AQA GCSE Combined Science: Trilogy Biology Paper 1 (Higher), June 2025: Question 4

10 marks · Standard Demand difficulty · Short Answer

Explain osmosis in potato tissue, analyze the effect of surface area on percentage mass increase, and describe modifications to investigate salt concentration.

Practise this question

Question

Question 4 presents a method for investigating the effect of surface area on the mass of potato pieces in distilled water. Figure 5 illustrates beakers A to E containing potato cylinders cut into 1, 2, 3, 4, and 5 pieces respectively. Table 1 gives total surface area and percentage increase in mass for each beaker: A (7.4 cm², 4.4%), B (8.1 cm², 4.9%), C (8.9 cm², 5.3%), D (9.7 cm², 5.5%), and E (10.5 cm², 5.6%). Sub-questions 04.1 to 04.5 ask: why calculating percentage increase is more valid, description of the relationship shown in Table 1, explanation of the mass increase, expected results after 24 hours with reasons, and how to adapt the method to test the effect of salt concentration.
Question text

04 A student investigated the effect of surface area on the mass of potato pieces

placed in water.

This is the method used.

1. Cut 5 cylinders from one potato. Cut each cylinder to a length of 3 cm.

2. Cut 4 of the cylinders into different numbers of pieces.

3. Dry each piece of potato on a paper towel.

4. Record the mass of each group of potato pieces.

5. Put each group of potato pieces into different beakers containing distilled water as

shown in Figure 5.

6. After 30 minutes remove and dry each group of potato pieces.

7. Record the mass of each group of potato pieces.

8. Calculate the percentage increase in mass for each group of potato pieces.

Figure 5

Table 1 shows the results.

Table 1

Total surface area of Percentage (%)

Beaker 2

potato pieces in cm increase in mass

A 7.4 4.4

B 8.1 4.9

C 8.9 5.3

D 9.7 5.5

E 10.5 5.6

04.1 Why is it more valid to calculate the percentage increase in mass rather than

using the increase in mass?

[1 mark]

04.2 Describe the relationship between total surface area and percentage increase

in mass.

Use Table 1.

[2 marks]

04.3 Explain why the potato pieces increased in mass.

[2 marks]

04.4 The student repeated the investigation.

The potato pieces were in the beakers of distilled water for 24 hours.

Explain what results would be expected after leaving the investigation set up

for 24 hours.

[3 marks]

04.5 The method used is repeated below.

1. Cut 5 cylinders from one potato. Cut each cylinder to a length of 3 cm.

2. Cut 4 of the cylinders into different numbers of pieces.

3. Dry each piece of potato on a paper towel.

4. Record the mass of each group of potato pieces.

5. Put each group of potato pieces into different beakers containing distilled water as

shown in Figure 5 on page 13.

6. After 30 minutes, remove and dry each group of potato pieces.

7. Record the mass of each group of potato pieces.

*158. Calculate the percentage increase in mass* for each group of potato pieces.

A different student wanted to investigate the effect of salt concentration on

potato tissue.

Describe how the student could change the method to investigate the effect of salt

concentration on potato tissue.

[2 marks]

Mark scheme

Show the mark scheme Mark scheme for Question 4 outlines acceptable answers across five parts: 04.1 allows accounting for different starting masses (1 mark); 04.2 awards marks for identifying that as surface area increases percentage mass increases (1 mark) by a decreasing amount (1 mark); 04.3 requires stating water moves in by osmosis from a dilute solution to a more concentrated solution inside the potato cells (2 marks); 04.4 expects that all groups reach the same percentage change in mass because cell walls become fully stretched/turgid and cannot absorb more water (3 marks); 04.5 requires using different concentrations of salt solution as the independent variable and keeping the surface area or number of pieces constant (2 marks). Total 10 marks.

Question 4

AO /

Question Answers Extra information Mark

Spec. Ref.

04.1 (takes account of) different ignore were not all the same 1 AO2

starting masses size 4.1.3.2

do not accept as a control RPA2

variable

AO /

Spec. Ref.

04.2 as (total) surface area increases allow as one increases, so does 1 AO2

percentage increase in mass the other 4.1.3.2

increases allow there is a positive

correlation

by a decreasing amount allow description of decreasing 1

amount of increase

do not accept they are directly

proportional

AO /

Spec. Ref.

04.3 water moved in by osmosis allow water moved in by 1 AO1

diffusion 4.1.3.2

do not accept (water moves) by RPA2

active transport

(because water moves) allow (because water moves) 1

from a dilute solution to a from a high(er) concentration of

concentrated solution (inside the water to a low(er) concentration

cell / potato) of water (inside the cell / potato)

allow (because water moves)

from a high(er) water potential to

a low(er) water potential (inside

the cell / potato)

allow (because water moves)

from a lower concentration (of

solute) to a higher concentration

(of solute inside the cell / potato)

allow (because water moves)

down its concentration gradient

do not accept water moves

along / across a concentration

gradient

AO / 15

Spec. Ref.

04.4 all the (groups of) potato pieces 1 AO2

had the same percentage

change in mass

(because the) cell walls are allow cells are turgid 1 AO3

completely stretched

(so) the cells cannot absorb any 1 AO3

more water

4.1.3.2

RPA 2

AO /

Spec. Ref.

04.5 (change the independent 1 AO3

variable to) different 4.1.3.2

concentrations of salt solution RPA2

do not cut the potato into pieces allow control the surface area of 1

the potato

allow cut into the same number

of pieces

ignore use the same shape /

size

Total Question 4 10

How to answer it

Potato Osmosis & Surface Area Practical

WHAT THIS QUESTION TESTS

This question assesses core concepts from AQA GCSE Biology / Combined Science Required Practical 2:

  • Understanding why percentage change in mass is used to control for variable starting masses.
  • Describing non-linear relationships and data trends from a practical results table.
  • Explaining the mechanism and direction of water movement via osmosis.
  • Predicting long-term equilibrium when plant cells reach full turgidity.
  • Modifying experimental design when investigating a new independent variable (solute concentration).
QUESTION 04.1 • 1 MARK

Why calculate percentage increase rather than raw increase in mass?

Evaluating Experimental Validity

✅ Correct Answer

To take account of the different starting masses of the potato groups (allows a valid comparison).

❌ Common Errors

  • Vague answers like "to make it a fair test" (scores 0).
  • Writing "they were not all the same size" without explicitly mentioning mass.
  • Claiming mass is a "control variable".
Mark Scheme: 1 mark for stating that it accounts for / allows comparison between different initial (starting) masses.
QUESTION 04.2 • 2 MARKS

Relationship between total surface area and percentage increase in mass

Data Interpretation (Table 1)

✅ Correct Answer

  • Mark 1: As the total surface area increases, the percentage increase in mass increases (positive correlation).
  • Mark 2: It increases by a decreasing amount (the rate of increase slows down / begins to level off).

📐 Data Evidence from Table 1

  • 7.4 to 8.1 cm² → increase of +0.5% (4.4 → 4.9)
  • 8.1 to 8.9 cm² → increase of +0.4% (4.9 → 5.3)
  • 8.9 to 9.7 cm² → increase of +0.2% (5.3 → 5.5)
  • 9.7 to 10.5 cm² → increase of +0.1% (5.5 → 5.6)

🧠 Exam Technique

For 2-mark trend questions, look past the general rule ("as X goes up, Y goes up"). Always look at the differences between values to see if the change is constant, accelerating, or decreasing.

❌ Common Errors

Do not say they are "directly proportional". Directly proportional means doubling surface area exactly doubles the mass increase and the line passes through (0,0), which is not true here.

Mark Scheme: 1 mark for stating as surface area increases, % mass increase increases. 1 mark for describing that it increases by a decreasing amount.
QUESTION 04.3 • 2 MARKS

Explain why the potato pieces increased in mass

Scientific Explanation of Osmosis

✅ Correct Answer

  • Mark 1: Water moved in by osmosis.
  • Mark 2: Water moved from a dilute solution (distilled water outside) to a more concentrated solution (inside the potato cells)
    OR from a higher concentration of water to a lower concentration of water.

💡 Key Knowledge

Osmosis Definition: The net movement of water molecules from a dilute solution (higher water potential) to a more concentrated solution (lower water potential) across a partially permeable membrane.

🧠 Exam Technique

Always state the direction of movement and specify where the dilute and concentrated solutions are located (e.g., "distilled water is dilute, potato cytoplasm is concentrated").

❌ Common Errors

  • Saying water moves by "active transport" (scores 0).
  • Saying water moves "along" or "across" a concentration gradient instead of down its concentration gradient.
  • Confusing solute concentration with water concentration.
Mark Scheme: 1 mark for identifying osmosis / diffusion of water. 1 mark for correct concentration gradient explanation.
QUESTION 04.4 • 3 MARKS

Expected results after leaving set up for 24 hours

Equilibrium & Cell Turgidity

✅ Correct Answer

  • Mark 1: All the potato groups would have the same percentage change in mass.
  • Mark 2: Because the plant cells become fully turgid (cell walls are completely stretched).
  • Mark 3: So the cells cannot absorb any more water.

💡 Key Knowledge

Surface area alters the rate of osmosis, not the final equilibrium position. Over 30 minutes, higher surface area means faster uptake. Over 24 hours, all pieces have reached their absolute capacity and become fully turgid.

🧠 Exam Technique: Rate vs. Final Endpoint

When an experiment runs for a very long time (like 24 hours), think about the biological limit: the rigid cellulose cell wall prevents plant cells from taking in more water once maximum turgor pressure is reached.

❌ Common Errors

  • Predicting that Beaker E would continue to absorb more water indefinitely.
  • Saying the cells "burst" (plant cells have cell walls and do not burst in water; animal cells lyse).
Mark Scheme: 1 mark for same percentage increase across all beakers. 1 mark for stating cells are turgid / walls fully stretched. 1 mark for cells cannot absorb any more water.
QUESTION 04.5 • 2 MARKS

Modifying the method to investigate salt concentration

Experimental Design & Variables

✅ Correct Answer

  • Mark 1 (Independent Variable): Use different concentrations of salt solution (e.g. 0.2 mol dm⁻³, 0.4 mol dm⁻³, etc.) instead of distilled water.
  • Mark 2 (Control Variable): Keep the surface area constant (e.g., do not cut cylinders into different numbers of pieces / use 1 whole cylinder in each beaker).

💡 Experimental Design Rule

When you swap the independent variable to salt concentration, your previous independent variable (surface area) must now become a controlled variable to ensure validity.

❌ Common Errors

  • Only stating what to change, forgetting that a valid method must control surface area.
  • Writing "use the same shape and size" (too vague; the mark scheme explicitly ignores "same shape/size" and expects mention of controlling surface area or cutting into the same number of pieces).
Mark Scheme: 1 mark for changing independent variable to different salt concentrations. 1 mark for controlling surface area / cutting into the same number of pieces.

Topics

Biology · B1: Cell Biology

Question and mark scheme from the AQA GCSE Combined Science: Trilogy examination, Biology Paper 1 (Higher), June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.