OCR A-Level Chemistry AS Breadth in chemistry (01), June 2018: Question 17

1 mark · Easy difficulty · Multiple Choice

Determine the molecular formula of naphthalene from its skeletal structure.

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Question

Multiple choice question 17 showing the skeletal structure of naphthalene, which consists of two fused benzene rings. Below the structure, the question asks for the molecular formula of naphthalene, with four options provided: A, C10H8; B, C10H10; C, C12H10; and D, C12H12, followed by an answer box.
Question text

17 The structure of naphthalene is shown below.

What is the molecular formula of naphthalene?

A C10H8

B C10H10

C C12H10

D C12H12

Your answer [1]

Mark scheme

Show the mark scheme Mark scheme for question 17 showing the correct answer is A, worth 1 mark.

17 A 1

How to answer it

Determining the Molecular Formula of Naphthalene

OCR AS Level Chemistry • Multiple Choice Question

What this question tests

This question assesses your ability to interpret skeletal and aromatic ring structures, apply chemical bonding rules (tetravalency of carbon), and deduce the molecular formula of polycyclic aromatic hydrocarbons by counting carbon and hydrogen atoms correctly.

Question 17 Analysis

Part (a) — Finding the Molecular Formula

✅ Correct Answer: A ( C₁₀H₈ )

Naphthalene consists of two fused benzene rings. Counting the carbon vertices and accounting for the shared central carbons yields 10 carbons and 8 hydrogens.

💡 Key Knowledge

  • Skeletal Formula Rules: Each vertex represents a carbon atom.
  • Fused Rings: Two carbons are shared at the bridgehead position between the rings and do not bond to hydrogen atoms.
  • Valency: Carbon must form 4 covalent bonds. Unoccupied bonds at each vertex correspond to hydrogen atoms attached to carbons.

🧠 Exam Technique

Don't guess based on standard benzene derivatives. Systematically count:

  1. Count total outer and inner ring vertices to find carbons ( 10 ).
  2. Identify that the 2 bridgehead carbons have 0 hydrogens attached (all 4 bonds are already used within the ring framework).
  3. Count peripheral carbons with available bonding space ( 8 carbons each bonded to 1 hydrogen).

❌ Common Errors

  • Option B ( C₁₀H₁₀ ): Assuming every carbon atom around the perimeter holds a hydrogen atom, forgetting that fused rings share carbons.
  • Counting loops instead of atoms: Misinterpreting aromatic rings as simple saturated alkane ring systems.
Mark Scheme Allocation: 1 mark awarded for selecting A.

Topics

Module 6: Organic chemistry and analysis · 6.1 Aromatic compounds, carbonyls and acids

Question and mark scheme from the OCR A-Level Chemistry examination, AS Breadth in chemistry (01), June 2018. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.