional comments/Guidelines Mark

06.1 E-Z (isomerism) ALLOW Z / geometric / cis-trans / cis

(1 x AO1)

M1 9

06.2 M2 four (1 x AO1,

2 x AO3)

M3 biodiesel / biofuel

M1 C H O Na / C H COONa ALLOW C H O – / C H COO–

18 31 2 17 31 18 31 2 17 31

ALLOW any unambiguous formula/structure

ALLOW CHCH for CH=CH in structural formula

06.3 (1 x AO1,

NOT O–Na i.e. covalent bond between O & Na

1 x AO2)

M2 soaps / anionic surfactant NOT cationic surfactant / detergents / shampoo

How to answer it

Triglycerides: Stereoisomerism, Biodiesel & Saponification

WHAT THIS QUESTION TESTS

This question assesses your understanding of lipid chemistry, specifically:

  • Identifying forms of stereoisomerism in unsaturated aliphatic chains.
  • Systematic numbering of long-chain fatty acids starting from the carbonyl carbon ( C-1 ).
  • Calculating possible stereoisomers using the 2ⁿ rule for multiple double bonds.
  • Industrial applications of transesterification (making biodiesel).
  • Base-catalysed hydrolysis (saponification) of triglycerides to produce carboxylate salts (soap) and avoiding covalent bond errors.
QUESTION 06.1

Type of Stereoisomerism in Branch A

Identifying isomerism around the carbon-carbon double bond

✅ Correct Answer

  • E-Z (isomerism)
Mark Scheme notes: ALLOW Z / geometric / cis-trans / cis [1 mark, AO1].

💡 Key Knowledge

Two essential conditions give rise to E-Z stereoisomerism in unsaturated fatty acid tails:

  1. Restricted rotation about the planar C=C double bond.
  2. Two different groups attached to each carbon of the C=C bond (in Branch A, each alkene carbon has a –H and an alkyl chain).
QUESTION 06.2

Transesterification with Methanol: IUPAC Locants, Isomer Count & Uses

Analysis of Branch A & Branch B Methyl Esters

✅ Correct Answers

  • Number in ester name: 9 [1 mark]
  • Number of stereoisomers: 4 (or four) [1 mark]
  • Use for these esters: biodiesel / biofuel [1 mark]

📐 Step-by-Step Chain Counting

1. Locant of the C=C bond (Branch A):

  • Carbonyl carbon ( C=O ) is always C-1.
  • Follow the chain: there are 7 methylene groups: –(CH₂)₇– (Carbons 2 to 8).
  • The first alkene carbon encountered is therefore carbon number 9.

2. Stereoisomers for Branch B:

  • Branch B contains 2 separate C=C double bonds ( n = 2 ).
  • Each alkene centre independently exhibits E or Z geometry.
  • Total possible stereoisomers = 2ⁿ = 2² = 4 ((E,E), (E,Z), (Z,E), (Z,Z)).

🧠 Exam Technique: Industrial Uses

Reacting vegetable oils (triglycerides) with methanol in the presence of a strong base catalyst (e.g. KOH/NaOH) yields a mixture of fatty acid methyl esters (FAME) and propane-1,2,3-triol (glycerol).

Whenever you see a triglyceride reacted with methanol or ethanol, think biodiesel production.

❌ Common Errors

  • Counting backwards: Counting from the hydrocarbon methyl end gives 9 purely by coincidence here, but in other fatty acids this leads to incorrect locants. Always count from the ester carbonyl group as C-1!
  • Vague uses: Writing general terms like "fuel" or "petrol" instead of the specific syllabus keyword biodiesel or biofuel.
QUESTION 06.3

Alkaline Hydrolysis (Saponification) of Branch B

Deducing carboxylate formula and product application

✅ Correct Answers

  • Formula: C₁₇H₃₁COONa or C₁₈H₃₁O₂Na [1 mark]
  • Use: soap / anionic surfactant [1 mark]
Mark scheme guidance:
• ALLOW carboxylate ion alone: C₁₇H₃₁COO⁻ or C₁₈H₃₁O₂⁻
• ALLOW any unambiguous structural formula (e.g. condensed formula).
• NOT ALLOWED: Covalent bond between O and Na ( O–Na ).
• NOT ALLOWED for use: Cationic surfactant, detergents, shampoo.

📐 Deducing the Molecular Formula

Count the atoms in fatty acid tail B:

  • Carboxyl carbon: 1 C ( C=O )
  • Aliphatic spacer: 7 × CH₂ = 7 C, 14 H
  • First alkene: CH=CH = 2 C, 2 H
  • Methylene link: CH₂ = 1 C, 2 H
  • Second alkene: CH=CH = 2 C, 2 H
  • Aliphatic tail: 4 × CH₂ + CH₃ = 5 C, 11 H
  • Total: 18 Carbons, 31 Hydrogens, 2 Oxygens, 1 Sodium
  • Formula written as a salt: C₁₇H₃₁COONa or C₁₈H₃₁O₂Na

❌ Critical Trap: Covalent O–Na Bond

Never draw a bond line between O and Na!

Sodium carboxylates are ionic lattices/salts in aqueous media. A line indicates a shared electron pair (covalent bond). Drawing –C–O–Na will automatically forfeit the mark.

Always write it as either –COONa or with explicit charges: –COO⁻ Na⁺ .

💡 Soap vs Detergents

  • Alkaline hydrolysis of fats produces carboxylate salts ( RCOO⁻Na⁺ ), which are traditional soaps (anionic surfactants).
  • Synthetic detergents are typically derived from sulfonate salts ( RSO₃⁻Na⁺ ) or quaternary ammonium salts (cationic surfactants used in hair conditioners), not natural saponification products.

Topics

Organic Chemistry · 3.3.1 Introduction to Organic Chemistry · 3.3.9 Carboxylic Acids and Derivatives

Question and mark scheme from the AQA A-Level Chemistry examination, Paper 3, June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.