AQA GCSE Combined Science: Trilogy Biology Paper 1 (Higher), June 2025: Question 4
10 marks · Standard Demand difficulty · Short Answer
Explain osmosis in potato tissue, analyze the effect of surface area on percentage mass increase, and describe modifications to investigate salt concentration.
Practise this questionQuestion
Question text
04 A student investigated the effect of surface area on the mass of potato pieces
placed in water.
This is the method used.
1. Cut 5 cylinders from one potato. Cut each cylinder to a length of 3 cm.
2. Cut 4 of the cylinders into different numbers of pieces.
3. Dry each piece of potato on a paper towel.
4. Record the mass of each group of potato pieces.
5. Put each group of potato pieces into different beakers containing distilled water as
shown in Figure 5.
6. After 30 minutes remove and dry each group of potato pieces.
7. Record the mass of each group of potato pieces.
8. Calculate the percentage increase in mass for each group of potato pieces.
Figure 5
Table 1 shows the results.
Table 1
Total surface area of Percentage (%)
Beaker 2
potato pieces in cm increase in mass
A 7.4 4.4
B 8.1 4.9
C 8.9 5.3
D 9.7 5.5
E 10.5 5.6
04.1 Why is it more valid to calculate the percentage increase in mass rather than
using the increase in mass?
[1 mark]
04.2 Describe the relationship between total surface area and percentage increase
in mass.
Use Table 1.
[2 marks]
04.3 Explain why the potato pieces increased in mass.
[2 marks]
04.4 The student repeated the investigation.
The potato pieces were in the beakers of distilled water for 24 hours.
Explain what results would be expected after leaving the investigation set up
for 24 hours.
[3 marks]
04.5 The method used is repeated below.
1. Cut 5 cylinders from one potato. Cut each cylinder to a length of 3 cm.
2. Cut 4 of the cylinders into different numbers of pieces.
3. Dry each piece of potato on a paper towel.
4. Record the mass of each group of potato pieces.
5. Put each group of potato pieces into different beakers containing distilled water as
shown in Figure 5 on page 13.
6. After 30 minutes, remove and dry each group of potato pieces.
7. Record the mass of each group of potato pieces.
*158. Calculate the percentage increase in mass* for each group of potato pieces.
A different student wanted to investigate the effect of salt concentration on
potato tissue.
Describe how the student could change the method to investigate the effect of salt
concentration on potato tissue.
[2 marks]
Mark scheme
Show the mark scheme
Question 4
AO /
Question Answers Extra information Mark
Spec. Ref.
04.1 (takes account of) different ignore were not all the same 1 AO2
starting masses size 4.1.3.2
do not accept as a control RPA2
variable
AO /
Spec. Ref.
04.2 as (total) surface area increases allow as one increases, so does 1 AO2
percentage increase in mass the other 4.1.3.2
increases allow there is a positive
correlation
by a decreasing amount allow description of decreasing 1
amount of increase
do not accept they are directly
proportional
AO /
Spec. Ref.
04.3 water moved in by osmosis allow water moved in by 1 AO1
diffusion 4.1.3.2
do not accept (water moves) by RPA2
active transport
(because water moves) allow (because water moves) 1
from a dilute solution to a from a high(er) concentration of
concentrated solution (inside the water to a low(er) concentration
cell / potato) of water (inside the cell / potato)
allow (because water moves)
from a high(er) water potential to
a low(er) water potential (inside
the cell / potato)
allow (because water moves)
from a lower concentration (of
solute) to a higher concentration
(of solute inside the cell / potato)
allow (because water moves)
down its concentration gradient
do not accept water moves
along / across a concentration
gradient
AO / 15
Spec. Ref.
04.4 all the (groups of) potato pieces 1 AO2
had the same percentage
change in mass
(because the) cell walls are allow cells are turgid 1 AO3
completely stretched
(so) the cells cannot absorb any 1 AO3
more water
4.1.3.2
RPA 2
AO /
Spec. Ref.
04.5 (change the independent 1 AO3
variable to) different 4.1.3.2
concentrations of salt solution RPA2
do not cut the potato into pieces allow control the surface area of 1
the potato
allow cut into the same number
of pieces
ignore use the same shape /
size
Total Question 4 10
How to answer it
Potato Osmosis & Surface Area Practical
This question assesses core concepts from AQA GCSE Biology / Combined Science Required Practical 2:
- Understanding why percentage change in mass is used to control for variable starting masses.
- Describing non-linear relationships and data trends from a practical results table.
- Explaining the mechanism and direction of water movement via osmosis.
- Predicting long-term equilibrium when plant cells reach full turgidity.
- Modifying experimental design when investigating a new independent variable (solute concentration).
Why calculate percentage increase rather than raw increase in mass?
Evaluating Experimental Validity
✅ Correct Answer
To take account of the different starting masses of the potato groups (allows a valid comparison).
❌ Common Errors
- Vague answers like "to make it a fair test" (scores 0).
- Writing "they were not all the same size" without explicitly mentioning mass.
- Claiming mass is a "control variable".
Relationship between total surface area and percentage increase in mass
Data Interpretation (Table 1)
✅ Correct Answer
- Mark 1: As the total surface area increases, the percentage increase in mass increases (positive correlation).
- Mark 2: It increases by a decreasing amount (the rate of increase slows down / begins to level off).
📐 Data Evidence from Table 1
- 7.4 to 8.1 cm² → increase of +0.5% (4.4 → 4.9)
- 8.1 to 8.9 cm² → increase of +0.4% (4.9 → 5.3)
- 8.9 to 9.7 cm² → increase of +0.2% (5.3 → 5.5)
- 9.7 to 10.5 cm² → increase of +0.1% (5.5 → 5.6)
🧠 Exam Technique
For 2-mark trend questions, look past the general rule ("as X goes up, Y goes up"). Always look at the differences between values to see if the change is constant, accelerating, or decreasing.
❌ Common Errors
Do not say they are "directly proportional". Directly proportional means doubling surface area exactly doubles the mass increase and the line passes through (0,0), which is not true here.
Explain why the potato pieces increased in mass
Scientific Explanation of Osmosis
✅ Correct Answer
- Mark 1: Water moved in by osmosis.
- Mark 2: Water moved from a dilute solution (distilled water outside) to a more concentrated solution (inside the potato cells)
OR from a higher concentration of water to a lower concentration of water.
💡 Key Knowledge
Osmosis Definition: The net movement of water molecules from a dilute solution (higher water potential) to a more concentrated solution (lower water potential) across a partially permeable membrane.
🧠 Exam Technique
Always state the direction of movement and specify where the dilute and concentrated solutions are located (e.g., "distilled water is dilute, potato cytoplasm is concentrated").
❌ Common Errors
- Saying water moves by "active transport" (scores 0).
- Saying water moves "along" or "across" a concentration gradient instead of down its concentration gradient.
- Confusing solute concentration with water concentration.
Expected results after leaving set up for 24 hours
Equilibrium & Cell Turgidity
✅ Correct Answer
- Mark 1: All the potato groups would have the same percentage change in mass.
- Mark 2: Because the plant cells become fully turgid (cell walls are completely stretched).
- Mark 3: So the cells cannot absorb any more water.
💡 Key Knowledge
Surface area alters the rate of osmosis, not the final equilibrium position. Over 30 minutes, higher surface area means faster uptake. Over 24 hours, all pieces have reached their absolute capacity and become fully turgid.
🧠 Exam Technique: Rate vs. Final Endpoint
When an experiment runs for a very long time (like 24 hours), think about the biological limit: the rigid cellulose cell wall prevents plant cells from taking in more water once maximum turgor pressure is reached.
❌ Common Errors
- Predicting that Beaker E would continue to absorb more water indefinitely.
- Saying the cells "burst" (plant cells have cell walls and do not burst in water; animal cells lyse).
Modifying the method to investigate salt concentration
Experimental Design & Variables
✅ Correct Answer
- Mark 1 (Independent Variable): Use different concentrations of salt solution (e.g. 0.2 mol dm⁻³, 0.4 mol dm⁻³, etc.) instead of distilled water.
- Mark 2 (Control Variable): Keep the surface area constant (e.g., do not cut cylinders into different numbers of pieces / use 1 whole cylinder in each beaker).
💡 Experimental Design Rule
When you swap the independent variable to salt concentration, your previous independent variable (surface area) must now become a controlled variable to ensure validity.
❌ Common Errors
- Only stating what to change, forgetting that a valid method must control surface area.
- Writing "use the same shape and size" (too vague; the mark scheme explicitly ignores "same shape/size" and expects mention of controlling surface area or cutting into the same number of pieces).
Topics
Biology · B1: Cell Biology
Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Biology Paper 1 (Higher), June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.