OCR A-Level Chemistry AS Breadth in chemistry (01), June 2018: Question 18
1 mark · Easy difficulty · Multiple Choice
Identify the product formed from the reaction of pent-2-ene with bromine
Practise this questionQuestion
Question text
18 A student reacts pent-2-ene with bromine in the laboratory.
Which compound is formed?
A 1,1-dibromopentane
B 1,2-dibromopentane
C 2,2-dibromopentane
D 2,3-dibromopentane
Your answer [1]
Mark scheme
Show the mark scheme
18 D 1
How to answer it
Reaction of Pent-2-ene with Bromine
What this question tests
This question assesses your knowledge of the chemical reactions of alkenes, specifically electrophilic addition of halogens across the carbon-carbon double bond, along with IUPAC organic nomenclature and numbering rules.
Halogenation of Alkenes and IUPAC Nomenclature
✅ Correct Answer: D
2,3-dibromopentane
When bromine reacts with pent-2-ene, the C=C double bond is located between carbon-2 and carbon-3. The bromine atoms add across this double bond, attaching specifically to carbons 2 and 3.
💡 Key Knowledge
- Pent-2-ene structure: CH₃-CH=CH-CH₂-CH₃
- Reaction type: Electrophilic addition
- Reagent/Observation: Bromine (Br₂) liquid or water decolourises from orange/brown to colourless.
🧠 Exam Technique
Draw out the skeletal or displayed formula of the organic reactant before choosing your answer. Number the longest carbon chain from the end that gives the lowest locant numbers to functional groups or substituents.
❌ Common Errors
- Choosing 1,2-dibromopentane (B) by assuming the double bond is always at the end of the chain (confusing pent-2-ene with pent-1-ene).
- Failing to number the carbon chain correctly, leading to incorrect locant numbers like 2,2-dibromopentane.
Topics
Module 4: Core organic chemistry · 4.1 Basic concepts and hydrocarbons
Question and mark scheme from the OCR A-Level Chemistry examination, AS Breadth in chemistry (01), June 2018. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.