AQA GCSE Combined Science: Trilogy Biology Paper 1 (Higher), June 2025: Question 3

9 marks · Standard Demand difficulty · Short Answer

Analyze an investigation into the effect of light intensity and temperature on the rate of photosynthesis in pondweed using the inverse square law and collision theory.

Practise this question

Question

The question shows an experiment measuring the rate of photosynthesis of pondweed. Figure 3 illustrates pondweed under an inverted funnel inside a beaker containing water at 10 °C, topped with an inverted measuring cylinder to collect oxygen bubbles, positioned at various distances along a metre rule from a lamp. Figure 4 shows a graph plotting rate of oxygen production in cm³ per hour on the y-axis against distance between lamp and pondweed in cm on the x-axis, demonstrating a non-linear decrease from 3.6 at 10 cm to 0.1 at 60 cm. Sub-questions ask: 03.1 to select the most accurate measuring cylinder; 03.2 to calculate and explain the change in light intensity when distance is doubled using the inverse square law and graph data; 03.3 to explain how repeating at 20 °C affects the results; and 03.4 to explain how repeating at 80 °C affects the results.
Question text

03 Photosynthesis is important for plant growth.

A student used pondweed to investigate the rate of photosynthesis.

Figure 3 shows the apparatus used.

Figure 3

This is the method used.

1. Set up the apparatus as shown in Figure 3.

2. Switch on the lamp.

3. After 2 hours, record the volume of oxygen collected in the measuring cylinder.

4. Repeat steps 1 to 3 a further five times, increasing the distance between the lamp

and the pondweed each time.

5. Calculate the rate of oxygen production for each distance.

Figure 4 shows the results.

Figure 4

03.1 Which measuring cylinder should the student have used to give the most

accurate results?

[1 mark]

Tick ( ) one box.

10 cm3 measuring cylinder with intervals of 0.1 ± 0.01 cm3

10 cm3 measuring cylinder with intervals of 0.2 ± 0.01 cm3

20 cm3 measuring cylinder with intervals of 0.1 ± 0.02 cm3

20 cm3 measuring cylinder with intervals of 0.2 ± 0.02 cm3

03.2 Light intensity can be calculated using the inverse square law.

The equation shows the inverse square law.

light intensity ∝ 2

(distance from light source)

Explain how light intensity changed as the distance of the pondweed from the light

source was doubled.

Include calculations in your answer.

Use data from Figure 4.

[3 marks]

The student did the investigation at 10 °C.

The student repeated the investigation at 20 °C and again at 80 °C.

03.3 Explain how repeating the investigation at 20 °C would affect the results.

[3 marks]

03.4 Explain how repeating the investigation at 80 °C would affect the results.

[2 marks]

Mark scheme

Show the mark scheme The mark scheme lists answers for parts 03.1 to 03.4: 03.1 awards 1 mark for '10 cm³ measuring cylinder with intervals of 0.1 ± 0.01 cm³'. 03.2 awards 3 marks: 1 for evidence of squaring two doubled distances, 1 for calculating 1/d² for both, and 1 for stating light intensity is quartered. 03.3 awards 3 marks: rate of oxygen production increases, particles/enzymes have greater kinetic energy, and collisions are more frequent. 03.4 awards 2 marks: no/less oxygen produced because enzymes are denatured.

Question 3

AO /

Question Answers Extra information Mark

Spec. Ref.

03.1 10 cm3 measuring cylinder with 1 AO1

intervals of 0.1 ± 0.01 cm3 4.4.1.2

RPA5

AO /

Spec. Ref.

03.2 evidence of squaring allow other appropriate values 1 AO2

for two distances that double: throughout 4.4.1.2

(10 cm and 20 cm) RPA5

100 and 400

or

(20 cm and 40 cm)

400 and 1600

or

(30 cm and 60 cm)

900 and 3600

calculate 1/d2 for two distances 1

that double:

(10 cm and 20 cm)

0.01 / and 0.0025 /

100 400

or

(20 cm and 40 cm)

11 allow 2 marks for these

0.0025 / and 0.000625 / values without working

400 1600

or

(30 cm and 60 cm)

0.001(11…) /

and 0.00027(77…) /

3600

(therefore as distance doubles) 1

light intensity is quartered

AO /

Spec. Ref.

03.3 the rate of oxygen production allow rate of photosynthesis 1 AO3

increases increases

ignore the volume of oxygen

production increases unqualified

(because) reactants / particles / allow reactants / particles / 1 AO2

molecules / enzymes have molecules / enzymes move

greater (kinetic) energy faster 13

(so) collisions are more frequent allow (so) more collisions in a 1 AO2

given time

allow (so) more successful

collisions 4.2.2.1

4.4.1.2

AO /

Spec. Ref.

03.4 no / less oxygen (is produced) allow photosynthesis is stopped 1 AO3

/ reduced

allow the rate of oxygen

production is 0 (cm3/hour)

(because) enzymes are allow the enzymes are 1 AO2

destroyed denatured

allow active site has changed

shape 4.2.2.1

do not accept the cells / plant / 4.4.1.2

pondweed is denatured

do not accept the enzymes are

killed

Total Question 3 9

How to answer it

Photosynthesis Practical: Light Intensity & Temperature

What this question tests

This question evaluates your practical and theoretical understanding of AQA Biology Required Practical 5 (Photosynthesis):

  • Selecting measuring apparatus for resolution, precision, and accuracy.
  • Applying mathematical relationships: calculating light intensity changes using the Inverse Square Law ( 1/d² ).
  • Explaining rate changes with temperature using kinetic theory and enzyme denaturation.
Part 03.1 • 1 Mark

Apparatus Precision & Accuracy

Selecting the most appropriate measuring cylinder

✅ Correct Answer

10 cm³ measuring cylinder with intervals of 0.1 ± 0.01 cm³

💡 Key Knowledge

The total volume of gas collected in 2 hours is around 7.2 cm³ (since the peak rate is 3.6 cm³/hour). A 10 cm³ cylinder has sufficient capacity without being oversized.

Intervals of 0.1 cm³ offer higher resolution (smaller scale divisions) and an uncertainty of only ± 0.01 cm³, minimising measurement errors.

❌ Common Errors

Choosing the 20 cm³ cylinder because it is "bigger". In science, choosing a container far larger than needed reduces resolution and makes readings less accurate.

🧠 Exam Technique

Always pick measuring equipment that:

  • Accommodates the maximum expected volume.
  • Has the smallest scale divisions (finest resolution).
  • Shows the smallest margin of uncertainty (± value).
Mark breakdown: [1 mark] for selecting the first checkbox option only.
Part 03.2 • 3 Marks

The Inverse Square Law

Explaining changes in light intensity as distance doubles

📐 Step-by-Step Calculation

Step 1: Choose any two distances from Figure 4 where distance doubles
For example: d₁ = 10 cm and d₂ = 20 cm (or 20 cm and 40 cm, or 30 cm and 60 cm).
Step 2: Square both distances (Mark 1)
10² = 100  and  20² = 400
Step 3: Calculate relative light intensity using 1/d² (Mark 2)
At 10 cm: 1 / 100 = 0.01 (or 1/100)
At 20 cm: 1 / 400 = 0.0025 (or 1/400)
Step 4: State how the intensity changes (Mark 3)
Compare values: 0.0025 ÷ 0.01 = 1/4
Therefore, as distance doubles, light intensity quarters (or decreases by a factor of 4).

🧠 Top Tip for Full Marks

The prompt explicitly asks to "include calculations". Stating only that "light intensity quarters" without showing the squared distances or the 1/d² values will cost you 2 out of the 3 marks!

❌ Common Errors

  • Saying light intensity "halves" because distance doubles (ignoring the square relationship).
  • Using rate values directly from the y-axis instead of using the formula 1/d² as instructed.
Mark breakdown: [1 mark] for squaring two doubling distances + [1 mark] for calculating 1/d² values + [1 mark] for stating intensity is quartered.
Part 03.3 • 3 Marks

Effect of Increasing Temperature to 20 °C

Collision theory and enzyme activity

✅ Model Answer

  • The rate of oxygen production increases (or rate of photosynthesis increases).
  • Reactants, particles, and enzymes gain greater kinetic energy (move faster).
  • Resulting in more frequent collisions (or more successful collisions per second).

💡 Why 20 °C Increases Rate

Photosynthesis is controlled by enzymes. At 10 °C, the enzymes have low kinetic energy. Raising temperature to 20 °C brings it closer to the optimum temperature, speeding up enzyme-substrate collisions without causing denaturation.

❌ Common Misconceptions

  • Writing "more oxygen is produced" unqualified without mentioning rate or per hour.
  • Saying "more collisions occur" without specifying frequency ("more collisions per second" or "more frequent collisions").

🧠 Exam Technique: Rate vs Total

Always refer to the rate of oxygen production. A plant at 10 °C could eventually make the same total volume of oxygen if left long enough; what changes is how fast it makes it.

Mark breakdown: [1 mark] for rate increases + [1 mark] for particles have more kinetic energy / move faster + [1 mark] for more frequent collisions.
Part 03.4 • 2 Marks

Effect of Extreme Temperature (80 °C)

Enzyme denaturation

✅ Model Answer

  • No oxygen is produced (rate falls to 0 / photosynthesis stops).
  • Because the photosynthetic enzymes are denatured (their active site has changed shape).

❌ Forbidden Phrasing (Zero Marks)

  • "Enzymes are killed" → NEVER say this! Enzymes are biological catalysts (protein molecules), not living organisms.
  • "The plant / pondweed / cells are denatured" → Only proteins / enzymes denature, not whole organisms or cells.
Mark breakdown: [1 mark] for no oxygen produced / rate drops to zero + [1 mark] for enzymes denatured (or active site changes shape).

Topics

Biology · B4: Bioenergetics · B2: Organisation

Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Biology Paper 1 (Higher), June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.